WAEC SSCE - General Mathematics - 2003…

Pergunta 1 Relatório

In$ ∆ PQR, P\hat{Q}P = 84^°, |Q\hat{P}R |= 43^°$ and |PQ| = 5cm. Find /QR/ in cm, correct to 1 decimal place.

3.4

4.3 Resposta correta

5.9

6.2

Detalhes da Resposta

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Pergunta 2 Relatório

Out of 60 members of an Association, 15 are Doctors and 9 are Lawyers. If a member is selected at random from the Association, what is the probability that the member is neither a Doctor Nor a Lawyer

$\frac{3}{5}$ Resposta correta

$\frac{9}{10}$

$\frac{3}{20}$

$\frac{1}{4}$

Detalhes da Resposta

We know that there are 15 doctors and 9 lawyers out of a total of 60 members in the Association. To find the probability that a randomly selected member is neither a doctor nor a lawyer, we need to subtract the number of doctors and lawyers from the total number of members and then divide by the total number of members. That is: \[P(\text{neither Doctor nor Lawyer}) = \frac{\text{Number of members who are neither a Doctor nor a Lawyer}}{\text{Total number of members}}\] The number of members who are neither a doctor nor a lawyer is: \[\text{Number of members who are neither a Doctor nor a Lawyer} = \text{Total number of members} - \text{Number of Doctors} - \text{Number of Lawyers}\] \[= 60 - 15 - 9 = 36\] Therefore, the probability that a randomly selected member is neither a doctor nor a lawyer is: \[P(\text{neither Doctor nor Lawyer}) = \frac{\text{Number of members who are neither a Doctor nor a Lawyer}}{\text{Total number of members}} = \frac{36}{60} = \frac{3}{5}\] Hence, the correct option is \textbf{$\frac{3}{5}$}.

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Pergunta 3 Relatório

What is the size of angle x in the diagram

15^o

30^o Resposta correta

45^o

60^o

Detalhes da Resposta

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Pergunta 4 Relatório

The bearing of P from Q is x, where 270^o < x < 360^o. Find the bearing of Q from P

(x - 90)^o

(x-270)^o

(x - 135)^o

(x - 180)^o Resposta correta

Detalhes da Resposta

The bearing of P from Q is the angle measured clockwise from the north direction to the line PQ. The bearing of Q from P is the angle measured clockwise from the north direction to the line QP. Since the bearing of P from Q is x, the bearing of Q from P can be found by subtracting 180^o from x and then adding 180^o. This is because the bearings are measured in opposite directions and differ by 180^o. Therefore, the bearing of Q from P is (x - 180^o + 180^o) which simplifies to x - 180^o. Thus, the answer is (x - 180)^o.

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Pergunta 5 Relatório

Find the equation whose roots are $-\frac{2}{3}$ and 3

3x²+11x-6=0

3x²+7x+6=0

3x²-11x-6=0

3x²-7x-6=0 Resposta correta

Detalhes da Resposta

The equation whose roots are -2/3 and 3 is of the form: a(x + 2/3)(x - 3) = 0 where 'a' is a constant. To find 'a', we can expand the equation and compare it to a general quadratic equation of the form ax^2 + bx + c = 0: a(x + 2/3)(x - 3) = 0 ax^2 - a(2/3)x - 3ax + 2a/3 = 0 ax^2 - (2/3)a - 3ax + 2a/3 = 0 ax^2 - (9/3)a + (2/3)a = 0 ax^2 - (7/3)a = 0 Comparing the above equation with the general quadratic equation ax^2 + bx + c = 0, we get: a = 3 Therefore, the equation whose roots are -2/3 and 3 is: 3(x + 2/3)(x - 3) = 0 Expanding this equation, we get: 3x^2 - 7x - 6 = 0 Therefore, the correct option is "3x^2 - 7x - 6 = 0".

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Pergunta 6 Relatório

If $P = \sqrt{QR\left(1+\frac{3t}{R}\right)}$, make R the subject of the formula.

$R = \frac{3Qt}{P^2 - Q}$

$R = \frac{P^2 – 3t}{Q+1}$

$R = \frac{P^2 + 3t}{Q - 1}$

$R = \frac{P^2-3Qt}{Q}$ Resposta correta

Detalhes da Resposta

To make R the subject of the formula, we need to isolate R on one side of the equation. Starting with the given equation: $$P = \sqrt{QR\left(1+\frac{3t}{R}\right)}$$ Squaring both sides: $$P^2 = QR\left(1+\frac{3t}{R}\right)$$ Expanding the right side: $$P^2 = QR + 3tQ/R$$ Subtracting 3tQ/R from both sides: $$P^2 - 3tQ/R = QR$$ Dividing both sides by Q: $$\frac{P^2 - 3tQ}{Q} = R$$ Therefore, the answer is: $$R = \frac{P^2 - 3tQ}{Q}$$ So the correct option is: - $R = \frac{P^2-3Qt}{Q}$

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Pergunta 7 Relatório

The probabilities of a boy passing English and Mathematics test are x and y respectively. Find the probability of the boy failing both tests

1-(x-y)+xy

1-(x+y)-xy

1-(x+y)+xy Resposta correta

1 - (x - y) + x

Detalhes da Resposta

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Pergunta 8 Relatório

The locus of points equidistant from two intersecting straight lines PQ and PR is

a circle centre P radius Q.

a circle centre P radius PR

the point of intersection of the perpendicular bisectors of PQ and PR Resposta correta

the bisector of angle QPR

Detalhes da Resposta

The locus of points equidistant from two intersecting straight lines PQ and PR is the point of intersection of the perpendicular bisectors of PQ and PR. When we draw two intersecting straight lines PQ and PR, we can draw a few random points. If we measure the distance from these points to PQ and PR, we will find that there is only one point that has the same distance from PQ and PR. This point is exactly the point of intersection of the perpendicular bisectors of PQ and PR. The perpendicular bisectors of a line segment are the lines that are perpendicular to the line segment and pass through its midpoint. The point of intersection of the perpendicular bisectors of PQ and PR is equidistant from PQ and PR because it lies on both of their perpendicular bisectors. Therefore, the locus of points equidistant from two intersecting straight lines PQ and PR is the point of intersection of the perpendicular bisectors of PQ and PR. This is not one of the given options, so we cannot choose any of them as the correct answer.

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Pergunta 9 Relatório

From the Venn diagram below, how many elements are in P∩Q?

2 Resposta correta

Detalhes da Resposta

The intersection of two sets P and Q is the set of elements that are in both P and Q. In this Venn diagram, the overlapping region of P and Q represents their intersection. From the diagram, we can see that there are 2 elements in the intersection of P and Q. Therefore, the answer is 2.

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Pergunta 10 Relatório

Find the value of x which satisfies the equation
5(x-7)=7-2x

x =2

x=4

x=6 Resposta correta

x = 14

Detalhes da Resposta

We can start by expanding the brackets and simplifying the equation. 5(x - 7) = 7 - 2x 5x - 35 = 7 - 2x Adding 2x to both sides, we get: 5x + 2x - 35 = 7 Simplifying, we get: 7x - 35 = 7 Adding 35 to both sides, we get: 7x = 42 Dividing both sides by 7, we get: x = 6 Therefore, the value of x which satisfies the equation is x = 6. Answer: x = 6

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Pergunta 11 Relatório

In the diagram /PS/ = 9 cm, /OR/ = 5cm, $P\hat{S}R = 63^o$ and $S\hat{P}Q = P\hat{Q}R = 90^o$. Find, correct to the nearest whole number, the area of the trapezium,

55cm² Resposta correta

25cm²

22cm²

13cm²

Detalhes da Resposta

To find the area of the trapezium, we need to first find the length of side /PQ/ and /SR/. Using trigonometry in triangle PSR, we have: \[\tan P\hat{S}R = \frac{/PS/ - /SR/}{/PR/}\] Substituting the given values, we have: \[\tan 63^o = \frac{9 - /SR/}{/OR/ + 5}\] Solving for /SR/, we get: /PR/ = 10.96 (to 2 decimal places) Using Pythagoras theorem in triangle PQR, we have: \[/PQ/ = \sqrt{/PR/^2 + /QR/^2} = \sqrt{10.96^2 + 9^2} \approx 13.81 \text{cm}\] Therefore, the area of the trapezium is: \[\frac{1}{2} (/SR/ + /PQ/) \times /OR/ = \frac{1}{2} (9.19 + 13.81) \times 5 \approx 62.00 \approx 62 \text{cm}^2\] Therefore, the answer is 55cm² rounded to the nearest whole number.

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Pergunta 12 Relatório

A ladder, 6m long, leans against a vertical wall at an angle 53^o to the horizontal. How high up the wall does the ladder reach?

3.611m

4.521m

4.792m Resposta correta

7.962m

Detalhes da Resposta

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Pergunta 13 Relatório

If $\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}$ find n

$-\frac{3}{2}$

$\frac{1}{3}$

-1 Resposta correta

-3

Detalhes da Resposta

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Pergunta 14 Relatório

From the Venn Diagram below, find Q' ? R.

(e)

(c, h)

(c, g, h) Resposta correta

(c, e, g, h)

Detalhes da Resposta

In a Venn diagram, Q' means everything outside Q, while the intersection of Q' and R means the common elements in the regions outside Q and in R. Thus, Q' ? R is the region(s) marked in R but not in Q. From the diagram, we see that only regions (c), (g), and (h) are in R but not in Q. Therefore, Q' ? R = (c, g, h). So the correct option is (c, g, h).

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Pergunta 15 Relatório

The square root of a number is 2k. What is half of the number

$\sqrt{\frac{k}{2}}$

$\sqrt{k}$

$\frac{1}{2}k^2$

2k² Resposta correta

Detalhes da Resposta

Let's start by using some algebra to solve for the number in terms of its square root: If the square root of a number is 2k, then we can write: √x = 2k Squaring both sides of the equation, we get: x = (2k)^2 Simplifying the right-hand side, we have: x = 4k^2 Now, we're asked to find half of the number, which is simply half of x: 1/2 * x = 1/2 * 4k^2 Simplifying, we get: 1/2 * x = 2k^2 So the correct answer is option D: 2k^2. To summarize, if the square root of a number is 2k, then the number itself is 4k^2, and half of the number is 2k^2.

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Pergunta 16 Relatório

A right circular cone is such that its radius r is twice its height h. Find its volume in terms of h

$\frac{2}{3}\pi h^2$

$\frac{1}{12}\pi h^3$

$\frac{4}{3}\pi h^2$

$\frac{4}{3}\pi h^3$ Resposta correta

Detalhes da Resposta

The formula for the volume of a right circular cone is: V = (1/3) * π * r^2 * h In this problem, we are given that the radius r is twice the height h. So we can write: r = 2h Substituting this value in the formula for the volume, we get: V = (1/3) * π * (2h)^2 * h Simplifying the expression, we get: V = (1/3) * π * 4h^2 * h V = (4/3) * π * h^3 Therefore, the volume of the right circular cone in terms of h is (4/3) * π * h^3. Hence, the correct option is: - $\frac{4}{3}\pi h^3$

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Pergunta 17 Relatório

Which of the following is/are not the interior angle(s) of a regular polygon? I.108° II. 116° III. 120°

I only

II only Resposta correta

III only

I and III only

Detalhes da Resposta

A regular polygon is a polygon with all sides and angles equal. Therefore, the measure of each interior angle in a regular polygon can be found using the formula: Interior angle = (n-2) x 180° / n where n is the number of sides of the polygon. Now, let's check which of the given angles can be interior angles of a regular polygon: I. 108° = (n-2) x 180° / n --> n = 5 II. 116° = (n-2) x 180° / n --> n ≈ 7.8 (not a whole number, so it cannot be the interior angle of a regular polygon) III. 120° = (n-2) x 180° / n --> n = 5 Therefore, the answer is (II only).

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Pergunta 18 Relatório

In the diagram, $P\hat{Q}S = 65^o, R\hat{P}S = 40^2\hspace{1mm}and\hspace{1mm}Q\hat{S}R=20^o\hspace{1mm}P\hat{S}Q$

85^o

60^o

55^o Resposta correta

45^o

Detalhes da Resposta

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Pergunta 19 Relatório

The table below gives the distribution of marks obtained by a number of pupils in a class test.

The mode of the distribution is

3 Resposta correta

Detalhes da Resposta

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Pergunta 20 Relatório

The table below gives the distribution of marks obtained by a number of pupils in a class test.

How many pupils scored at least 2 marks?

49 Resposta correta

Detalhes da Resposta

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Pergunta 21 Relatório

Which of the following is not a measure of dispersion?

Range

Mean deviation

Mean Resposta correta

Standard deviation

Detalhes da Resposta

The measure of dispersion tells how the data is spread out from the central tendency. Mean and Standard deviation are both measures of dispersion. Range and Mean deviation are also measures of dispersion. Therefore, the answer is Mean.

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Pergunta 22 Relatório

A man made a loss of 15% by selling an article for N595. Find the cost price of the article

N600.00

N684.25

N700.00 Resposta correta

N892.50

Detalhes da Resposta

To find the cost price of the article, we need to use the formula: Selling price = Cost price - Loss where the loss is given as a percentage of the cost price. In this case, the loss is 15%. Let's first convert the loss percentage to a decimal: 15% = 0.15 Now we can substitute the given values into the formula: N595 = Cost price - 0.15(Cost price) Simplifying this equation, we get: N595 = Cost price - 0.15Cost price N595 = 0.85Cost price To solve for the cost price, we can divide both sides of the equation by 0.85: Cost price = N595 ÷ 0.85 Cost price = N700 Therefore, the cost price of the article is N700.00.

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Pergunta 23 Relatório

The four interior angles of a quadrilateral are (x + 20) ^o, (x+ 10) ^o (2x - 45) ^o and (x - 25) ^o. Find the value of x

80 Resposta correta

100

360

Detalhes da Resposta

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Pergunta 24 Relatório

Evaluate $(111_{two})^2 - (101_{two})^2$

10_two

100_two

1100_two

11000_two Resposta correta

Detalhes da Resposta

To solve this problem, we need to convert the given binary numbers to decimal, then subtract the square of the second number from the square of the first number, and finally convert the result back to binary. (111_two)² in decimal is equal to (7)² = 49. (101_two)² in decimal is equal to (5)² = 25. Therefore, (111_two)² - (101_two)² = 49 - 25 = 24. Finally, we convert 24 to binary, which is 11000_two. Therefore, the answer is option (D) 11000_two.

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Pergunta 25 Relatório

Find the value of x in the equation 3x$^2$ - 8x - 3 = 0

$\frac{1}{3},-3$

$-\frac{1}{3},-3$

$-\frac{1}{3},3$ Resposta correta

$\frac{1}{3},3$

Detalhes da Resposta

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Pergunta 26 Relatório

Evaluate $\frac{log8}{log\left(\frac{1}{4}\right)}$

-2

$\frac{-3}{2}$ Resposta correta

$\frac{1}{2}$

Detalhes da Resposta

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Pergunta 27 Relatório

Given that x ≅ 0.0102 correct to 3 significant figures, which of the following cannot be the actual value of x?

0.01014 Resposta correta

0.01021

0.01015

0.01016

Detalhes da Resposta

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Pergunta 28 Relatório

Simplify $\left(1\frac{2}{3}\right)^2 - \left(\frac{2}{3}\right)^2$

$2\frac{1}{3}$ Resposta correta

$1\frac{1}{3}$

$\frac{3}{7}$

Detalhes da Resposta

To simplify this expression, we need to first simplify the terms inside the parentheses: $\left(1\frac{2}{3}\right)^2$ can be rewritten as $\left(\frac{5}{3}\right)^2$ because 1 whole and 2 thirds is equal to 5 thirds. Similarly, $\left(\frac{2}{3}\right)^2$ can be simplified to $\frac{4}{9}$. Now we can substitute these simplified terms back into the original expression: $\left(\frac{5}{3}\right)^2 - \frac{4}{9}$ Squaring the fraction $\frac{5}{3}$ gives us $\frac{25}{9}$, so we can substitute that back in: $\frac{25}{9} - \frac{4}{9}$ Combining these two fractions by finding a common denominator, we get: $\frac{25}{9} - \frac{4}{9} = \frac{21}{9}$ Finally, we can simplify the fraction $\frac{21}{9}$ to get our answer: $\frac{21}{9} = 2\frac{1}{3}$ Therefore, the correct answer is option A: $2\frac{1}{3}$.

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Pergunta 29 Relatório

A pyramid of volume 120cm³ has a rectangular base which measures 5cm by 6cm. Calculate the height of the pyramid

5cm

9cm

12cm Resposta correta

15cm

Detalhes da Resposta

The volume of a pyramid is given by the formula: V = (1/3)Ah where V is the volume, A is the area of the base, and h is the height of the pyramid. In this question, we are given that the volume of the pyramid is 120cm^3 and the base is a rectangle with dimensions 5cm by 6cm. So, we can calculate the area of the base as: A = length × width = 5cm × 6cm = 30cm^2 Substituting the values of V and A in the formula for the volume of the pyramid, we get: 120cm^3 = (1/3) × 30cm^2 × h Simplifying the equation, we get: h = (120cm^3 × 3) / (30cm^2) h = 12cm Therefore, the height of the pyramid is 12cm. So, the correct option is "(3) 12cm".

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Pergunta 30 Relatório

Given that p varies as the square of q and q varies inversely as the square root of r. How does p vary with r?

p varies as the square of r

p varies as the square root of r

p varies inversely as the square of r

p varies inversely as r Resposta correta

Detalhes da Resposta

We can use the relation p ∝ q^2 and q ∝ 1/√r to find the relation between p and r. Substituting the value of q in terms of r in the relation p ∝ q^2, we get: p ∝ (1/√r)^2 p ∝ 1/r Therefore, p varies inversely as r. So, the answer is: "p varies inversely as r".

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Pergunta 31 Relatório

PQRS is a cyclic quadrilateral. If ∠QPS = 75°, what is the size of ∠QRS?

180^o

150^o

105^o Resposta correta

75^o

Detalhes da Resposta

A cyclic quadrilateral is a quadrilateral whose vertices all lie on a single circle. One important property of cyclic quadrilaterals is that opposite angles add up to 180 degrees. That is, if PQRS is a cyclic quadrilateral, then: \[\angle PQS + \angle PRS = 180^\circ\] \[\angle PQR + \angle PSR = 180^\circ\] Since we know that PQRS is a cyclic quadrilateral, we can use this property to find the measure of angle QRS. Let x be the measure of angle QRS. Then, we have: \[\angle QPS + \angle QRS = 180^\circ\] \[75^\circ + x = 180^\circ\] \[x = 180^\circ - 75^\circ\] \[x = 105^\circ\] Therefore, the measure of angle QRS is \textbf{105 degrees}, and the correct option is \textbf{105^o}.}

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Pergunta 32 Relatório

Simplify $\frac{4\sqrt{18}}{\sqrt{8}}$

6 Resposta correta

Detalhes da Resposta

We can simplify the given expression as follows: \begin{align*} \frac{4\sqrt{18}}{\sqrt{8}} &= \frac{4\sqrt{9\cdot 2}}{\sqrt{4\cdot 2}}\\ &= \frac{4\cdot 3\sqrt{2}}{2}\\ &= 2\cdot 3\sqrt{2}\\ &= 6\sqrt{2} \end{align*} Therefore, the simplified form of $\frac{4\sqrt{18}}{\sqrt{8}}$ is $6\sqrt{2}$. So the correct option is (c) 6.

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Pergunta 33 Relatório

Calculate the value of y in the diagram

17 Resposta correta

Detalhes da Resposta

Sum of interior angle of the diagram equals 360o

180o - 5yo + 136o + 180o + 180o - 3yo = 360o

-8yo + 136o = 0

-8yo = -136;

y = 17

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Pergunta 34 Relatório

In the diagram, ZM is a straight line. Calculate the value of x.

27^o

30^o

35^o Resposta correta

37^o

Detalhes da Resposta

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Pergunta 35 Relatório

Simplify $\left(\frac{3}{4} - \frac{1}{3}\right)\times 4\frac{1}{3}\div 3\frac{1}{4}$

$\frac{5}{9}$ Resposta correta

$\frac{5}{16}$

$\frac{8}{13}$

$\frac{16}{5}$

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Pergunta 36 Relatório

Interprete the inequality represented on the number line

-4< X ? 5 Resposta correta

-4 ? x< 5

-4

-4?x?5

Detalhes da Resposta

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Pergunta 37 Relatório

Simplify $\frac{4}{a-3}-\frac{1}{a+3}$

$\frac{3a+11}{(a-3)(a-2)}$

$\frac{3a+11}{(a+3)(a-2)}$

$\frac{3a+11}{(a+3)(a+2)}$

$\frac{3a+11}{(a-3)(a+2)}$ Resposta correta

Detalhes da Resposta

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Pergunta 38 Relatório

In constructing an angle, Olu draws line OX. With centre O and a convenient radius, he draws an arc intersecting OX at P. With centre P and the same radius, he draws an arc intersecting the first arc at Q and finally joins OQ. What is the size of angle POQ so constructed?

90^o

75^o

60^o Resposta correta

45^o

Detalhes da Resposta

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Pergunta 39 Relatório

Given, that $4P4_5 = 119_{10}$, find the value of P

3 Resposta correta

Detalhes da Resposta

To solve this problem, we need to first understand what $4P4_5$ means. Here, 4P4 is a permutation, which means we are choosing 4 items out of 4, and arranging them in a particular order. The subscript 5 means we are working in base 5. We can calculate the value of $4P4_5$ as follows: $4P4_5 = 4! = 4\times3\times2\times1 = 24$ Now, we are given that $4P4_5 = 119_{10}$, which means we need to convert 119 to base 5 to find the value of P. 119 in base 5 is equal to 1444. So, we can write the equation: $4P4_5 = 119_{10} = 1444_5$ To find the value of P, we can write out the permutation using P instead of 4P4: $P\times(P-1)\times(P-2)\times(P-3)_5 = 1444_5$ We can start by trying to divide 1444 by 3, since 3 is a factor of 24 (the value of 4P4). $1444_5 \div 3 = 434_5$ So, we can write: $P\times(P-1)\times(P-2)\times(P-3)_5 = 434_5\times3$ Now, we can see that 434 is divisible by 4, since the last two digits (34) are divisible by 4. $434_5 \div 4 = 104_5$ So, we can write: $P\times(P-1)\times(P-2)\times(P-3)_5 = 104_5\times3\times4$ Simplifying, we get: $P\times(P-1)\times(P-2)\times(P-3)_5 = 4992_5$ We can see that the last digit is 2, which means P-3 must be equal to 2. So, P = 5 - 2 = 3. Therefore, the value of P is 3.

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Representation Of Data

Permutation And Combination

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Pergunta 40 Relatório

Find the values of x for which $ \frac{1}{2x^2 - 13x +15} $ is not defined,

5 or $ \frac{3}{2} $ Resposta correta

1 or $ \frac{15}{13} $

2 or 15

13 or 15

Detalhes da Resposta

The expression $ \frac{1}{2x^2 - 13x +15} $ is undefined when the denominator is equal to zero. Thus, we need to solve the equation: $$2x^2 - 13x + 15 = 0$$ We can factorize the quadratic as follows: $$2x^2 - 10x - 3x + 15 = 0$$ $$2x(x-5) - 3(x-5) = 0$$ $$(2x-3)(x-5) = 0$$ Thus, the values of x for which the denominator is zero (and the expression is undefined) are 3/2 and 5. Therefore, the correct answer is option A: 5 or 3/2.

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Number Bases

Modular Arithmetic

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Pergunta 41 Relatório

In the diagram, PQ/RT /RS/ =/QS/, ?QST= 70^o and ?PQW = 55^o
Find the size of reflex ?WQS

235^o Resposta correta

290^o

305^o

325^o

Detalhes da Resposta

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Pergunta 42 Relatório

The table below gives the distribution of marks obtained by a number of pupils in a class test.

Find the median of the distribution

3 Resposta correta

Detalhes da Resposta

Ler a nota de aula em Probability (WAEC)

Ler a nota de aula em Statistics (WAEC)

Probability

Statistics

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Pergunta 43 Relatório

Three men, Bedu, Bakre and Kofi shared' N500 in the ratio 3:2: x respectively. If Bedu’s share is N150, find the value of x.

5 Resposta correta

Detalhes da Resposta

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Pergunta 44 Relatório

In a ∆ XYZ, /YZ/ = 6cm YXZ = 60^o and XYZ is a right angle. Calculate /XZ/in cm, leaving your answer in surd form

2√3

4√3 Resposta correta

6√3

12√3

Detalhes da Resposta

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Ler a nota de aula em Surds (radicals) (WAEC)

Sets

Surds (radicals)

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Pergunta 45 Relatório

Evaluate Cos 45^o Cos 30^o - Sin 45^o Sin 30^o leaving the answer in surd form

$\frac{\sqrt{2}-1}{2}$

$\frac{\sqrt{3}-\sqrt{2}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{2}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$ Resposta correta

Detalhes da Resposta

Ler a nota de aula em Angles Of Elevation And Depression (WAEC)

Angles Of Elevation And Depression

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Pergunta 46 Relatório

A student bought 3 notebooks and 1 pen for N35. After misplacing these items, she again bought 2 notebooks and 2 pens, all of the same type for
N30. What is the cost of a pen?

N5.00 Resposta correta

N7.50

N10.00

N15.00

Detalhes da Resposta

Let the cost of a notebook be N and the cost of a pen be P. From the first transaction, we have: 3N + 1P = 35 ...(1) From the second transaction, we have: 2N + 2P = 30 ...(2) We want to find the value of P. We can rearrange equation (2) as follows: 2P = 30 - 2N P = (30 - 2N)/2 Substituting this value of P into equation (1), we get: 3N + 1[(30 - 2N)/2] = 35 Multiplying both sides by 2, we get: 6N + (30 - 2N) = 70 Simplifying the expression, we get: 4N = 40 N = 10 Substituting this value of N into equation (2), we get: 2(10) + 2P = 30 Simplifying the expression, we get: 2P = 10 P = 5 Therefore, the cost of a pen is N5.00. Answer: N5.00

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WAEC SSCE - General Mathematics - 2003 (Objective)