Sciences - Co-ordinated (9-1) - 0973 CIE

Electrical Quantities Continued

Gbogbo ọrọ náà

Every time you switch on a light, charge is pushed around a circuit by a source, gives up energy in the bulb, and returns for more. The push is the electromotive force, the energy given up per coulomb is the potential difference, and the opposition to the flow is the resistance. Master these three and you can analyse and cost almost any circuit.

In this topic you will define e.m.f. and potential difference, use voltmeters, measure and calculate resistance, and link power and energy to current and voltage. You will sketch the current-voltage graphs of a resistor, a lamp and a diode, and learn to work out the cost of running appliances in kilowatt-hours.

Ebumnobi

  1. Define electromotive force (e.m.f.) as the electrical work done by a source in moving a unit charge around a complete circuit
  2. Know that e.m.f. is measured in volts (V)
  3. Define potential difference (p.d.) as the work done by a unit charge passing through a component
  4. Know that the p.d. between two points is measured in volts (V)
  5. Describe the use of voltmeters (analogue and digital) with different ranges
  6. Recall and use the equation for resistance V R = I
  7. Describe an experiment to determine resistance using a voltmeter and an ammeter and do the appropriate calculations
  8. State, qualitatively, the relationship of the resistance of a metallic wire to its length and to its cross-sectional area
  9. Understand that electric circuits transfer energy from a source of electrical energy, such as an electrical cell or mains supply, to the circuit components and then into the surroundings
  10. Recall and use the equation for electrical power P = IV
  11. Recall and use the equation for electrical energy E = IVt
  12. Define the kilowatt-hour (kW h) and calculate the cost of using electrical appliances where the energy unit is the kW h
  13. [Supplement] Recall and use the equation for e.m.f. W E = Q
  14. [Supplement] Recall and use the equation for p.d. W V = Q
  15. [Supplement] Sketch and explain the current-voltage graphs for a resistor of constant resistance, a filament lamp and a diode
  16. [Supplement] Recall and use the following relationship for a metallic electrical conductor: (a) resistance is directly proportional to length (b) r esistance is inversely proportional to cross-sectional area

Akọmọ Ojú-ẹkọ

Electrical quantities run through every device and every electricity bill. Engineers size wires, rate appliances and design circuits using exactly these equations. In the exam this topic is rich in marks: definitions, graph sketches, and a string of calculations for resistance, power, energy and cost.

Ọ dị na ngwa Green Bridge

Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.

Akwụkwọ ndụmọdụ zuru oke nwere eserese
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Mụọ n'ụzọ na-enweghị ịntaneti, oge ọbụla, ebe ọbụla
Ọ dị na Android, Windows, macOS, na Linux

Ayẹwo Ẹkọ

Ekele diri gi maka imecha ihe karịrị na Electrical Quantities Continued. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.

Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.

Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.

  1. The resistance of a component carrying 2 A with 12 V across it is: A. 24 ohm B. 6 ohm C. 0.17 ohm D. 10 ohm Answer: B
  2. A voltmeter should be connected: A. in series with the component B. in parallel with the component C. before the cell only D. it does not matter Answer: B
  3. The I-V graph of a resistor of constant resistance is: A. a curve flattening off B. a straight line through the origin C. zero one way only D. a horizontal line Answer: B
  4. A 60 W lamp runs for 1 hour. The energy used is: A. 60 J B. 0.06 kW h C. 60 kW h D. 3600 kW h Answer: B
  5. 1 kilowatt-hour is equal to: A. 1000 J B. 3600 J C. 3.6 MJ D. 60 J Answer: C

Ọ dị na ngwa Green Bridge

Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.

Akwụkwọ ndụmọdụ zuru oke nwere eserese
Onye inyeaka mmụta AI
Mụọ n'ụzọ na-enweghị ịntaneti, oge ọbụla, ebe ọbụla
Ọ dị na Android, Windows, macOS, na Linux

Ọ dị na ngwa Green Bridge

Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.

Akwụkwọ ndụmọdụ zuru oke nwere eserese
Onye inyeaka mmụta AI
Mụọ n'ụzọ na-enweghị ịntaneti, oge ọbụla, ebe ọbụla
Ọ dị na Android, Windows, macOS, na Linux

Meecha Ajụjụ Ule Ọmarịcha

Ị chọrọ ime ajụjụ ule ọmarịcha gbasara Electrical Quantities Continued? Budata ngwa Green Bridge CBT iji nweta ajụjụ ule ọmarịcha na nyocha zuru ezu gbasara isiokwu a.

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