Mathematics - Additional - 0606 CIE

Kinematics

Gbogbo ọrọ náà

Calculus describes motion exactly. Differentiating a displacement gives velocity, and differentiating velocity gives acceleration; integrating reverses each step. The area under a velocity-time graph is the distance travelled.

In this lesson you will apply differentiation and integration to kinematics problems involving displacement, velocity and acceleration, and draw and use the related motion graphs.

Ebumnobi

Apply differentiation and integration to kinematics problems involving the displacement, velocity and acceleration of a particle moving in a straight line.
Draw and use displacement-time, velocity-time and acceleration-time graphs.

Akọmọ Ojú-ẹkọ

Kinematics is calculus made physical: it is how the motion of vehicles, projectiles and machines is analysed and predicted.

Ọ dị na ngwa Green Bridge

Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.

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Ayẹwo Ẹkọ

Ekele diri gi maka imecha ihe karịrị na Kinematics. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.

Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.

Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.

To get velocity from displacement you: A. integrate B. differentiate C. square D. add a constant Answer: B
Acceleration is the rate of change of: A. displacement B. velocity C. distance D. time Answer: B
The area under a velocity-time graph gives the: A. acceleration B. distance travelled C. speed D. time Answer: B
If s = 3t^3 - 10t^2 + 4t, then v at general t is: A. 9t^2 - 20t + 4 B. 6t - 10 C. 9t^2 - 20t D. 3t^2 - 10t Answer: A
The gradient of a velocity-time graph gives the: A. distance B. displacement C. acceleration D. speed Answer: C