Linear Law (straight-line Form)
Gbogbo ọrọ náà
Experimental data rarely falls on a straight line, but a clever change of variables can often make it do so. By taking logarithms, a power law or an exponential law can be straightened into the form \(Y=mX+c\). Then the gradient and intercept of the straight-line graph hand you the unknown constants.
In this lesson you will convert relationships such as \(y=Ax^n\) and \(y=Ab^x\) into straight-line form by taking logarithms, identify what to plot, and read off the constants from the gradient and intercept. This is the bridge between curved real-world data and the simple line you know how to analyse.
Ebumnobi
- Transform given relationships, such as y = Ax to the power n and y = Ab to the power x, to and from straight-line form.
- Determine unknown constants by calculating the gradient or intercept of the transformed straight-line graph.
Akọmọ Ojú-ẹkọ
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Ayẹwo Ẹkọ
Ekele diri gi maka imecha ihe karịrị na Linear Law (straight-line Form). Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.
Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.
Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.
- To straighten y = Ax^n, you plot: A. y against x B. lg y against lg x C. lg y against x D. y against lg x Answer: B
- To straighten y = Ab^x, you plot: A. lg y against lg x B. lg y against x C. y against x D. y against lg x Answer: B
- Taking logs of y = Ax^n gives: A. lg y = n lg x + lg A B. lg y = A lg x + n C. lg y = lg x + n lg A D. y = n lg x + A Answer: A
- If lg y against lg x has gradient 3 and intercept 0.7 for y = Ax^n, then n is: A. 0.7 B. 3 C. 10^0.7 D. 0.3 Answer: B
- If the intercept of the straight-line graph is lg A = 1, then A equals: A. 1 B. 10 C. 0.1 D. 100 Answer: B
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Ọ dị na ngwa Green Bridge
Budata ngwa Green Bridge CBT na ekwentị maọbụ kọmputa gị iji nweta akwụkwọ ndụmọdụ zuru oke, ajụjụ mmụta, na ndị ọzọ.
Àwọn Ìwé Tó Dáa Láti Kà
Meecha Ajụjụ Ule Ọmarịcha
Ị chọrọ ime ajụjụ ule ọmarịcha gbasara Linear Law (straight-line Form)? Budata ngwa Green Bridge CBT iji nweta ajụjụ ule ọmarịcha na nyocha zuru ezu gbasara isiokwu a.
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