WAEC SSCE - Physics - 1998 (Objective)

Vraag 1 Verslag

a ball of mass 5.0kg hits a smooth vertical wall normally with a speed of 2m^-1 and rebounds with the same speed. Determine the impulse experienced by the ball

20.0kgm^-1 Juist antwoord

5.0kgm^-1

1.3kgm^-1

0.0kgm^-1

10.0kgm^-1

Antwoorddetails

The impulse experienced by an object is equal to the change in momentum of the object. Momentum is defined as the product of mass and velocity, i.e., p=mv. When the ball hits the wall, it experiences an impulse that causes a change in its momentum. Initially, the ball is moving towards the wall with a velocity of 2m/s, and the velocity changes direction after the collision, so the final velocity is -2m/s. The change in velocity, Δv = (-2) - (2) = -4m/s. Using the formula for impulse, J = Δp = mΔv, we can calculate the impulse experienced by the ball: J = 5.0kg × (-4m/s) = -20.0kgm/s. Therefore, the impulse experienced by the ball is 20.0 kgm/s. Note that the negative sign indicates that the impulse is in the opposite direction to the initial velocity of the ball.






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