JAMB UTME - Physics - 2010
Swali 1 Ripoti
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Swali 2 Ripoti
In the diagram above, a 200 W bulb is lighted by a 240 V a.c mains supply. If 1kwh is sold at ₦40, the cost of keeping the bulb lighted for a day is
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= 200W x 24hr = 4800wh
= 4.8 kwh
But 1 kwh cost N40
∴ 4.8kwh costs 4.8 x 40
= N192
Swali 3 Ripoti
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Swali 4 Ripoti
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= 2 + 4 + 8 = 14μF
V = 6V
Energy = 1/2CV21/2 x 14 x 10-6 x 62
= 2.52 x 10-4 J
Swali 5 Ripoti
In the diagram above, if the south-poles of two magnets strokes steel bar, the polarities at T and V will respectively be
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Swali 6 Ripoti
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Swali 7 Ripoti
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Swali 8 Ripoti
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Swali 9 Ripoti
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Swali 10 Ripoti
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Swali 11 Ripoti
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Swali 12 Ripoti
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Thus V = K√T or K = V/T
V is independent of pressure and density at a fixed temperature.
∴ V1/√T1 = V2/√T2
T1 = 16 + 273 = 289K, V1 = 340ms-1
T2 = 127 + 273 = 400K, V2 = ?
| 340 | = | V2 |
| √289 | √400 |
| ∴ V2 = | 340√400 |
| _√289 |
= 400m/s
Swali 13 Ripoti
The diagram above shows a velocity - time graph. The statement that is true about this motion is that the car
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Swali 14 Ripoti
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Swali 15 Ripoti
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15 + 5 = 20mH = (20)H/1000
1 = 5A
Energy of inductor, (1)/2 L I2
= (1)/2 X (20)/1000 X 5-2
= 0.25 J
Swali 16 Ripoti
The diagram above shows a balanced metre bridge, the value of x is
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∴ R = 4Ω
l/l1 = R/R1
(x)/(100-x) = 4/8
4(100-x) = 8x
400-4x = 8x
400 = 8x + 4x = 12x
x = 400/12 = 33.3cm
Swali 17 Ripoti
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Swali 18 Ripoti
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Swali 19 Ripoti
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Swali 20 Ripoti
The density of a certain oil on frying becomes
0.4 kgm-3 with the volume of 20m3. what will be its initial volume when its initial density is 0.8 kgm-3 assuming no loss of oil due to spillage?
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Swali 21 Ripoti
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Swali 22 Ripoti
The diagram above represents balls in an undulating surface. Which of the following option represents positions of stable equilibrium?
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Swali 23 Ripoti
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= average force x extension
= (1)/2 Fe
= (1)/2 x 300 N (30.5 - 30.0) x 10-2 m
= (300)/2 x 0.5 x 10-2 = 0.75J
Swali 24 Ripoti
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Swali 25 Ripoti
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Swali 26 Ripoti
Two metals P and Q are heated through the same temperature difference. If the ratio of the linear expansivities of P to Q is 2:3 and the ratio of their
Length is 3: 4 respectively, the ratio of the increase in lengths of P to Q is
Swali 27 Ripoti
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Swali 28 Ripoti
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R = resistance of the multiplier
G = resistance of the galvanometer
∴ G = (vg-R)/lg 5(1000/10) - 490 = 500 -490 = 10Ω
Swali 29 Ripoti
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Swali 30 Ripoti
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Swali 31 Ripoti
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Swali 32 Ripoti
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Swali 33 Ripoti
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Swali 34 Ripoti
The radioisotope \( {}^{235}_{92}\mathrm{U} \) decays by emitting two alpha particles, three beta particles and a gamma ray. What is the mass and atomic number of the resulting element?
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Swali 35 Ripoti
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Swali 36 Ripoti
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Swali 37 Ripoti
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Swali 38 Ripoti
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Swali 39 Ripoti
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Swali 40 Ripoti
[molar gas constant = 8.3 J mol-1 k-1]
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PV = NRT
i.e P = (NRT)/V = (1 x 8.3 x 300)/10-2
= 2.49 x 105 Nm-1
Swali 41 Ripoti
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Swali 42 Ripoti
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Swali 43 Ripoti
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L = y + x = 0.5m
∴ x = L - y
= distance moved in the direction of force (which is the weight) when the body is released But cos 60o = y/0.5
∴ y = 0.5cos60 = 0.5 x 1/2 = 0.25
∴ x = l - y = 0.5 - 0.25 = 0.25m
Work done = force x distance moved in the direction of force.
= 0.1 x 0.25 = 0.0252J
Swali 44 Ripoti
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Swali 45 Ripoti
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Swali 46 Ripoti
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Swali 47 Ripoti
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Swali 48 Ripoti
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so, when voltage is high and current is low heat generated in the wire will be minimal.
Therefore, high voltage and low current prevent overheating of the coil.
