JAMB UTME - Mathematics - 1999
Ibeere 1 Ìròyìn
What is the answer when 24346 is divided by 426?
Awọn alaye Idahun
Hint: Two methods can be used;
1. Direct division (if you know division in number bases)
2. Convert both sides to base 10, divide and convert your answer back to base 6. Your answer should be 356
Ibeere 3 Ìròyìn
Evaluate: \( \int_{0}^{z}(\sin x-\cos x)\,dx \)
Where \( z=\frac{\pi}{4}.(\pi=pi) \)
Awọn alaye Idahun
To solve the definite integral ∫z0(sinx−cosx)dx, we need to find the antiderivative of the given expression first, and then evaluate it from 0 to z. The antiderivative of sin(x) is -cos(x), and the antiderivative of cos(x) is sin(x). Therefore, the antiderivative of (sin(x) - cos(x)) is (-cos(x) - sin(x)). Thus, ∫z0(sinx−cosx)dx = [-cos(x) - sin(x)] evaluated from 0 to z. Plugging in the values of z and 0, we get: [-cos(z) - sin(z)] - [-cos(0) - sin(0)] = [-cos(π/4) - sin(π/4)] - [-cos(0) - sin(0)] = [-(1/√2) - (1/√2)] - [-1 - 0] = -√2 + 1 Therefore, the value of the definite integral is -√2 + 1. Hence, the option that represents this result is √2-1.
Ibeere 4 Ìròyìn
Find the equation of the locus of a point P(x,y) such that PV = PW, where V = (1,1) and W = (3,5)
Awọn alaye Idahun
To find the locus of point P(x,y) such that PV = PW, we need to find the set of all points that are equidistant from V(1,1) and W(3,5). First, we can find the distance between V and W using the distance formula: d = sqrt((3-1)^2 + (5-1)^2) = sqrt(20) The midpoint M of line segment VW is: M = ((1+3)/2, (1+5)/2) = (2,3) Using the midpoint formula, we can find the equation of the perpendicular bisector of VW, which is the locus of points equidistant from V and W: (y - 3) = -(1/2)(x - 2) 2y - 6 = -x + 2 x + 2y = 8 Therefore, the correct option is (D) x + 2y = 8.
Ibeere 6 Ìròyìn
Simplify \( \sqrt{\frac{(0.0023 \ast 750)}{(0.00345 \ast 1.25)}} \)
Awọn alaye Idahun
To simplify the given expression: $$\sqrt{\frac{(0.0023\cdot750)}{(0.00345\cdot1.25)}}$$ We can first simplify the expression inside the square root by multiplying the numerators and denominators: $$\sqrt{\frac{0.0023\cdot750}{0.00345\cdot1.25}} = \sqrt{\frac{1.725}{0.0043125}}$$ Then we can divide the numerator and denominator by 0.0043125 to get: $$\sqrt{\frac{1.725}{0.0043125}} = \sqrt{400} = 20$$ Therefore, the simplified expression is 20.
Ibeere 7 Ìròyìn
If the maximum value of \(y = 1 + hx - 3x^2\) is \(13\), find \(h\).
Awọn alaye Idahun
Ibeere 8 Ìròyìn
If log 10 to base 8 = X, evaluate log 5 to base 8 in terms of X.
Awọn alaye Idahun
We can use the change of base formula to evaluate log 5 to base 8 in terms of X: log 5 to base 8 = log 5 / log 8 We know that log 10 to base 8 = X, which means: 8^X = 10 We can rewrite this as: 2^3X = 10 Taking the logarithm of both sides of the equation with base 2, we get: log 2 (2^3X) = log 2 10 3X = log 2 10 X = (1/3) log 2 10 Substituting this value of X into the expression for log 5 to base 8, we get: log 5 to base 8 = log 5 / log 8 = (log 5 / log 2) / (log 8 / log 2) = log 2 5 / log 2 8 = log 2 5 / (3 log 2 2) = (1/3) log 2 5 Therefore, log 5 to base 8 in terms of X is: X - (1/3) log 2 5.
Ibeere 9 Ìròyìn
In the diagram above, EFGH is a cyclic quadrilateral in which EH//FG, EG and FH are chords. If \( \angle FHG = 42^\circ \) and \( \angle EFH = 34^\circ \), calculate \( \angle HEG \)
Awọn alaye Idahun
∠EFH = ∠EGH(∠s in same segment)
= 34∘
∠HEG = ∠HFG(∠s in same segment)
= X
also ∠HFG = ∠EHF (alternate ∠s)
But ∠EHG + ∠EFG =180(opp sof a cyclic quad)
42 + x + 34 + x = 180
2x + 76 = 180
2x = 180 - 76
2x = 104
x = 52∘
Ibeere 10 Ìròyìn
The diagram above is the graph of y = x2, the shaded area is
Awọn alaye Idahun
The shaded area is a quarter of a circle with radius 8 units. To find the area of the shaded region, we need to find the area of the quarter circle. The area of a circle with radius r is given by the formula A = πr², and the area of a quarter of a circle is one-fourth of the area of the full circle. Therefore, the area of the shaded region is: A = (1/4)π(8²) = 16π square units Using the approximation π ≈ 3.14, we get: A ≈ 50.24 square units Therefore, the answer is approximately 50.24 square units. is the closest approximation to this value, which is 64/3 square units.
Ibeere 12 Ìròyìn
Find the area bounded by the curve y = x(2-x). The x-axis, x = 0 and x = 2.
Awọn alaye Idahun
To find the area bounded by the curve y = x(2-x), the x-axis, x = 0 and x = 2, we need to integrate the function with respect to x from 0 to 2. The function y = x(2-x) is a quadratic equation, which opens downwards and has its vertex at (1, 1). It intersects the x-axis at x = 0 and x = 2, forming a trapezium. To integrate the function, we need to first expand it: y = x(2-x) = 2x - x^2 Then, we integrate it with respect to x from 0 to 2: ∫(2x - x^2)dx, limits 0 to 2 = [x^2 - (x^3)/3] from 0 to 2 = [(2^2) - (2^3)/3] - [(0^2) - (0^3)/3] = [4 - (8/3)] - [0 - 0] = (4/3) sq units Therefore, the area bounded by the curve y = x(2-x), the x-axis, x = 0 and x = 2 is (4/3) sq units.
Ibeere 14 Ìròyìn
Find a positive value of ã if the coordinate of the centre of a circle X2+y2-2ãx+4y-ã = 0 is (ã,-2) and the radius is 4 units.
Awọn alaye Idahun
Ibeere 15 Ìròyìn
Find the length XZ in the triangle
Awọn alaye Idahun
xz2 = xy2 + yx2 - 2(xy) (yz) cos 120∘
= 22 + 12 - 2(2) (1) cos 1202
= 4 + 1 - 4x - cos 60 = 5 - 4x - 12
5 + 2 = 7
xz = √7 m
Ibeere 16 Ìròyìn
Find the value of l in the frustrum above
Awọn alaye Idahun
ΔABE and ΔACD are similar
| ∴ | x |
|
|||
| x+4 |
6x = 3(x+4)
6x = 3x + 12
3x = 12
x = 4
In ΔACD; L2 = (4+4)2 + 62
= 82 + 62
= 64 + 36
= 100
L =
√ 100
= 10cm
In ABE, AE2 = 42 + 32
= 16 + 9
= 25
AE = 5cm
∴L = 10 - 5
= 5cm
Ibeere 17 Ìròyìn
The first term of a geometric progression is twice its common ratio. Find the sum of the first two terms of the G.P if its sum to infinity is 8.
Awọn alaye Idahun
Le the common ratio be r so that the first term is 2r.
Sum, s = a/(1-r)
ie. 8 = 2r/(1-r)
8(1-r) = 2r, r = 8/5.
Sn = a(1-rn)/(1-r)
Solve further to get 72/25
Ibeere 18 Ìròyìn
Three consecutive positive integers k, l and m are such that l2 = 3(k+m). Find the value of m
Awọn alaye Idahun
Let's start by translating the given problem into equations. First, we know that the three integers are consecutive, so we can express them as k, k+1, and k+2. Second, we know that l^2 = 3(k+m). We can substitute k+1 for l to get (k+1)^2 = 3(k+m). Expanding (k+1)^2, we get k^2 + 2k + 1 = 3(k+m). Simplifying, we get k^2 - k(6-3m) + 3m - 1 = 0. We can use the quadratic formula to solve for k: k = [(6-3m) ± sqrt((6-3m)^2 - 4(3m-1))]/2. Simplifying under the square root, we get sqrt(9m^2 - 36m + 37). Since k is a positive integer, the expression under the square root must be a perfect square. We can check the perfect squares between 1 and 37 and find that only 4, 16, and 25 are possibilities. Solving for m in each case gives us three potential solutions: 4, 5, and 7. However, only one of these solutions satisfies the original equation l^2 = 3(k+m), and that is m=4. Therefore, the answer to the problem is m=4.
Ibeere 19 Ìròyìn
What is the derivative of t2 sin (3t - 5) with respect to t?
Awọn alaye Idahun
To find the derivative of the function t^2 sin(3t-5), we will use the product rule of differentiation. The product rule states that the derivative of the product of two functions is equal to the first function times the derivative of the second function plus the second function times the derivative of the first function. So, applying the product rule to the given function, we get: d/dt [t^2 sin(3t-5)] = t^2 d/dt[sin(3t-5)] + sin(3t-5) d/dt[t^2] Now, we need to find the derivatives of sin(3t-5) and t^2. The derivative of sin(3t-5) is cos(3t-5) times the derivative of the inside function (3t-5), which is simply 3. So, d/dt[sin(3t-5)] = 3cos(3t-5). The derivative of t^2 is 2t. So, d/dt[t^2] = 2t. Now, we can substitute these values back into the original equation: d/dt [t^2 sin(3t-5)] = t^2 * 3cos(3t-5) + sin(3t-5) * 2t Simplifying this expression, we get: d/dt [t^2 sin(3t-5)] = 3t^2 cos(3t-5) + 2t sin(3t-5) Therefore, the correct option is: 2t sin (3t - 5) + 3t^2 cos (3t - 5).
Ibeere 20 Ìròyìn
Find the value of X if \( \frac{\sqrt{2}}{x+\sqrt{2}}=\frac{1}{x-\sqrt{2}} \)
Awọn alaye Idahun
Start your solution by cross-multiplying, then collect like terms and factorize accordingly to get the unknown.
Ibeere 21 Ìròyìn
From a point P, the bearings of two points Q and R are N670W and N230E respectively. If the bearing of R from Q is N680E and PQ = 150m, calculate PR
Awọn alaye Idahun
Ibeere 23 Ìròyìn
The grades of 36 students in a test are shown in the pie chart above. How many students had excellent?
Awọn alaye Idahun
Angle of Excellent
= 360 - (120+80+90)
= 360 - 290
= 70∘
If 360∘
represents 36 students
1∘
will represent 36/360
50∘
will represent 36/360 * 70/1
= 7
Ibeere 24 Ìròyìn
The sum of two numbers is twice their difference. If the difference of the numbers is P, find the larger of the two numbers
Awọn alaye Idahun
Let's call the two numbers x and y. From the problem, we can write two equations: x + y = 2(x - y) (the sum of the two numbers is twice their difference) x - y = P (the difference of the numbers is P) To solve for x and y, we can use the first equation to eliminate one of the variables. x + y = 2(x - y) x + y = 2x - 2y 3y = x Now we can substitute 3y for x in the second equation: 3y - y = P 2y = P y = P/2 Since x = 3y, we have: x = 3(P/2) = 3P/2 Therefore, the larger of the two numbers is 3P/2. So, the answer is: 3P/2.
Ibeere 25 Ìròyìn
A binary operation * is defined by a*b = ab+a+b for any real number a and b. if the identity element is zero, find the inverse of 2 under this operation.
Awọn alaye Idahun
a*a-1 = aa-1 + a + a-1 = e
if e = 0
2.2-1 + 2 + 2-1 = 0
3.2-1 + 2 = 0
= 2-1 = -23
Ibeere 26 Ìròyìn
In the diagram, EFGH is a cyclic quadrilateral in which EH || FG, EG and FH are chords. If < FHG = \(424^{\circ}\) and < EFH = \(34^{\circ}\)
Awọn alaye Idahun
< EFH = < EGH = 34∘ (angles n the same segment)
< GHF = < GEF = 42∘ (angles in the same segment)
< FOG = 42 + 34 = 76(exterior angle)
< FOG = < EOH = 76(vertically opposite angle)
< EDO = 90∘ , < DOE = 762 = 38∘
< HEG = 90∘ - 38∘ = 52∘
Ibeere 27 Ìròyìn
If \(m \ast n = \left(\frac{m}{n} - \frac{n}{m}\right)\) for m, n belong to R, evaluate -3*4
Awọn alaye Idahun
Using the formula given, we have: -3 * 4 = (3*4 - 4*3) / (3 + 4) = 0 / 7 = 0 Therefore, the answer is 0. is the closest approximation to this value, which is 7/12.
Ibeere 28 Ìròyìn
If {(a2b-3c)3/4/a-1b4c5} = apbqcr; what is the value of p+2q?
Awọn alaye Idahun
Hint: Use BODMAS and algebra to arrive at the values of P = 5/2, q = -25/4 and r = -9/2.
Then substitute the values of p and q into p+2q to get -10.
Ibeere 29 Ìròyìn
A group of market women sell at least one of yam, plantain and maize. 12 of them sell maize, 10 sell yam and 14 sell plantain. 5 sell plantain and maize, 4 sell yam and maize, 2 sell yam and plantain only while 3 sell all the three items. How many women are in the group?
Awọn alaye Idahun
Let the three items be M, Y and P.
n{M ∩ Y} only = 4-3 = 1
n{M ∩ P) only = 5-3 = 2
n{ Y ∩ P} only = 2
n{M} only = 12-(1+3+2) = 6
n{Y} only = 10-(1+2+3) = 4
n{P} only = 14-(2+3+2) = 7
Number of women in the group = 6+4+7+(1+2+2+3) as above =25 women.
Ibeere 30 Ìròyìn
If \( \frac{(a^2b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^4c^5}=a^pb^qc^r \) What is the value of p+2q?
Awọn alaye Idahun
Hint: apply basic mathematics rules beginning from BODMAS to algebra, and follow solution carefully to arrive at p =(5/2), q = -(25/4) and r = -(9/2).
Then p+2q will give you 52+2(−254)=−10
Ibeere 31 Ìròyìn
A man 1.7m tall observes a bird on top of a tree at an angle of 300. if the distance between the man's head and the bird is 25m, what is the height of the tree?
Awọn alaye Idahun
Hint: Make a sketch forming a right angled triangle. Let X = height required. Such that x/25 = tan 30.
Ibeere 32 Ìròyìn
In the figure above, TZ is tangent to the circle QPZ. Find x if TZ = 6 units and PQ = 9 units
Ibeere 33 Ìròyìn
The table above shows the frequency distribution of the ages (in years) of pupils in a certain secondary school. What percentage of the total number of pupils is over 15 years but less than 21 years?
Awọn alaye Idahun
% of those above 15 but less than 21 years
age = 25/50 x 100/1
= 50%
Ibeere 34 Ìròyìn
In ∆MNO, MN = 6 units, MO = 4 units and NO = 12 units. If the bisector of and M meets NO at P, calculate NP.
Awọn alaye Idahun
Hint: start with making a sketch of the figure described.
Ibeere 35 Ìròyìn
In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.
Awọn alaye Idahun
PQRS is a cyclic quad
^P = 180 - 110 (opp ∠s of a cyclic quad)
^P = 70
In ΔPTS, ^S = ^T (base ∠s of Isc Δ)
∴^T = (180-70) / 2
= 110/2
= 55∘
But ^T x(corr ∠)
∴x =55
Ibeere 37 Ìròyìn
Find the tangent to the acute angle between the lines 2x+y = 3 and 3x-2y = 5.
Awọn alaye Idahun
Ibeere 38 Ìròyìn
The shaded portion in the graph above is represented by
Awọn alaye Idahun
y + x - x2 ≥ 0
y = x3 - x
on x axis, y = 0
∴x2 - x = 0
x(x2 - 1) = 0
x = 0 or x2 - 1 = 0
x2 = 1
x = +/-1
∴ x = -1, 0 and 1 which are the roots of the equation y + x - x2 ≥ 0
Also y - x ≤ 0
=> y ≤ 0 + x
∴ the region where y ≤ 0
Ibeere 39 Ìròyìn
Divide 4x3-3x+1 by 2x-1
Awọn alaye Idahun
To divide 4x³-3x+1 by 2x-1, we can use polynomial long division.
First, we set up the division like this:
2x² + x - 1
-----------------
2x - 1 | 4x³ + 0x² - 3x + 1
Next, we look at the leading term of the dividend (4x³) and the leading term of the divisor (2x) and ask: "How many times does 2x go into 4x³?" The answer is 2x², so we write that above the division line and multiply by the divisor:
2x² + x - 1
-----------------
2x - 1 | 4x³ + 0x² - 3x + 1
- 4x³ + 2x²
-------------
2x² - 3x
We then subtract the result from the dividend and bring down the next term (1x):
2x² + x - 1
-----------------
2x - 1 | 4x³ + 0x² - 3x + 1
- 4x³ + 2x²
-------------
2x² - 3x
- 2x² + x
----------
-2x + 1
We repeat the process with the new polynomial (-2x+1) and the divisor (2x-1):
2x² + x - 1
-----------------
2x - 1 | 4x³ + 0x² - 3x + 1
- 4x³ + 2x²
-------------
2x² - 3x
- 2x² + x
----------
-2x + 1
-2x + 1
------
0
We end up with a remainder of 0, which means that the division is exact. Therefore, the quotient is:
2x² + x - 1
So the answer is (B) 2x²-x-1.
Ibeere 40 Ìròyìn
In the figure, PQRS is a circle with ST||RQ. Find the value of x if PT = PS
Awọn alaye Idahun
< PST = < RQT = x(corresponding angle)
< PST = < PTS = < PTS x (PS = PT0
< SRQ = < SPT = 180∘ (sum of < on straight line)
< SPT = 180∘ - 110∘ = 70∘
in < SPT, < PST = PTS = < PSt = 180∘
2x + 70 = 180∘
2x = 180∘ - 70∘ = 110∘
x = 110o2 = 55∘
Ibeere 41 Ìròyìn
Find the value of x for which the function y = x3 - x has a minimum value.
Awọn alaye Idahun
Ibeere 42 Ìròyìn
Find the volume of solid generated when the area enclosed by y = 0, y = 2x, and x = 3 is rotated about the x-axis.
Awọn alaye Idahun
To find the volume of the solid generated when the area enclosed by y = 0, y = 2x, and x = 3 is rotated about the x-axis, we need to use the formula for the volume of a solid of revolution: V = π∫[a,b]f(x)^2dx where f(x) is the function defining the curve being rotated, and a and b are the limits of integration. In this case, the limits of integration are 0 and 3, and the function defining the curve is f(x) = 2x. Substituting into the formula, we get: V = π∫[0,3](2x)^2dx = π∫[0,3]4x^2dx = π[4x^3/3] from 0 to 3 = π[(4(3)^3/3) - (4(0)^3/3)] = π[36] = 36π Therefore, the volume of the solid generated when the area enclosed by y = 0, y = 2x, and x = 3 is rotated about the x-axis is 36π cubic units. The correct option is 36 π cubic units.
Ibeere 43 Ìròyìn
A trader bought 100 oranges at 5 for N1.20, 20 oranges got spoilt and the remaining were sold at 4 for N1.50. Find the percentage gain or loss
Awọn alaye Idahun
First, let's calculate how much the trader spent on the oranges. The trader bought 100 oranges at 5 for N1.20, which means that the cost of each orange was (N1.20 ÷ 5) = N0.24. Therefore, the total cost of 100 oranges was N0.24 × 100 = N24. Now, 20 of the oranges got spoilt and were not sold. So the trader had 80 oranges left to sell. The remaining 80 oranges were sold at 4 for N1.50, which means that the selling price of each orange was (N1.50 ÷ 4) = N0.375. Therefore, the total revenue from selling 80 oranges was N0.375 × 80 = N30. To calculate the profit or loss, we need to compare the cost and revenue. The cost of buying 100 oranges was N24, but the trader only earned N30 from selling the remaining 80 oranges. So, the trader earned a profit of N30 - N24 = N6. To calculate the percentage gain or loss, we need to use the formula: Percentage gain or loss = (Profit or loss / Cost price) × 100% In this case, the profit was N6, and the cost was N24. Percentage gain or loss = (6/24) × 100% = 25% Therefore, the answer is "25% gain."
