WAEC SSCE - Physics - 2004 (Objective)

Swali 1 Ripoti

The diagram above represent displacement D, versus time, t graph of a progressive wave. Deduce the frequency of the wave

20 Hz

10 Hz

5 Hz

4 Hz

Fluid At Rest

Tazama Jibu

Swali 2 Ripoti

Calculate the change in volume when 90g of ice is completely melted. [density of water = 1g cm^-3, density of ice = 0.9cm^-3]

0.00cm³

9.00cm³

10.00cm³

90.00cm³

Temperature And Its Measurement

Tazama Jibu

Swali 3 Ripoti

When compared with water, mercury is preferred as a thermometric liquid because

has a higher density

has lower specific heat capacity

exhibits anomalous thermal expansion

contains molecules which have very strong adhesive forces

Maelezo ya Majibu

Mercury is preferred as a thermometric liquid over water because it has a much lower specific heat capacity. This means that it requires less heat energy to change its temperature than water. This makes it easier to measure small temperature changes accurately. Additionally, mercury has a much higher density than water, which allows it to rise and fall more easily in narrow capillary tubes used in thermometers. The other options are not correct - mercury does not exhibit anomalous thermal expansion and does not have molecules with very strong adhesive forces.

Soma maelezo ya somo kwenye Temperature And Its Measurement (JAMB)

Temperature And Its Measurement

Tazama Jibu

Swali 4 Ripoti

Which of the following statements is not correct?

a magnetic field is a region in which a magnetic force will be detected

a magnetic line of force is a path along which a magnetic fields are scalar quantities it were free

magnetic fields are scalar quantities

neutral point are obtained where the earth's magnetic force is exactly equal and opposite to that due to a magnet

Maelezo ya Majibu

The statement that is not correct is: "magnetic fields are scalar quantities." This statement is incorrect because magnetic fields are vector quantities, meaning they have both magnitude and direction. The direction of a magnetic field is given by the direction of the force that would be exerted on a moving charged particle in that field. Magnetic fields can also be visualized using magnetic field lines, which show the direction and strength of the field at different points in space.

Soma maelezo ya somo kwenye Electric Field (WAEC)

Electric Field

Tazama Jibu

Swali 5 Ripoti

A body of mass 8kg moving with a speed of 30ms^-1 is brought to rest in 2.5s by a constant retarding force. Calculate the magnitude of the force

240N

96N

20N

9N

Maelezo ya Majibu

The formula for force is F = ma, where F is force, m is mass and a is acceleration. The body is initially moving with a speed of 30ms^-1 and is brought to rest, which means the final velocity is 0ms^-1. The acceleration, a, can be calculated using the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken. Rearranging the formula to make a the subject gives a = (v - u)/t. Substituting the values gives a = (0 - 30)/2.5 = -12ms^-2. The negative sign indicates that the acceleration is in the opposite direction to the initial velocity. Substituting the mass and acceleration into the formula F = ma gives F = 8 x (-12) = -96N. The negative sign indicates that the force is in the opposite direction to the initial velocity. Taking the magnitude of the force gives 96N. Therefore, the magnitude of the force is 96N. Note that the negative sign indicates the direction of the force, and is not part of the magnitude of the force.

Soma maelezo ya somo kwenye Gravitational Field (JAMB)

Gravitational Field

Tazama Jibu

Swali 6 Ripoti

A faulty barometer reads 72.6cm Hg when the atmospheric pressure is 75.0cm Hg. Calculate the atmospheric pressure when the barometer reads 72.0cn Hg

79.4cm Hg

74.38cm Hg

74.2cm Hg

69.4cm Hg

Pressure

Tazama Jibu

Swali 7 Ripoti

A car fuse marked 3A operates optimally on a 12V battery, calculate the resistance of the fuse

36.0\(\Omega\)

15.0\(\Omega\)

9.0\(\Omega\)

4.0\(\Omega\)

Maelezo ya Majibu

The formula for calculating resistance is: R = V/I where R is resistance, V is voltage and I is current. Given the fuse is marked 3A, it means it can carry a maximum current of 3A. Also, the voltage of the battery is given as 12V. Using Ohm's law, we can calculate the resistance of the fuse as follows: R = V/I = 12V / 3A = 4.0Ω Therefore, the resistance of the fuse is 4.0Ω.

Soma maelezo ya somo kwenye Gravitational Field (JAMB)

Gravitational Field

Tazama Jibu

Swali 8 Ripoti

The bob of a single pendulum has a mass of 0.02kg. Determine the weight of the bob [g = 10ms^-2]

0.02N

0.20N

20.00N

200.00N

Maelezo ya Majibu

The weight of an object is given by the product of its mass and the acceleration due to gravity, that is, weight = mass x acceleration due to gravity Given that the mass of the bob of the pendulum is 0.02kg and acceleration due to gravity is 10ms^-2, weight = 0.02kg x 10ms^-2 weight = 0.2N Therefore, the weight of the bob of the single pendulum is 0.2N. So the correct option is: - 0.20N

Tazama Jibu

Swali 9 Ripoti

On a basis of the kinetic theory, an increase in the temperature of a fixed volume of an ideal gas causes

a incease in the number of gas molecules

a decrease in the density of the gass

an increase in the average speed of the gas molecules

a decrease in pressure exerted by the gas

Maelezo ya Majibu

On the basis of the kinetic theory, an increase in the temperature of a fixed volume of an ideal gas causes an increase in the average speed of the gas molecules. This is because the kinetic theory states that the temperature of a gas is directly proportional to the average kinetic energy of its molecules. As the temperature increases, the molecules of the gas gain more kinetic energy and move faster, resulting in an increase in their average speed. This increase in the average speed of the gas molecules also results in an increase in the pressure exerted by the gas, as they collide more frequently with the walls of the container.

Soma maelezo ya somo kwenye Temperature And Its Measurement (JAMB)

Temperature And Its Measurement

Tazama Jibu

Swali 10 Ripoti

An object weighs 60.0N in air, 48.2N in a certain liquid X, and 44.9N in water, Calculate the relative density of X

3.300

1.279

0.932

0.782

Maelezo ya Majibu

Weight of object in air (W_air): 60.0 N

Weight of object in liquid X (W_X): 48.2 N

Weight of object in water (W_water): 44.9 N

The loss of weight in a fluid is equal to the buoyant force, which is equal to the weight of the displaced fluid.

Buoyant force in water: 𝐹buoyant, water=𝑊air−𝑊water=60.0 N−44.9 N=15.1 NFbuoyant, water=Wair−Wwater=60.0N−44.9N=15.1N

Since the buoyant force is equal to the weight of the water displaced and the density of water (ρ_water) is 1 g/cm³ (or 1000 kg/m³), the volume of the object (V) can be calculated using:

𝐹buoyant, water=𝜌water⋅𝑉⋅𝑔Fbuoyant, water=ρwater⋅V⋅g 15.1 N=1000 kg/m3⋅𝑉⋅9.8 m/s215.1N=1000kg/m3⋅V⋅9.8m/s2 𝑉=15.1 N1000 kg/m3⋅9.8 m/s2V=1000kg/m3⋅9.8m/s215.1N 𝑉≈1.54×10−3 m3V≈1.54×10−3m3

Buoyant force in liquid X:

𝐹buoyant, X=𝑊air−𝑊X=60.0 N−48.2 N=11.8 NFbuoyant, X=Wair−WX=60.0N−48.2N=11.8N

Using the same volume V (since the object's volume doesn't change), the density of liquid X (ρ_X) can be calculated:

𝐹buoyant, X=𝜌X⋅𝑉⋅𝑔Fbuoyant, X=ρX⋅V⋅g 11.8 N=𝜌X⋅1.54×10−3 m3⋅9.8 m/s211.8N=ρX⋅1.54×10−3m3⋅9.8m/s2 𝜌X=11.8 N1.54×10−3 m3⋅9.8 m/s2ρX=1.54×10−3m3⋅9.8m/s211.8N 𝜌X≈786.1 kg/m3ρX≈786.1kg/m3

Relative density of liquid X: The relative density (specific gravity) is the ratio of the density of liquid X to the density of water: Relative density=𝜌X𝜌water=786.1 kg/m31000 kg/m3≈0.786Relative density=ρwaterρX=1000kg/m3786.1kg/m3≈0.786

Therefore, the relative density of liquid X is approximately 0.786.

Soma maelezo ya somo kwenye Gravitational Field (JAMB)

Gravitational Field

Tazama Jibu

Swali 11 Ripoti

On a cold day, a concrete floor feels colder to the bear foot then a mat on the same floor because the

is better conductor of heat than the foot

mat loses heat to the bare foot at a faster rate

mat is better conductor of heat than the floor

concrete floor is a better conductor of heat than the mat

Maelezo ya Majibu

A concrete floor feels colder to bare feet than a mat on the same floor because the concrete floor is a better conductor of heat than the mat. Heat flows from a warmer object to a colder object until they reach thermal equilibrium. When we stand on the floor, the heat from our body transfers to the surrounding area by conduction. Since concrete is a better conductor of heat than the mat, it takes more heat away from our feet, making the concrete floor feel colder. The mat, on the other hand, insulates our feet and does not conduct heat away from our feet as efficiently as the concrete floor. Therefore, it feels warmer than the concrete floor.

Soma maelezo ya somo kwenye Heat Transfer (JAMB)

Soma maelezo ya somo kwenye Heat Energy (WAEC)

Soma maelezo ya somo kwenye Pressure (JAMB)

Heat Transfer

Heat Energy

Pressure

Tazama Jibu

Swali 12 Ripoti

A ball bearing is projected vertically upwards from the ground with a velocity of 15ms^-1. Calculate the time taken by the ball to return to the ground [g = 10ms^-1]

1.5s

3.0s

5.0s

7.5s

Maelezo ya Majibu

The ball bearing was projected upwards with an initial velocity of 15ms^-1. At the highest point, the velocity of the ball becomes zero before it starts falling back to the ground. Using the equation of motion for free-falling objects: h = ut + 1/2 gt^2 where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time. At the highest point, the height of the ball bearing is given by: h = (15)^2 / (2 × 10) = 11.25m (using v² = u² + 2gh) The time taken for the ball bearing to reach the highest point can be obtained by using the equation of motion: v = u + gt 0 = 15 - 10t t = 1.5s The total time taken for the ball bearing to reach the ground is twice the time taken to reach the highest point, which is: 2t = 2 × 1.5s = 3.0s Therefore, the time taken by the ball bearing to return to the ground is 3.0s. Hence, the answer is 3.0s.

Soma maelezo ya somo kwenye Motion (JAMB)

Motion

Tazama Jibu

Swali 13 Ripoti

Charges on a conductor are

evenly distributed over a surface of any shape

concentrate on the inner surface of the conductor

concentrate at the outer flat surface of the conductor

generally concentrated at sharply curved surface

Electrostatics

Tazama Jibu

Swali 14 Ripoti

Which of the following representations is correct for an atom X with 28 electrons and 30 neutrons?

\(^{30}_{28} X\)

\(^{28}_{30} X\)

\(^{58}_{30} X\)

\(^{58}_{28} X\)

Maelezo ya Majibu

The correct representation for an atom X with 28 electrons and 30 neutrons is \(^{58}_{28} X\). The atomic number of an element is the number of protons in its nucleus. Since the element X has 28 electrons, which are equal to the number of protons in its nucleus, the atomic number is 28. The mass number of an element is the total number of protons and neutrons in its nucleus. Since the element X has 30 neutrons in addition to its 28 protons, the mass number is 58. Therefore, the correct representation of the atom X is \(^{58}_{28} X\). Option (d) is the correct representation.

Soma maelezo ya somo kwenye Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

Tazama Jibu

Swali 15 Ripoti

The sound from a vibrating tuning sound is when the tip of its stem is placed on a wooden table than when in air because

the friction between the table and the tuning fork generates additional energy

air molecules obsorb sound wave but wood transmit sound waves

the table increases the frequency of the turning fork

a large mass of air is set into vibration by the table

Sound Waves

Propagation Of Sound Waves

Tazama Jibu

Swali 16 Ripoti

A steel needle floating on water, sinks when kerosine is added to the water. This is because the kerosine

increased the surface tension of the water

reduces the density of the water

reduces the surface tension of the water

reduces the upthrust on the needle

Electrostatics

Tazama Jibu

Swali 17 Ripoti

Calculate the energy stored in a 20\(\mu F\) capacitor. If the p.d between the plates is 40V

3.2 x 10^-2J

1.6 x 10^-2J

8.0 x 10^-4J

4.0 x 10^-4J

Capacitors

Tazama Jibu

Swali 18 Ripoti

A girl stand 80m away from a tall cliff and blows a whistle. If the speed of sound in air is 330ms^-1, how long would it take for her to hear the echo of the sound?

2.062s

0.970s

0.485s

0.242s

Scalars And Vectors

Thermal Expansion

Tazama Jibu

Swali 19 Ripoti

The temperature of 900cm³ of an ideal gas at a pressure of 114cm Hg is 27^oC. Calculate its volume at 76cm Hg and 0^oC

50.0cm³

546.0cm³

659.3cm³

1228.5cm³

Quantity Of Heat

Tazama Jibu

Swali 20 Ripoti

Which of the following concept is not an evidence of the particle nature of matter?

diffusion

brownian motion

diffraction

crystallization

Properties Of Waves: Reflection, Refraction, Diffraction

Tazama Jibu

Swali 21 Ripoti

Which of the following statements about X-rays is not correct? They

are electromagnetic waves

can be used to study crystal lattice

can destroy living cells

are produced from the nucleus of an atom

Maelezo ya Majibu

X-rays are not produced from the nucleus of an atom, so the statement "are produced from the nucleus of an atom" is not correct. X-rays are electromagnetic waves that have a high frequency and short wavelength. They can penetrate solid objects, making them useful for medical imaging, studying crystal lattice, and industrial applications. However, X-rays can also be harmful to living cells, as they have enough energy to ionize atoms and molecules, which can damage or destroy cells. X-rays are produced when high-energy electrons collide with a target material, such as tungsten, in an X-ray machine.

Soma maelezo ya somo kwenye Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum (WAEC)

Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum

Tazama Jibu

Swali 22 Ripoti

Given that the gravitational constant is G. Newton's universal law of gravitation states that the force of attraction between two masses M₁ and M₂ separation by a distance r is

\(Gr^2 M_1M_2\)

\(Gr M_1M_2\)

\(\frac{GM_1 M_2}{r^2}\)

\(\frac{GM_1 M_2}{r}\)

Maelezo ya Majibu

Newton's universal law of gravitation states that the force of attraction between two masses M1 and M2 separated by a distance r is given by the formula: F = G * M1 * M2 / r^2, where G is the gravitational constant. This means that the force of attraction between the two masses is directly proportional to the product of their masses (M1 and M2), and inversely proportional to the square of the distance between them (r^2). In other words, the greater the masses of the objects and the closer they are, the stronger the force of attraction between them. is the correct answer as it is the formula that represents the force of attraction between two masses based on Newton's universal law of gravitation.

Soma maelezo ya somo kwenye Gravitational Field (JAMB)

Gravitational Field

Tazama Jibu

Swali 23 Ripoti

Which of the following values on the absolute scale of temperature is the ice point?

0K

32K

100K

273k

Maelezo ya Majibu

The ice point is the temperature at which pure water melts or freezes. On the absolute scale of temperature, the ice point is equivalent to 273K. Therefore, the correct option is 273K.

Soma maelezo ya somo kwenye Temperature And Its Measurement (JAMB)

Temperature And Its Measurement

Tazama Jibu

Swali 24 Ripoti

Which of following functions is performed by manganese IV oxide in the Lenclanche cell?

control of local action

depolarisation of the cell

regulating current flow in the cell

reduction of the internal resistance of the cell

Maelezo ya Majibu

Manganese IV oxide in the Leclanché cell performs the function of depolarizing the cell. The Leclanché cell is a type of dry cell commonly used in household batteries. When a cell is discharging, chemical reactions occur inside the cell, which can lead to the accumulation of hydrogen gas on the negative electrode, hindering the flow of electricity. Manganese IV oxide acts as a depolarizer, meaning that it reacts with the hydrogen gas to form water, thereby preventing the accumulation of hydrogen gas and allowing the cell to continue functioning efficiently.

Soma maelezo ya somo kwenye Current Electricity (JAMB)

Soma maelezo ya somo kwenye Electric Cells (JAMB)

Current Electricity

Electric Cells

Tazama Jibu

Swali 25 Ripoti

Find the cost of running a 60W lamp for 24 hours. If 1kW hr cost 5 naira

14.4 naira

12.5 naira

7.2 naira

2.0 naira

Maelezo ya Majibu

To find the cost of running a 60W lamp for 24 hours, we need to calculate the energy consumed by the lamp in kilowatt-hours (kWh) and then multiply by the cost of one kWh. First, let's convert the power of the lamp from watts to kilowatts by dividing it by 1000: 60 W ÷ 1000 = 0.06 kW Next, we can calculate the energy consumed by the lamp in kWh by multiplying the power by the time: 0.06 kW × 24 h = 1.44 kWh Finally, we can find the cost of running the lamp by multiplying the energy consumed by the cost per kWh: 1.44 kWh × 5 naira/kWh = 7.2 naira Therefore, the answer is option (C) 7.2 naira.

Soma maelezo ya somo kwenye Electrical Energy And Power (JAMB)

Electrical Energy And Power

Tazama Jibu

Swali 26 Ripoti

A charge of 1.6 x 10^-10C is placed in a uniform electric field of intensity 2.0 x 10⁵ NC^-1. calculate the magnitude of the electric force exerted on the change

3.2 x 10⁵N

1.8 x 10⁵N

3.2 x 10^-5N

1.8 x 10^-5N

Maelezo ya Majibu

The magnitude of electric force can be calculated using the formula: Electric force (F) = charge (Q) x electric field intensity (E) Substituting the given values, we get: F = Q x E F = (1.6 x 10^-10 C) x (2.0 x 10^5 NC^-1) F = 3.2 x 10^-5 N Therefore, the magnitude of the electric force exerted on the charge is 3.2 x 10^-5 N. The correct option is (C) 3.2 x 10^-5 N.

Soma maelezo ya somo kwenye Electrostatics (JAMB)

Electrostatics

Tazama Jibu

Swali 27 Ripoti

A diver is 5.2m below the surface of water of density 1000Kgm^-3. If the atmospheric pressure is 1.02 x 10⁵pa. Calculate the pressure on the diver [g = 10ms^-2]

6.20 x 10⁴ pa

1.02 x 10⁵ pa

1.54 x 10⁵ pa

5.20 x 10⁵ pa

Maelezo ya Majibu

The pressure on the diver at a depth of 5.2m can be calculated using the formula: P = P₀ + ρgh where P₀ is the atmospheric pressure, ρ is the density of the water, g is the acceleration due to gravity, and h is the depth of the diver. Substituting the given values, we get: P = 1.02 x 10⁵ + (1000 kg/m³) x (10 m/s²) x (5.2 m) P = 1.02 x 10⁵ + 5.2 x 10⁴ Pa P = 1.54 x 10⁵ Pa Therefore, the pressure on the diver is 1.54 x 10⁵ Pa. The correct option is: 1.54 x 10⁵ pa.

Soma maelezo ya somo kwenye Pressure (JAMB)

Pressure

Tazama Jibu

Swali 28 Ripoti

The quantity of electric charge stored in a capacitor is measured in

farad

ampere

coulomb

volt

Maelezo ya Majibu

The quantity of electric charge stored in a capacitor is measured in coulombs. A capacitor is an electronic component that is used to store electric charge. When a capacitor is charged, it stores electrical energy in the form of electric charge. The amount of electric charge stored in a capacitor is directly proportional to the voltage applied across the capacitor and the capacitance of the capacitor. The unit of electric charge is coulomb, which is defined as the charge transported by a constant current of one ampere in one second. Therefore, the quantity of electric charge stored in a capacitor is measured in coulombs.

Soma maelezo ya somo kwenye Capacitors (JAMB)

Soma maelezo ya somo kwenye Fundamental And Derived Quantities And Units (WAEC)

Capacitors

Fundamental And Derived Quantities And Units

Tazama Jibu

Swali 29 Ripoti

A radioactive substance has a half-life of 3 days. If a mass of 1.55g of this substance is left after decaying for 15 days, determine the original value of the mass

49.6g

37.2g

24.8g

12.4g

Maelezo ya Majibu

The half-life of a radioactive substance is the time taken for half of the initial mass of the substance to decay. Let's denote the initial mass of the substance by m. After 3 days (one half-life), the mass of the substance remaining is m/2. After 6 days (two half-lives), the mass remaining is (m/2)/2 = m/4. Similarly, after 9 days (three half-lives), the mass remaining is m/8, and after 12 days (four half-lives), the mass remaining is m/16. After 15 days (five half-lives), we are told that there is 1.55g of the substance remaining. Therefore, we can set up the following equation: 1.55g = m/32 Solving for m gives: m = 49.6g Therefore, the original value of the mass of the radioactive substance was 49.6g.

Soma maelezo ya somo kwenye Wave-particle Paradox (WAEC)

Wave-particle Paradox

Tazama Jibu

Swali 30 Ripoti

A body is dropped from a certain height above the ground level, falls with uniform

speed

velocity

acceleration

retardation

Maelezo ya Majibu

When a body is dropped from a height above the ground level, it begins to fall towards the ground due to the force of gravity acting on it. The acceleration due to gravity is a constant value, which means that the speed of the body increases uniformly as it falls towards the ground. Therefore, the body falls with a uniform speed, meaning that the speed at which it is falling remains constant throughout its journey towards the ground. The body does not have a constant velocity because velocity is a vector quantity that takes into account both the speed and direction of the body. In this case, the body is only moving in one direction, towards the ground, so its velocity is constantly changing as it gains speed. The acceleration of the body is due to gravity and is constant throughout its fall. This means that the rate at which the body gains speed is also constant, resulting in a uniform acceleration. Retardation, on the other hand, refers to a decrease in speed or a negative acceleration. Since the body is only experiencing a force in the downward direction, there is no force acting against its motion to cause a decrease in speed. Therefore, there is no retardation acting on the body during its fall.

Soma maelezo ya somo kwenye Motion (JAMB)

Motion

Tazama Jibu

Swali 31 Ripoti

A loaded spring performs simple harmonic motion with an amplitude of 5cm. If the maximum acceleration of the load is 20cm s-1, calculate the angular frequency of the motion

2 rad s^-1

4 rad s^-1

5 rad s^-1

10 rad s^-1

Maelezo ya Majibu

The acceleration of an object in simple harmonic motion can be represented as a = -ω²x, where a is acceleration, x is displacement, and ω is the angular frequency. Given that the maximum acceleration of the load is 20cm s^-1, we can substitute a = 20cm s^-1, and x = 5cm (the amplitude) into the equation above to solve for ω. 20cm s^-1 = -ω²(5cm) ω² = -20cm s^-1/5cm = -4 s^-2 ω = ±2 s^-1 Since the problem asks for the magnitude of ω, we take the positive value: ω = 2 rad s^-1 Therefore, the answer is option (A) 2 rad s^-1.

Soma maelezo ya somo kwenye Scalars And Vectors (WAEC)

Soma maelezo ya somo kwenye Simple Harmonic Motion (WAEC)

Scalars And Vectors

Simple Harmonic Motion

Tazama Jibu

Swali 32 Ripoti

When a metal ball is heated through 30^oC,its volume becomes 1.0018cm³. If the linear expansivity of the material of the ball is 2.0 x 10^-5 K^-1, calculate its original volume

1.0000cm³

1.0020cm³

1.0036cm³

1.0180cm³

Maelezo ya Majibu

When a material is heated, it expands due to increase in temperature. The amount of expansion depends on the linear expansivity of the material which is the fractional increase in length per degree rise in temperature. Let V₀ be the original volume of the ball and ΔT = 30°C be the temperature rise. Then, the new volume V after heating is given by: V = V₀(1 + γΔT) where γ is the linear expansivity of the material. Substituting the given values, we have: V = 1.0018 cm³ = V₀(1 + 2.0 x 10^-5 x 30) Simplifying the expression, we get: V₀ = V / (1 + γΔT) = 1.0018 cm³ / (1 + 2.0 x 10^-5 x 30) Calculating this expression gives us: V₀ = 1.0000 cm³ Therefore, the original volume of the metal ball is 1.0000 cm³. Hence, the answer is 1.0000 cm³.

Soma maelezo ya somo kwenye Thermal Expansion (JAMB)

Thermal Expansion

Tazama Jibu

Swali 33 Ripoti

A magnified and virtual image of a near object is produced by

prism binoculas

astronomical telescope

periscope

simple microscope

Maelezo ya Majibu

None of the given options is correct. A magnified and virtual image of a near object is produced by a simple microscope. A simple microscope consists of a single converging lens that is used to magnify small objects, such as biological specimens or small components in electronic devices. When an object is placed close to the lens, a magnified and virtual image is formed on the same side of the lens as the object. The image is virtual because it cannot be projected onto a screen, and it is magnified because it appears larger than the object itself. Prism binoculars use two lenses and a prism to produce a magnified, upright image of a distant object. Astronomical telescopes are also used to view distant objects, such as stars and galaxies. A periscope is a device that uses mirrors to reflect light and allow the viewer to see objects around corners or over obstacles.

Soma maelezo ya somo kwenye Light Energy (JAMB)

Light Energy

Tazama Jibu

Swali 34 Ripoti

The speed of an object in rectilinear motion can be determine from the

area under a velocity-time graph

area under a distance-time graph

slope of a distance-time graph

slope of a velocity-time graph

Maelezo ya Majibu

The speed of an object in rectilinear motion can be determined from the slope of a distance-time graph. A distance-time graph plots the distance covered by an object on the y-axis against the time taken on the x-axis. The slope of this graph represents the rate of change of distance with respect to time, which is the speed of the object. The steeper the slope, the faster the object is moving, and the shallower the slope, the slower the object is moving. Therefore, the slope of a distance-time graph can be used to determine the speed of an object in rectilinear motion.

Soma maelezo ya somo kwenye Rectilinear Acceleration (WAEC)

Soma maelezo ya somo kwenye Speed And Velocity (WAEC)

Rectilinear Acceleration

Speed And Velocity

Tazama Jibu

Swali 35 Ripoti

A force acting on a body causes a change in the momentum of the body from 12kg ms^-1 to 16kg ms^-1 in 0.2s. calculate the magnitude of the force

140.0N

20.0N

4.0N

0.8N

Maelezo ya Majibu

The change in momentum of a body is given by the formula: Δp = mΔv where Δp is the change in momentum, m is the mass of the body, and Δv is the change in velocity. In this case, the change in momentum is: Δp = 16 kg ms^-1 - 12 kg ms^-1 = 4 kg ms^-1 The time taken for the change in momentum is: Δt = 0.2 s Therefore, the magnitude of the force is given by: F = Δp/Δt = (4 kg ms^-1)/(0.2 s) = 20 N So, the correct option is: 20.0N.

Soma maelezo ya somo kwenye Newton’s Laws Of Motion (WAEC)

Newton’s Laws Of Motion

Tazama Jibu

Swali 36 Ripoti

Which of the following reasons explains why the walls and ceilings of a standard concert hall are usually covered with perforated pads? To

increase the intensity of sound waves

increases the loudness of the sound waves

reduce the effect of revibration of sound waves

decreases thr frequency of sound waves

Maelezo ya Majibu

Perforated pads are used in concert halls to reduce the effect of reverberation of sound waves. Reverberation happens when sound waves reflect off surfaces multiple times, causing an echo-like effect that can distort the original sound. By covering walls and ceilings with perforated pads, the sound waves are absorbed by the pads, reducing their reflection and therefore reducing the amount of reverberation in the hall. This allows for clearer and more accurate sound, making it easier for performers and audience members to hear the music as intended. Therefore, the correct option is: "reduce the effect of reverberation of sound waves".

Soma maelezo ya somo kwenye Sound Waves (WAEC)

Soma maelezo ya somo kwenye Motion (WAEC)

Sound Waves

Motion

Tazama Jibu

Swali 37 Ripoti

The basic difference between a transverse wave and a longitudinal wave travelling in the same direction in a medium is in the

amplitude of the wave

wavelength of the wave

direction of vibration of the particles of the medium

period of vibration of the particle of the medium

Maelezo ya Majibu

The basic difference between a transverse wave and a longitudinal wave is in the direction of vibration of the particles of the medium. In a transverse wave, the particles of the medium vibrate perpendicular to the direction of propagation of the wave. In contrast, in a longitudinal wave, the particles of the medium vibrate parallel to the direction of propagation of the wave. Therefore, the direction of vibration of the particles of the medium is the main difference between a transverse wave and a longitudinal wave traveling in the same direction in a medium. The amplitude, wavelength, and period of vibration of the particles of the medium can be the same in both types of waves, depending on the specific characteristics of the wave.

Soma maelezo ya somo kwenye Electrostatics (JAMB)

Electrostatics

Tazama Jibu

Swali 38 Ripoti

In which of the following devices is the principle of photoelectric effect not applicable?

close-circuit television camera

burglar alarm

solar cells

periscope

Maelezo ya Majibu

The principle of photoelectric effect refers to the phenomenon where electrons are emitted from a material when light of certain frequencies shines on it. This means that in devices that use the photoelectric effect, the emission of electrons is triggered by light. Therefore, the device that does not use the photoelectric effect is the periscope. A periscope is an optical device that uses mirrors to reflect light and allows a viewer to see objects that are not in their direct line of sight. It does not use any photoelectric material or any process related to the emission of electrons by light.

Soma maelezo ya somo kwenye Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

Tazama Jibu

Swali 39 Ripoti

During a thunderstorm, lightning and thunder occurred simultaneously in the atmosphere. An observer on the earth surface's sees the lightning flash shortly before hearing the thunder. This is because the

atmospheric pressure is higher at the surface than at the higher altitudes

speed of sound is less than that of light

temperature of the atmosphere decreases with altitude

atmospheric density decreases with altitude

Maelezo ya Majibu

The reason why an observer on the earth's surface sees the lightning flash before hearing the thunder during a thunderstorm is that the speed of light is much faster than the speed of sound. When lightning occurs, it generates a large amount of energy that produces light, heat, and sound. Light travels at a very high speed of approximately 299,792,458 meters per second, whereas sound travels at a much lower speed of approximately 343 meters per second. Therefore, the observer sees the lightning flash almost instantaneously as it travels to the observer's eyes, while the sound waves from the thunder travel much slower and take some time to reach the observer's ears. This delay is known as the thunder's audible time delay, and the amount of time it takes for the sound waves to reach the observer is dependent on the distance between the observer and the lightning strike. Hence, the option that best explains why the observer sees the lightning flash before hearing the thunder is that the speed of sound is less than that of light.

Soma maelezo ya somo kwenye Sound Waves (WAEC)

Soma maelezo ya somo kwenye Temperature And Its Measurement (JAMB)

Sound Waves

Temperature And Its Measurement

Tazama Jibu

Swali 40 Ripoti

The image of an optical pin placed at the principal focus of a concave mirror will be formed

between the principal focus and the pole

at the centre of the curvature

between the principal focus and the centre of curvature

at infinity

Maelezo ya Majibu

When an object is placed at the principal focus of a concave mirror, the reflected rays will be parallel to each other. This happens because the light rays coming from the object get refracted by the mirror in such a way that they all converge at the principal focus of the mirror. Therefore, the image of the object will be formed at infinity. So, the correct option is "at infinity".

Soma maelezo ya somo kwenye Reflection Of Light At Plane And Curved Surfaces (JAMB)

Reflection Of Light At Plane And Curved Surfaces

Tazama Jibu

Swali 41 Ripoti

A machine of velocity ratio 5 is used in lifting a load with an effort of 500N. If the machine is 80% efficient. Determine the magnitude of load

2500N

2000N

900N

625N

Maelezo ya Majibu

The velocity ratio of a machine is defined as the ratio of the distance moved by the effort to the distance moved by the load. In general, it is given by: Velocity ratio = (distance moved by effort) / (distance moved by load) In this problem, the velocity ratio is given as 5, which means that for every 5 units of distance moved by the effort, the load moves 1 unit of distance. Let us assume that the load is lifted through a height of h meters. Then, the effort is applied through a distance of 5h meters. The work done by the effort is given by the product of the effort and the distance moved by it. Similarly, the work done on the load is given by the product of the load and the distance moved by it. Since the machine is 80% efficient, the work done by the effort is equal to 80% of the work done on the load. Mathematically, Effort x Distance moved by effort = Load x Distance moved by load x Efficiency 500N x 5h = Load x h x 0.8 Simplifying the above equation, we get: Load = (500N x 5 x 0.8) / 1 Load = 2000N Therefore, the magnitude of the load is 2000N. Hence, the correct option is: 2000N.

Tazama Jibu

Swali 42 Ripoti

A wave travelling from water to glass suffers a change in its speed at the common boundary. Which of the following properties explains this observation?

dispersion

refraction

interference

diffraction

Maelezo ya Majibu

The property that explains the observation of a wave changing its speed when travelling from water to glass at the common boundary is refraction. Refraction occurs when a wave crosses the boundary between two media with different densities, causing a change in its speed and direction. In this case, the speed of the wave changes because the density of the medium changes, as glass is denser than water. This change in speed causes the wave to bend or change direction. Therefore, refraction is the property that explains the observation of a wave changing its speed at the common boundary between water and glass.

Soma maelezo ya somo kwenye Refraction Of Light Through Plane And Curved Surfaces (JAMB)

Refraction Of Light Through Plane And Curved Surfaces

Tazama Jibu

Swali 43 Ripoti

On which of the following factor does the viscosity of a liquid depend? i. Nature of the liquid. ii. Temperature of the liquid. iii. Area of the liquid surface

i and ii only

ii and iii only

i and iii only

i, ii and iii

Temperature And Its Measurement

Pressure

Tazama Jibu

Swali 44 Ripoti

Which of the following statements about the mass and the weight of a body is not correct? its

mass is a scalar quantity

weight is a function of the gravitational pull on it

mass on earth and on the moon is the same

weigh at the equatior and at the poles is the same

Maelezo ya Majibu

The statement that "weigh at the equator and at the poles is the same" is not correct. Mass is a scalar quantity that measures the amount of matter in an object, and it remains the same regardless of the object's location. Weight, on the other hand, is a force that is exerted on an object due to the gravitational pull of the planet it is on. Therefore, weight depends on both the mass of the object and the strength of the gravitational field it is in. The gravitational pull on the surface of the Earth is not the same everywhere, as the Earth is not a perfect sphere and it rotates. The gravitational force at the poles is slightly stronger than at the equator because the poles are closer to the center of the Earth, where gravity is stronger. As a result, the weight of an object will be slightly different at the poles and the equator, even if its mass remains the same.

Tazama Jibu

Swali 45 Ripoti

A body is said to be moving with uniform acceleration if it experiences equal

increase in velocity at equal time intervals

decreases in velocity at equal time intervals

increases in speed at equal time intervals

decreases in speed at equal time intervals

Maelezo ya Majibu

A body is said to be moving with uniform acceleration if it experiences an equal increase in velocity at equal time intervals. In other words, the rate at which the velocity of the body changes is constant over time. This means that if we plot the velocity of the body against time, we will get a straight line with a constant slope. The acceleration can be calculated by dividing the change in velocity by the change in time. It is important to note that uniform acceleration refers to a constant rate of change in velocity and not speed, since the velocity of a body is a vector quantity that takes into account both its speed and direction.

Soma maelezo ya somo kwenye Rectilinear Acceleration (WAEC)

Soma maelezo ya somo kwenye Equilibrium Of Forces (WAEC)

Rectilinear Acceleration

Equilibrium Of Forces

Tazama Jibu

Swali 46 Ripoti

The molecular structure of a liquid is such that

the molecules have unlimited freedom of movement

molecular movement is restricted to vibration only

intermolecular collisions take place

all molecules moves move with the same speed

Thermal Expansion

Structure Of Matter And Kinetic Theory

Tazama Jibu

Swali 47 Ripoti

An elastic string of force constant 200N m^-1 is stretched through 0.8m within its elastic limit. Calculate the energy stored in the string

64.0J

80.0J

128.0J

160.0J

Maelezo ya Majibu

The energy stored in an elastic string that is stretched is given by the equation: E = 0.5kx² where E is the energy stored, k is the force constant of the string, and x is the displacement from its original length. In this case, the force constant k is given as 200 N/m, and the displacement x is 0.8 m. Substituting these values in the above equation, we get: E = 0.5 × 200 N/m × (0.8 m)² E = 0.5 × 200 N/m × 0.64 m² E = 64 J Therefore, the energy stored in the elastic string is 64J. Hence, the correct option is (a) 64.0J.

Soma maelezo ya somo kwenye Elasticity (JAMB)

Elasticity

Tazama Jibu

Swali 48 Ripoti

An atom is normally electrically neutral because the

number of electrons is equal to the number of protons

number of electrons is equal to the number of neutrons

number of protons is equal to the number of neutrons

electrons of the atom are buried deeply in the nucleus

Maelezo ya Majibu

An atom is composed of protons, neutrons, and electrons. The protons are positively charged, the electrons are negatively charged, and the neutrons are neutral. In an atom that is normally electrically neutral, the number of positively charged protons is equal to the number of negatively charged electrons. This means that the positive charge of the protons is exactly balanced by the negative charge of the electrons, resulting in a net charge of zero. Therefore, the correct option is that the number of electrons is equal to the number of protons.

Soma maelezo ya somo kwenye Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

Tazama Jibu

Swali 49 Ripoti

A man 1.8m tall stands 3m away from a pin hole camera. If the distance between the pin hole and the screen of the camera is 0.3m. Calculate the height of the image of the man produced by the camera

0.18m

0.50m

1.62m

18.00m

Maelezo ya Majibu

The pinhole camera model assumes that light travels in straight lines and that the aperture is so small that the light rays pass through it in parallel lines. Based on this model, we can use the similar triangle relationship between the object and image to find the height of the image produced. We have a right-angled triangle with the object, pinhole and screen of the camera as the vertices. Let's call the height of the man "h" and the height of the image "h'". From the triangle, we have: h / 3m = h' / 0.3m Cross-multiplying, we get: h' = (h / 3) x 0.3 Substituting h = 1.8m, we get: h' = (1.8 / 3) x 0.3 = 0.18m Therefore, the height of the image of the man produced by the camera is 0.18m. The correct option is (a) 0.18m.

Soma maelezo ya somo kwenye Motion (JAMB)

Motion

Tazama Jibu

Swali 50 Ripoti

The main function of the mouth piece of a telephone is that it converts sound energy to

mechanical energy

electrical energy

chemical energy

thermal energy

Maelezo ya Majibu

The main function of the mouthpiece of a telephone is to convert sound energy to electrical energy. When a person speaks into the mouthpiece, the sound waves from their voice cause a diaphragm or microphone in the mouthpiece to vibrate. These vibrations are then converted into electrical signals that can be transmitted through the telephone wires to the receiver at the other end. The electrical signals can then be converted back into sound waves by the receiver, allowing the person on the other end to hear the speaker's voice. Therefore, option B - electrical energy - is the correct answer.

Soma maelezo ya somo kwenye Electrostatics (JAMB)

Electrostatics

Tazama Jibu

Swali 51 Ripoti

In an experiment using a converging lens to produce real images on a screen, the linear magnification m, is plotted against the image distance v, as illustrated in the diagram below. The distance OP represents the

focal legth of the lens

thickness of the lens

radius of curvature of the lens

diameter of the lens

Structure Of The Atom (Nigeria Only)

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