Differentiating Products And Quotients
Gbogbo ọrọ náà
You can differentiate simple powers, but real functions are often built by multiplying or dividing two expressions together. To differentiate these you need two new tools: the product rule and the quotient rule. They are the natural next step once basic differentiation is secure.
In this lesson you will learn the product rule \((uv)'=u'v+uv'\) and the quotient rule \(\left(\frac{u}{v}\right)'=\frac{u'v-uv'}{v^2}\), and apply them to worked examples. The key skill is identifying the two pieces, differentiating each, and assembling the result in the correct order, especially the subtraction in the quotient rule.
Ebumnobi
- Differentiate products and quotients of functions.
Akọmọ Ojú-ẹkọ
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Ayẹwo Ẹkọ
Ekele diri gi maka imecha ihe karịrị na Differentiating Products And Quotients. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.
Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.
Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.
- The product rule for y = uv states that dy/dx equals: A. u'v' B. u'v + uv' C. u'v - uv' D. (u'v - uv')/v^2 Answer: B
- The quotient rule for y = u/v states that dy/dx equals: A. (u'v + uv')/v^2 B. (u'v - uv')/v^2 C. (uv' - u'v)/v^2 D. u'/v' Answer: B
- Differentiate y = x^2(2x + 1). A. 4x + 1 B. 6x^2 + 2x C. 2x^2 + 2x D. 6x^2 + 1 Answer: B
- Differentiate y = x/(x + 1). A. 1 B. 1/(x + 1) C. 1/(x + 1)^2 D. x/(x + 1)^2 Answer: C
- In the quotient rule, the denominator of the result is: A. v B. v^2 C. u^2 D. uv Answer: B
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Àwọn Ìwé Tó Dáa Láti Kà
Meecha Ajụjụ Ule Ọmarịcha
Ị chọrọ ime ajụjụ ule ọmarịcha gbasara Differentiating Products And Quotients? Budata ngwa Green Bridge CBT iji nweta ajụjụ ule ọmarịcha na nyocha zuru ezu gbasara isiokwu a.
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