CORE Chemistry (Short Course) - 9222 OxfordAQA

Use Of Amount Of Substance In Relation To Masses Of Pure Substances

Gbogbo ọrọ náà

Two sacks stand side by side in a farm supply store. They hold the same mass, they cost the same money, and both are sold as nitrogen fertiliser. One of them will put more than twice as much nitrogen into the soil as the other, and nothing on the outside of either sack tells you which. The only way to find out is to read the chemical formula and do about ninety seconds of arithmetic. That arithmetic is what this lesson is about, and it is the single most useful piece of number work in the whole of chemistry.

You will start by learning to add up a formula, turning a string of symbols and subscripts into one number that stands for the mass of the whole unit. From there you will work out what fraction of a compound is the element you actually care about, which is how a farmer chooses between two sacks and how a mining company decides whether an ore is worth digging out of the ground. Then you will take that fraction off the page and put it to work on a real mass, turning a percentage into tonnes of metal or kilograms of nutrient. Three steps, one balance, and no instrument more exotic than a calculator.

Ebumnobi

  1. The relative formula mass (Mr) of a compound is the sum of the relative atomic masses of the atoms in the numbers shown in the formula. Students are expected to use relative atomic masses in the calculations specified in the subject content. Students should be able to calculate the relative formula mass (Mr) of a compound from its formula.
  2. The percentage by mass of an element in a compound can be calculated from the relative atomic mass of the element in the formula and the relative formula mass of the compound.

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Akwụkwọ Ọmụmụ

A chemical formula looks like a label and behaves like an account book. Written out, NH4NO3 names a substance; read properly, it tells you exactly how the mass of that substance is shared out between nitrogen, hydrogen and oxygen, down to the last percent. Nothing else is needed to extract that information. No instrument, no experiment, no reference book beyond a periodic table. The formula already contains the answer and the arithmetic simply reads it out.

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Nnyocha Ọmụmụ

Ekele diri gi maka imecha ihe karịrị na Use Of Amount Of Substance In Relation To Masses Of Pure Substances. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.

Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.

Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.

  1. What is the relative formula mass of calcium carbonate, CaCO3? Relative atomic masses: C = 12, O = 16, Ca = 40. A. 68 B. 88 C. 100 D. 116 Answer: C
  2. What is the percentage by mass of oxygen in water, H2O? Relative atomic masses: H = 1, O = 16. A. 11.1 B. 16.0 C. 50.0 D. 88.9 Answer: D
  3. What is the relative formula mass of aluminium sulfate, Al2(SO4)3? Relative atomic masses: O = 16, Al = 27, S = 32. A. 123 B. 150 C. 278 D. 342 Answer: D
  4. What is the percentage by mass of sulfur in sulfur dioxide, SO2? Relative atomic masses: O = 16, S = 32. A. 20.0 B. 33.3 C. 50.0 D. 66.7 Answer: C
  5. A farmer spreads 30 kg of urea, CO(NH2)2, on a field. What mass of nitrogen does this supply? Relative atomic masses: H = 1, C = 12, N = 14, O = 16. A. 7.0 kg B. 12.5 kg C. 14.0 kg D. 28.0 kg Answer: C

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