Linear Law (straight-line Form)
Muhtasari
Experimental data rarely falls on a straight line, but a clever change of variables can often make it do so. By taking logarithms, a power law or an exponential law can be straightened into the form \(Y=mX+c\). Then the gradient and intercept of the straight-line graph hand you the unknown constants.
In this lesson you will convert relationships such as \(y=Ax^n\) and \(y=Ab^x\) into straight-line form by taking logarithms, identify what to plot, and read off the constants from the gradient and intercept. This is the bridge between curved real-world data and the simple line you know how to analyse.
Malengo
- Transform given relationships, such as y = Ax to the power n and y = Ab to the power x, to and from straight-line form.
- Determine unknown constants by calculating the gradient or intercept of the transformed straight-line graph.
Maelezo ya Somo
Inapatikana kwenye programu ya Green Bridge
Pakua programu ya Green Bridge CBT kwenye simu yako au kompyuta yako ili kupata maelezo kamili ya masomo, maswali ya mazoezi, na mengi zaidi.
Tathmini ya Somo
Hongera kwa kukamilisha somo la Linear Law (straight-line Form). Sasa kwa kuwa umechunguza dhana na mawazo muhimu, ni wakati wa kuweka ujuzi wako kwa mtihani. Sehemu hii inatoa mazoezi mbalimbali maswali yaliyoundwa ili kuimarisha uelewaji wako na kukusaidia kupima ufahamu wako wa nyenzo.
Utakutana na mchanganyiko wa aina mbalimbali za maswali, ikiwemo maswali ya kuchagua jibu sahihi, maswali ya majibu mafupi, na maswali ya insha. Kila swali limebuniwa kwa umakini ili kupima vipengele tofauti vya maarifa yako na ujuzi wa kufikiri kwa makini.
Tumia sehemu hii ya tathmini kama fursa ya kuimarisha uelewa wako wa mada na kubaini maeneo yoyote ambapo unaweza kuhitaji kusoma zaidi. Usikatishwe tamaa na changamoto zozote utakazokutana nazo; badala yake, zitazame kama fursa za kukua na kuboresha.
- To straighten y = Ax^n, you plot: A. y against x B. lg y against lg x C. lg y against x D. y against lg x Answer: B
- To straighten y = Ab^x, you plot: A. lg y against lg x B. lg y against x C. y against x D. y against lg x Answer: B
- Taking logs of y = Ax^n gives: A. lg y = n lg x + lg A B. lg y = A lg x + n C. lg y = lg x + n lg A D. y = n lg x + A Answer: A
- If lg y against lg x has gradient 3 and intercept 0.7 for y = Ax^n, then n is: A. 0.7 B. 3 C. 10^0.7 D. 0.3 Answer: B
- If the intercept of the straight-line graph is lg A = 1, then A equals: A. 1 B. 10 C. 0.1 D. 100 Answer: B
Inapatikana kwenye programu ya Green Bridge
Pakua programu ya Green Bridge CBT kwenye simu yako au kompyuta yako ili kupata maelezo kamili ya masomo, maswali ya mazoezi, na mengi zaidi.
Inapatikana kwenye programu ya Green Bridge
Pakua programu ya Green Bridge CBT kwenye simu yako au kompyuta yako ili kupata maelezo kamili ya masomo, maswali ya mazoezi, na mengi zaidi.
Vitabu Vinavyopendekezwa
Fanya Mazoezi ya Maswali ya Majaribio
Ungependa kufanya mazoezi ya maswali ya majaribio kuhusu Linear Law (straight-line Form)? Pakua programu ya Green Bridge CBT ili kupata maswali ya majaribio na tathmini kamili za mazoezi kuhusu mada hii.
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