WAEC SSCE - General Mathematics - 2015…

Swali 1 Ripoti

Make K the subject of the relation T = $\sqrt{\frac{TK - H}{K - H}}$

K = $\frac{H(T^2 - 1)}{T^2 - T}$ Jibu sahihi

K = $\frac{HT}{(T - 1)^2}$

K = $\frac{H(T^2 + 1)}{T}$

K = $\frac{H(T - 1)}{T}$

Maelezo ya Majibu

Soma maelezo ya somo kwenye Algebraic Fractions (WAEC)

Soma maelezo ya somo kwenye Quadratic Equations (WAEC)

Algebraic Fractions

Quadratic Equations

Tazama Jibu

Swali 2 Ripoti

$\begin{array}{c|c}
x & 0 & 1\frac{1}{4} & 2 & 4\\
\hline
y & 3 & 5\frac{1}{2} & &
\end{array}$
The table given shows some values for a linear graph. Find the gradient of the line

2 Jibu sahihi

Maelezo ya Majibu

To find the gradient of a line, we need to calculate the change in y divided by the change in x between two points on the line. Let's choose two points on the line from the given table. We can select the points (0,3) and (2,y), where y is the value of y for x = 2. The change in y is y - 3, and the change in x is 2 - 0 = 2. Therefore, the gradient of the line is: gradient = change in y / change in x = (y - 3) / 2 We don't know the value of y yet, but we can use the other point on the line to find it. Using the points (1.25, 5.5) and (2, y), we get: gradient = (y - 5.5) / (2 - 1.25) = (y - 5.5) / 0.75 Setting the two expressions for the gradient equal to each other, we get: (y - 3) / 2 = (y - 5.5) / 0.75 Solving for y gives: y = 7 Therefore, the value of y for x = 2 is 7, and the gradient of the line is: gradient = (y - 3) / 2 = (7 - 3) / 2 = 2 So the answer is 2, and the gradient of the line is 2. In simple terms, the gradient of a line tells us how steep the line is. If the gradient is positive, the line is sloping upwards from left to right. If the gradient is negative, the line is sloping downwards from left to right. The larger the absolute value of the gradient, the steeper the line.

Soma maelezo ya somo kwenye Graphs Of Linear And Quadratic Functions (WAEC)

Graphs Of Linear And Quadratic Functions

Tazama Jibu

Swali 3 Ripoti

Given that logx 64 = 3, evaluate x log$_2$8

12 Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Modular Arithmetic (WAEC)

Soma maelezo ya somo kwenye Logarithms (WAEC)

Modular Arithmetic

Logarithms

Tazama Jibu

Swali 4 Ripoti

In the given diagram, $\bar{QT}$ and $\bar{PR}$ are straight lines, < ROS = (3n - 20), < SOT = n, < POL = m and < QOL is a right angle. Find the value of n.

35^o Jibu sahihi

40^o

55^o

60^o

Maelezo ya Majibu

Since < QOL is a right angle, we have: < QOT + < SOT = 90^o Since < QOT = 180^o - < POL, we have: < QOT = 180^o - m Substituting into the first equation, we get: 180^o - m + n = 90^o n - m = 90^o - 180^o = -90^o Also, from the diagram, we have: < QOT + < ROS + < SOT = 180^o Substituting < QOT = 180^o - < POL and simplifying, we get: 180^o - m + (3n - 20) + n = 180^o 4n - m = 20 We now have a system of two equations: n - m = -90^o 4n - m = 20 Solving simultaneously, we get: n = 35^o

Soma maelezo ya somo kwenye Algebraic Expressions (WAEC)

Soma maelezo ya somo kwenye Angles And Intercepts On Parallel Lines (WAEC)

Algebraic Expressions

Angles And Intercepts On Parallel Lines

Tazama Jibu

Swali 5 Ripoti

The angle of elevation of an aircraft from a point K on the horizontal ground 30$\alpha$. If the aircraft is 800m above the ground, how far is it from K?

400.00m

692.82m

923.76m

1,600.99m Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Introductory Calculus (WAEC)

Soma maelezo ya somo kwenye Coordinate Geometry (WAEC)

Introductory Calculus

Coordinate Geometry

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Swali 6 Ripoti

Ada draws the graph of y = x² - x - 2 and y = 2x - 1 on the same axes. Which of these equations is she solving?

x² - x - 3 = 0

x² - 3x - 1 = 0 Jibu sahihi

x² - 3x - 3 = 0

x² + 3x - 1 = 0

Maelezo ya Majibu

Soma maelezo ya somo kwenye Quadratic Equations (WAEC)

Soma maelezo ya somo kwenye Graphs Of Linear And Quadratic Functions (WAEC)

Quadratic Equations

Graphs Of Linear And Quadratic Functions

Tazama Jibu

Swali 7 Ripoti

A trader bought 100 oranges at 5 for N40.00 and 20 for N120.00. Find the profit or loss percent

20% profit

20% loss

25% profit

25% loss Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Number Bases (WAEC)

Number Bases

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Swali 8 Ripoti

If {X: 2 d- x d- 19; X integer} and 7 + x = 4 (mod 9), find the highest value of x

15 Jibu sahihi

Maelezo ya Majibu

To solve this problem, we need to use the given conditions to find the possible values of x and then determine the highest value among them. From the first condition, we know that x is an integer between 2 and 19 (inclusive) and can be represented as {X: 2 d- x d- 19; X integer}. This means that x can take on any of the following values: 2, 3, 4, ..., 18, 19. The second condition tells us that 7 + x is congruent to 4 modulo 9, which can be written as: 7 + x ≡ 4 (mod 9) To solve for x, we can subtract 7 from both sides of the congruence: x ≡ -3 (mod 9) Since we want x to be between 2 and 19, we can add or subtract multiples of 9 to -3 until we get a value within the range of possible values for x. Doing so, we obtain: x ≡ -3 (mod 9) x ≡ 15 (mod 9) Since 15 is the largest value of x that satisfies both conditions, our answer is 15.

Soma maelezo ya somo kwenye Positive And Negative Integers, Rational Numbers (WAEC)

Soma maelezo ya somo kwenye Modular Arithmetic (WAEC)

Positive And Negative Integers, Rational Numbers

Modular Arithmetic

Tazama Jibu

Swali 9 Ripoti

Adding 42 to a given positive number gives the same result as squaring the number. Find the number

7 Jibu sahihi

Maelezo ya Majibu

Let's call the unknown number "x". According to the problem, adding 42 to x gives the same result as squaring x. We can write this as an equation: x + 42 = x^2 To solve for x, we can rearrange this equation to get it in standard quadratic form: x^2 - x - 42 = 0 Now we can factor this quadratic equation: (x - 7)(x + 6) = 0 This gives us two possible solutions: x = 7 and x = -6. However, we were given that x is a positive number, so we can discard the negative solution. Therefore, the answer is x = 7. To check our answer, we can substitute x = 7 into the original equation: 7 + 42 = 49 7^2 = 49 So adding 42 to 7 does indeed give the same result as squaring 7.

Tazama Jibu

Swali 10 Ripoti

Factorize completely: 6ax - 12by - 9ay + 8bx

(2a - 3b)(4x + 3y)

(3a + 4b)(2x - 3y) Jibu sahihi

(3a - 4b)(2x + 3y)

(2a + 3b)(4x -3y)

Maelezo ya Majibu

Soma maelezo ya somo kwenye Algebraic Expressions (WAEC)

Algebraic Expressions

Tazama Jibu

Swali 11 Ripoti

In the diagram, O is the centre. If PQ//RS and ∠ONS = 140°, find the size of ∠POM.

40^o Jibu sahihi

50^o

60^o

80^o

Maelezo ya Majibu

Soma maelezo ya somo kwenye Euclidean Geometry (JAMB)

Euclidean Geometry

Tazama Jibu

Swali 12 Ripoti

Find the value of p if $\frac{1}{4}$p + 3q = 10 and 2p - q = 7

4 Jibu sahihi

-3

-4

Maelezo ya Majibu

Soma maelezo ya somo kwenye Solution Of Linear Equations (WAEC)

Soma maelezo ya somo kwenye Algebraic Expressions (WAEC)

Solution Of Linear Equations

Algebraic Expressions

Tazama Jibu

Swali 13 Ripoti

The probability that kebba, Ebou and Omar will hit a target are $\frac{2}{3}$, $\frac{3}{4}$ and $\frac{4}{5}$ respectively. Find the probability that only Kebba will hit the target.

$\frac{2}{5}$

$\frac{7}{60}$

$\frac{1}{30}$ Jibu sahihi

$\frac{1}{60}$

Maelezo ya Majibu

The probability that only Kebba will hit the target means that Kebba hits the target and the other two miss the target. We can find this probability by multiplying the probability of Kebba hitting the target with the probability of Ebou missing the target and the probability of Omar missing the target. Probability that only Kebba hits the target = Probability of Kebba hitting the target × Probability of Ebou missing the target × Probability of Omar missing the target = $\frac{2}{3}$ × $\frac{1}{4}$ × $\frac{1}{5}$ = $\frac{2}{3\times4\times5}$ = $\frac{1}{30}$ Therefore, the probability that only Kebba will hit the target is $\frac{1}{30}$.

Soma maelezo ya somo kwenye Probability (WAEC)

Probability

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Swali 14 Ripoti

Find the equation whose roots are $\frac{3}{4}$ and -4

4x² - 13x + 12 = 0

4x² - 13x - 12 = 0

4x² + 13x - 12 = 0 Jibu sahihi

4x² + 13x + 12 = 0

Maelezo ya Majibu

If a quadratic equation has roots p and q, then it can be expressed in the factored form as:

(x - p)(x - q) = 0

Expanding this equation, we get:

x² - (p + q)x + pq = 0

In this case, the roots are given as $\frac{3}{4}$ and -4. Thus, the equation can be expressed as:

(x - \(\frac{3}{4}\))(x + 4) = 0

Expanding this equation, we get:

x² + (4 - \(\frac{3}{4}\))x - 3 = 0

Multiplying throughout by 4 to eliminate fractions, we get:

4x² + 13x - 12 = 0

Therefore, the equation whose roots are $\frac{3}{4}$ and -4 is 4x² + 13x - 12 = 0.

Hence, the answer is 4x² + 13x - 12 = 0.

Tazama Jibu

Swali 15 Ripoti

Tom will be 25 years old in n years' time. If he is 5 years younger than Bade's present age.

(30 - n)years Jibu sahihi

(20 - n)years

(25 - n)years

(30 + n)years

Maelezo ya Majibu

Soma maelezo ya somo kwenye Solution Of Linear Equations (WAEC)

Soma maelezo ya somo kwenye Circles (WAEC)

Solution Of Linear Equations

Circles

Tazama Jibu

Swali 16 Ripoti

Which of the following is used to determine the mode of a grouped data?

Bar chart

Frequency polygon

Ogive

Histogram Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Representation Of Data (JAMB)

Soma maelezo ya somo kwenye Integration (JAMB)

Representation Of Data

Integration

Tazama Jibu

Swali 17 Ripoti

In the diagram, PQ//RT, QR//Su,

134^o

132^o Jibu sahihi

96^o

48^o

Maelezo ya Majibu

Soma maelezo ya somo kwenye Angles And Intercepts On Parallel Lines (WAEC)

Soma maelezo ya somo kwenye Triangles And Polygons (WAEC)

Angles And Intercepts On Parallel Lines

Triangles And Polygons

Tazama Jibu

Swali 18 Ripoti

If 2ⁿ = y, Find 2$^{(2 + \frac{n}{3})}$

4y$^\frac{1}{3}$ Jibu sahihi

4y$^-3$

2y$^\frac{1}{3}$

2y$^-3$

Maelezo ya Majibu

We know that 2$^n$ = y. Therefore, 2$^{(2 + \frac{n}{3})}$ can be written as 2$^2$ × 2$^{\frac{n}{3}}$ = 4 × 2$^{\frac{n}{3}}$. Substituting 2$^n$ = y in the above equation, we get: 2$^{(2 + \frac{n}{3})}$ = 4y$^\frac{1}{3}$ Therefore, the answer is (a) 4y$^\frac{1}{3}$.

Soma maelezo ya somo kwenye Indices (WAEC)

Soma maelezo ya somo kwenye Logarithms (WAEC)

Indices

Logarithms

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Swali 19 Ripoti

PQRT is square. If x is the midpoint of PQ, Calculate correct to the nearest degree, LPXS

53^o

55^o

63^o Jibu sahihi

65^o

Maelezo ya Majibu

Tazama Jibu

Swali 20 Ripoti

If m = 4, n = 9 and r = 16., evaluate $\frac{m}{n}$ - 1$\frac{7}{9}$ + $\frac{n}{r}$

1$\frac{5}{16}$

1$\frac{1}{16}$

$\frac{5}{16}$

- 1$\frac{37}{48}$ Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Fractions, Decimals And Approximations (WAEC)

Fractions, Decimals And Approximations

Tazama Jibu

Swali 21 Ripoti

The rate of consumption of petrol by a vehicle varies directly as the square of the distance covered. If 4 litres of petrol is consumed on a distance of 15km. how far would the vehicle go on 9 litres of petrol?

22$\frac{1}{2}$km Jibu sahihi

30km

33$\frac{1}{2}$km

45km

Maelezo ya Majibu

Since the rate of consumption of petrol varies directly as the square of the distance covered, let's assume that the rate is k$\frac{\text{litres}}{\text{km}^2}$. Then we can write the relationship as: rate of consumption = k(distance covered)$^2$ We are given that when the distance covered is 15 km, the rate of consumption is 4 litres. Substituting these values in the above equation, we get: 4 = k(15)$^2$ k = $\frac{4}{15^2}$ Now, we need to find how far the vehicle can go on 9 litres of petrol. Let's assume that the vehicle can travel a distance of x km on 9 litres of petrol. Using the same equation as before, we get: 9 = $\frac{4}{15^2}$(x)$^2$ Simplifying this equation, we get: x$^2$ = $\frac{9}{\frac{4}{15^2}}$ x$^2$ = 506.25 x = 22.5 Therefore, the vehicle can travel 22.5 km on 9 litres of petrol. So the answer is 22$\frac{1}{2}$km.

Soma maelezo ya somo kwenye Sequence And Series (WAEC)

Soma maelezo ya somo kwenye Ratio, Proportions And Rates (WAEC)

Sequence And Series

Ratio, Proportions And Rates

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Swali 22 Ripoti

A trader bought an engine for $15,000.00 outside Nigeria. If the exchange rate is $0.075 to N1.00, how much did the engine cost in Naira?

N250,000.00

N200,000.00 Jibu sahihi

N150,000.00

N100,000.00

Maelezo ya Majibu

Soma maelezo ya somo kwenye Positive And Negative Integers, Rational Numbers (WAEC)

Soma maelezo ya somo kwenye Modular Arithmetic (WAEC)

Positive And Negative Integers, Rational Numbers

Modular Arithmetic

Tazama Jibu

Swali 23 Ripoti

The dimension of a rectangular tank are 2m by 7m by 11m. If its volume is equal to that of a cylindrical tank of height 4cm, calculate the base radius of the cylindrical tank. [Take $\pi = \frac{22}{7}$]

14cm

3$\frac{1}{2}$m Jibu sahihi

1$\frac{3}{4}$m

Maelezo ya Majibu

Soma maelezo ya somo kwenye Volumes (WAEC)

Soma maelezo ya somo kwenye Fractions, Decimals And Approximations (WAEC)

Volumes

Fractions, Decimals And Approximations

Tazama Jibu

Swali 24 Ripoti

In a circle radius rcm, a chord 16$\sqrt{3}cm$ long is 10cmfrom the centre of the circle. Find, correct to the nearest cm, the value of r

22cm

17cm Jibu sahihi

16cm

15cm

Maelezo ya Majibu

In a circle, a radius is a line segment that connects the center of the circle to any point on the circle. A chord is a line segment that connects two points on a circle. Given that a chord of length 16$\sqrt{3}cm$ is 10cm from the center of the circle, we can use the Pythagorean theorem to find the length of the radius. First, we draw a line from the center of the circle perpendicular to the chord, creating a right triangle with the radius, the perpendicular line, and half the chord length (which is $8\sqrt{3}$ cm). Using the Pythagorean theorem: \begin{align*} r^2 &= (8\sqrt{3})^2 + 10^2 \\ r^2 &= 192 + 100 \\ r^2 &= 292 \\ r &\approx \sqrt{292} \\ r &\approx 17 \text{ cm} \end{align*} Rounding to the nearest whole number, we get the answer of 17cm. Therefore, the correct option is (b) 17cm.

Soma maelezo ya somo kwenye Circles (WAEC)

Soma maelezo ya somo kwenye Triangles And Polygons (WAEC)

Circles

Triangles And Polygons

Tazama Jibu

Swali 25 Ripoti

A letter is selected from the letters of the English alphabet. What is the probability that the letter selected is from the word MATHEMATICS?

$\frac{9}{13}$

$\frac{11}{26}$

$\frac{4}{13}$ Jibu sahihi

$\frac{1}{26}$

Maelezo ya Majibu

The word MATHEMATICS contains the letters A, C, E, H, I, M, S, and T. Since there are 26 letters in the English alphabet, the probability of selecting any letter from the alphabet is 1 out of 26. Out of the letters in the word MATHEMATICS, there are 8 letters, so the probability of selecting a letter from the word MATHEMATICS is 8 out of 26. Therefore, the probability of selecting a letter from the word MATHEMATICS is: $$\frac{8}{26}=\frac{4}{13}$$ Therefore, the correct answer is option (C).

Soma maelezo ya somo kwenye Probability (WAEC)

Soma maelezo ya somo kwenye Surds (radicals) (WAEC)

Probability

Surds (radicals)

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Swali 26 Ripoti

If $\frac{\sqrt{2} + \sqrt{3}}{\sqrt{3}}$ is simplified as m + n$\sqrt{6}$, find the value of (m + n)

$\frac{1}{3}$

$\frac{2}{3}$

1$\frac{1}{3}$ Jibu sahihi

1$\frac{2}{3}$

Maelezo ya Majibu

Soma maelezo ya somo kwenye Surds (radicals) (WAEC)

Surds (radicals)

Tazama Jibu

Swali 27 Ripoti

The population of students in a school is 810. If this is represented on a pie chart, calculate the sectoral angle for a class of 7 students

32^o Jibu sahihi

45^o

60^o

75^o

Maelezo ya Majibu

To find the sectoral angle for a class of 7 students, we first need to calculate what percentage of the total population they represent: Percentage of class of 7 students = (Number of students in the class / Total population) x 100% Percentage of class of 7 students = (7 / 810) x 100% Percentage of class of 7 students = 0.864% (rounded to three decimal places) Next, we need to convert this percentage to an angle of the pie chart. We know that a full circle is 360 degrees, and the percentage of the class of 7 students represents a certain portion of this circle. We can use the following formula to calculate the sectoral angle: Sectoral angle = Percentage of class of 7 students x 360 degrees Plugging in the percentage we calculated earlier, we get: Sectoral angle = 0.864% x 360 degrees Sectoral angle ≈ 3.11 degrees (rounded to two decimal places) Therefore, the sectoral angle for a class of 7 students in the pie chart is approximately 3.11 degrees. So, the correct option is (a) 32^o.

Soma maelezo ya somo kwenye Representation Of Data (JAMB)

Soma maelezo ya somo kwenye Sets (JAMB)

Soma maelezo ya somo kwenye Mensuration (JAMB)

Representation Of Data

Sets

Mensuration

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Swali 28 Ripoti

Simplify: $\frac{3x - y}{xy} - \frac{2x + 3y}{2xy} + \frac{1}{2}$

$\frac{4x + 5y - xy}{2xy}$

$\frac{5y - 4x + xy}{2xy}$

$\frac{5x + 4y - xy}{2xy}$

$\frac{4x - 5y + xy}{2xy}$ Jibu sahihi

Maelezo ya Majibu

To simplify the expression, we first need to find a common denominator for the fractions. The lowest common multiple of the denominators xy and 2xy is 2xy. $\frac{3x - y}{xy} - \frac{2x + 3y}{2xy} + \frac{1}{2} = \frac{3x\cdot2 - y\cdot2}{xy\cdot2} - \frac{2x\cdot1 + 3y\cdot1}{2xy\cdot1} + \frac{1\cdot xy}{2\cdot xy}$ Simplifying further, we get: $\frac{6x - 2y}{2xy} - \frac{2x + 3y}{2xy} + \frac{xy}{2xy}$ Combining like terms, we get: $\frac{4x - 5y + xy}{2xy}$ Therefore, the answer is option D: $\frac{4x - 5y + xy}{2xy}$.

Tazama Jibu

Swali 29 Ripoti

In the diagram, VW//YZ, |WX| = 6cm, |XY| = 16cm, |YZ| = 20cm and |ZX| = 12cm. Calculate |VX|

3cm

4cm

6cm

8cm Jibu sahihi

Maelezo ya Majibu

Tazama Jibu

Swali 30 Ripoti

In the diagram, O is the centre, $\bar{RT}$ is a diameter, < PQT = 33$^o$ and < TOS = 76$^o$. Using the diagram, find the size of angle PRS.

76^o

71^o Jibu sahihi

38^o

33^o

Maelezo ya Majibu

Soma maelezo ya somo kwenye Circles (WAEC)

Circles

Tazama Jibu

Swali 31 Ripoti

$\begin{array}{c|c}
Scores & 0 - 4 & 5 - 9 & 10 - 14\\
\hline Frequency & 2 & 1 & 2\end{array}$

The table shows the distribution of the scores of some students in a test. Calculate the mean scores.

5.6

6.2

6.6

7.0 Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Integration (JAMB)

Soma maelezo ya somo kwenye Statistics (WAEC)

Integration

Statistics

Tazama Jibu

Swali 32 Ripoti

A farmer uses $\frac{2}{5}$ of his land to grow cassava, $\frac{1}{3}$ of the remaining for yam and the rest for maize. Find the part of the land used for maize

$\frac{2}{15}$

$\frac{2}{5}$ Jibu sahihi

$\frac{2}{3}$

$\frac{4}{5}$

Maelezo ya Majibu

Let's assume the farmer has 15 parts of land. The fraction of land used for cassava is $\frac{2}{5}$ of 15, which is 6 parts. The remaining land is 15 - 6 = 9 parts. The fraction of the remaining land used for yam is $\frac{1}{3}$ of 9, which is 3 parts. Therefore, the part of the land used for maize is the remaining land after cassava and yam are planted, which is 9 - 3 = 6 parts. So the fraction of the land used for maize is $\frac{6}{15}$, which simplifies to $\frac{2}{5}$. Therefore, the answer is option (B) $\frac{2}{5}$.

Soma maelezo ya somo kwenye Fractions, Decimals And Approximations (WAEC)

Soma maelezo ya somo kwenye Number Bases (WAEC)

Fractions, Decimals And Approximations

Number Bases

Tazama Jibu

Swali 33 Ripoti

In the diagram, O is the centre, $\bar{RT}$ is a diameter, < PQT = 33$^o$ and <TOS = 76$^o$. Using the diagram, calculate the value of angle PTR.

73^o

67^o

57^o Jibu sahihi

37^o

Maelezo ya Majibu

Soma maelezo ya somo kwenye Number Bases (WAEC)

Soma maelezo ya somo kwenye Coordinate Geometry (WAEC)

Number Bases

Coordinate Geometry

Tazama Jibu

Swali 34 Ripoti

In the diagram, PTR is a tangent to the centre O. If angles TON = 108°, Calculate the size of angle PTN

132^o

126^o Jibu sahihi

108^o

102^o

Maelezo ya Majibu

Soma maelezo ya somo kwenye Circles (WAEC)

Soma maelezo ya somo kwenye Algebraic Expressions (WAEC)

Soma maelezo ya somo kwenye Euclidean Geometry (JAMB)

Soma maelezo ya somo kwenye Triangles And Polygons (WAEC)

Circles

Algebraic Expressions

Euclidean Geometry

Triangles And Polygons

Tazama Jibu

Swali 35 Ripoti

Calculate the mean deviation of 5, 3, 0, 7, 2, 1

0.0

2.0 Jibu sahihi

2.5

3.0

Maelezo ya Majibu

To find the mean deviation, we need to first calculate the mean of the given set of numbers: Mean = (5 + 3 + 0 + 7 + 2 + 1) / 6 = 18 / 6 = 3 Next, we need to find the absolute deviation of each number from the mean: |5 - 3| = 2 |3 - 3| = 0 |0 - 3| = 3 |7 - 3| = 4 |2 - 3| = 1 |1 - 3| = 2 To calculate the mean deviation, we add up these absolute deviations and divide by the number of numbers: Mean deviation = (2 + 0 + 3 + 4 + 1 + 2) / 6 = 12 / 6 = 2 Therefore, the answer is option (B) 2.0.

Soma maelezo ya somo kwenye Measures Of Location (JAMB)

Measures Of Location

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Swali 36 Ripoti

The area of a rhombus is 110 cm$^2$. If the diagonals are 20 cm and (2x + 1) cm long, find the value of x.

5.0 Jibu sahihi

4.0

3.0

2.5

Maelezo ya Majibu

Soma maelezo ya somo kwenye Areas (WAEC)

Soma maelezo ya somo kwenye Angles (WAEC)

Areas

Angles

Tazama Jibu

Swali 37 Ripoti

The volume of a cone of height 3cm is 38$\frac{1}{2}$cm³. Find the radius of its base. [Take $\pi = \frac{22}{7}$]

3.0cm

3.5cm Jibu sahihi

4.0cm

4.5cm

Maelezo ya Majibu

Tazama Jibu

Swali 38 Ripoti

Two angles of a pentagon are in the ratio 2:3. The others are 60^o each. Calculate the smaller of the two angles

72^o

100^o

120^o

144^o Jibu sahihi

Maelezo ya Majibu

Let's call the two angles that are in the ratio 2:3 as "2x" and "3x". The sum of the interior angles of a pentagon is given by the formula (5-2) x 180 degrees = 540 degrees. Since the other three angles are all 60 degrees each, we can find the sum of those angles by multiplying 60 by 3, which gives us 180 degrees. Now we can set up an equation to solve for the unknown angle, which is 2x + 3x. 2x + 3x + 180 = 540 Simplifying this equation, we get: 5x + 180 = 540 Subtracting 180 from both sides, we get: 5x = 360 Dividing both sides by 5, we get: x = 72 So the smaller angle, which is 2x, is equal to 2 times 72, which is 144 degrees. Therefore, the correct answer is 144 degrees.

Soma maelezo ya somo kwenye Angles (WAEC)

Angles

Tazama Jibu

Swali 39 Ripoti

In the diagram, the shaded part is carpet laid in a room with dimensions 3.5m by 2.2m leaving a margin of 0.5m round it. Find area of the margin

4.7m² Jibu sahihi

4.9m²

5.7m²

5.9m²

Maelezo ya Majibu

Soma maelezo ya somo kwenye Lengths And Perimeters (WAEC)

Lengths And Perimeters

Tazama Jibu

Swali 40 Ripoti

If $\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1$, find the value of x.

$\frac{1}{2}$ Jibu sahihi

-$\frac{1}{2}$

-1

Maelezo ya Majibu

Soma maelezo ya somo kwenye Number Bases (WAEC)

Soma maelezo ya somo kwenye Indices (WAEC)

Number Bases

Indices

Tazama Jibu

Swali 41 Ripoti

Find the 7^th term of the sequence: 2, 5, 10, 17, 6,...

50 Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Sequence And Series (WAEC)

Sequence And Series

Tazama Jibu

Swali 42 Ripoti

The sum 11011₂, 1111₂ and 10_m10_n0₂. Find the value of m and n.

m = 0, n = 0

m = 1, n = 0

m = 0, n = 1 Jibu sahihi

m = 1, n = 1

Maelezo ya Majibu

Soma maelezo ya somo kwenye Number Bases (WAEC)

Number Bases

Tazama Jibu

Swali 43 Ripoti

Describe the shaded portion in the diagram

P' $\cap$ Q $\cap$ R' Jibu sahihi

(P' $\cap$ R)' $\cap$ R

P' $\cap$ Q $\cap$ R

(P $\cap$ Q)' $\cap$ R

Maelezo ya Majibu

The shaded portion in the diagram represents the set of elements that belong to the complement of P and the intersection of Q and R. In other words, it represents the set of elements that are not in P, but are in both Q and R. Therefore, the correct answer is P' $\cap$ Q $\cap$ R'.

Soma maelezo ya somo kwenye Logical Reasoning (WAEC)

Soma maelezo ya somo kwenye Sets (JAMB)

Logical Reasoning

Sets

Tazama Jibu

Swali 44 Ripoti

The scores of twenty students in a test are as follows: 44, 47, 48, 49, 50, 51, 52, 53, 53, 54, 58, 59, 60, 61, 63, 65, 67, 70, 73, 75. Find the third quartile.

64 Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Measures Of Dispersion (JAMB)

Measures Of Dispersion

Tazama Jibu

Swali 45 Ripoti

In the diagram, $\bar{OX}$ bisects < YXZ and $\bar{OZ}$ bisects < YZX. If < XYZ = 68^o, calculate the value of < XOZ

68^o

72^o

112^o

124^o Jibu sahihi

Maelezo ya Majibu

Soma maelezo ya somo kwenye Angles And Intercepts On Parallel Lines (WAEC)

Angles And Intercepts On Parallel Lines

Tazama Jibu






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WAEC SSCE - General Mathematics - 2015 (Objective)