JAMB UTME - Physics - 2010 | Green Bridge CBT

Pergunta 1 Relatório

A cell of e.m.f 12V and internal resistance 4Ω is connected to an external resistor of resistance 2Ω. Find the current flow.

5 A

4 A

3 A

2 A

Detalhes da Resposta

The current flow can be found using Ohm's Law, which states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. First, we can find the total resistance of the circuit by adding the external resistor to the internal resistance of the cell: total resistance = external resistance + internal resistance = 2Ω + 4Ω = 6Ω Next, we can use Ohm's Law to find the current flow: current = voltage / resistance current = 12V / 6Ω = 2A Therefore, the current flow in the circuit is 2A. Answer: 2 A






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340	=	V2
√289	=	√400

∴ V2 =	340√400
	_√289