Modulus Equations
Gbogbo ọrọ náà
The modulus, or absolute value, of a number is its distance from zero, so it is never negative. That single idea, distance, is the key to solving every modulus equation. Strip away the bars and you are left with two ordinary equations to consider, one for each sign.
In this lesson you will solve equations of the form \(|ax+b|=c\), \(|ax+b|=cx+d\) and \(|ax+b|=|cx+d|\). The guiding rule is simple: if \(|\text{something}|=c\) then that something is \(+c\) or \(-c\). You will also learn the vital habit of checking your solutions, because the modulus can quietly create answers that do not work.
Ebumnobi
- Solve equations involving the modulus, such as |ax + b| = c, |ax + b| = cx + d and |ax + b| = |cx + d|, using algebraic or graphical methods.
Akọmọ Ojú-ẹkọ
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Ayẹwo Ẹkọ
Ekele diri gi maka imecha ihe karịrị na Modulus Equations. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.
Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.
Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.
- Solve |2x - 1| = 5. A. x = 3 or x = -2 B. x = 2 or x = -3 C. x = 3 only D. x = -2 only Answer: A
- The equation |A| = c (with c >= 0) is equivalent to: A. A = c only B. A = c or A = -c C. A = -c only D. A = 0 Answer: B
- Which value is never possible for |x|? A. 0 B. 5 C. -3 D. 2.5 Answer: C
- Solve |x - 1| = |2x + 1|. A. x = -2 or x = 0 B. x = 2 or x = 0 C. x = 1 or x = -1 D. x = -2 only Answer: A
- When solving |x - 2| = 2x - 7, x = 3 is rejected because: A. it does not solve case 2 B. it makes the right-hand side negative C. it makes |x - 2| negative D. it is not an integer Answer: B
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Àwọn Ìwé Tó Dáa Láti Kà
Meecha Ajụjụ Ule Ọmarịcha
Ị chọrọ ime ajụjụ ule ọmarịcha gbasara Modulus Equations? Budata ngwa Green Bridge CBT iji nweta ajụjụ ule ọmarịcha na nyocha zuru ezu gbasara isiokwu a.
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