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Ibeere 1 Ìròyìn
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Ibeere 4 Ìròyìn
Ibeere 5 Ìròyìn
Ibeere 7 Ìròyìn
Simplify \( \frac{1}{x-2} + \frac{1}{x+2} + \frac{2x}{x^2-4} \)
Ibeere 8 Ìròyìn
Ibeere 9 Ìròyìn
Ibeere 10 Ìròyìn
Simplify and express in standard form \( \frac{0.00275 \times 0.0064}{0.025 \times 0.08} \)
Ibeere 11 Ìròyìn
In triangles XYZ and XQP, XP = 4cm, XQ = 5cm and PQ = QY = 3cm. Find ZY
Awọn alaye Idahun
Ibeere 12 Ìròyìn
Below are the scores of a group of students in a test:
| Scores | 1 | 2 | 3 | 4 | 5 | 6 |
| No. of students | 1 | 4 | 5 | 6 | \(x\) | 2 |
If the average scores is 3.5, find the value of x.
Ibeere 14 Ìròyìn
Awọn alaye Idahun
Ibeere 15 Ìròyìn
If the heights of two circular cylinder are in the ratio 2 : 3 and their volumes?
h1h2
= 23
h2 = 2h13
r1r2
= 98
r2 = 9r18
v1 = π
(9r18
)2(2h13
)
= π
r1 2h1 x 2732
v = πr12h1×2732πr12h1
= 2732
v2 : v1 = 27 : 32
Ibeere 16 Ìròyìn
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Ibeere 19 Ìròyìn
In the figure, YXZ = \(30^\circ\), XYZ = \(105^\circ\) and XY = 8cm. Calculate YZ
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Ibeere 22 Ìròyìn
Simplify \(4\frac{3}{4} - 6\frac{1}{4}\)
Ibeere 23 Ìròyìn
Simplify \( \sqrt{160r^2} + \sqrt{71r^4} + \sqrt{100r^2} \)
Ibeere 24 Ìròyìn
Three children shared a basket of mangoes in such a way that the first child took \( \frac{1}{4} \) of the mangoes and the second \( \frac{3}{4} \) of the remainder. What fraction of the mangoes did the third child take?
Ibeere 25 Ìròyìn
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Ibeere 30 Ìròyìn
Simplify \( \left(\frac{1}{x^{-1}} + \frac{1}{y^{-1}}\right)^{-1} \)
Ibeere 31 Ìròyìn
In the figure, PQR is a semicircle. Calculate the area of the shaded region.
Awọn alaye Idahun
Ibeere 32 Ìròyìn
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Ibeere 35 Ìròyìn
Awọn alaye Idahun
Ibeere 36 Ìròyìn
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Ibeere 38 Ìròyìn
If \(x + \frac{1}{x} = 4\), find \(x^2 + \frac{1}{x^2}\)
Ibeere 39 Ìròyìn
Ibeere 40 Ìròyìn
Given that \(x^2 + y^2 + z^2 = 194\), calculate z if \(x = 7\) and \(\sqrt{y} = 3\)
Given that x2 + y2 + z2 = 194, calculate z if x = 7 and √y
= 3
x = 7
∴ x2 = 49
√y
= 3
∴ y2 = 81 = x2 + y2 + z2 = 194
49 + 81 + z2 = 194
130 + z2 = 194
z2 = 194 - 130
= 64
z = √64
= 8
Ibeere 41 Ìròyìn
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Ibeere 43 Ìròyìn
What is the equation of the quadratic function represented by the graph?
i.e. B where the graph touches the graph touches the x-axis y = 0
x2 - x - 2 = 0 = (x + 1)(x - 2) = 0
Hence roots of the equation are -1 and 2 as shown in the graph
Ibeere 44 Ìròyìn
Ibeere 45 Ìròyìn
Find the solution of the equation \(x - 8\sqrt{x} + 15 = 0\)
Ibeere 46 Ìròyìn
Find the curved surface area of the frustrum in the figure.
6x = 4(6 + x) = 24 + 4x
x = 12 = c = πRL−πL
= π(6)√182+62−π×4×√122+42
= 6π√360−4π√160
= 36π√10−16π√10
= 20π√10 cm2
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