Mathematics - Additional - 0606 CIE

Solving Exponential Equations

Gbogbo ọrọ náà

When the unknown sits in the exponent, ordinary algebra cannot reach it. Logarithms are the tool that brings it down to ground level. Taking the logarithm of both sides of \(a^x=b\) lets you slide the power out in front, turning an exponential equation into a linear one you can solve at once.

In this lesson you will solve equations like \(2^x=10\) by taking logarithms, using either base 10 or the natural logarithm. The key formula is \(x=\dfrac{\log b}{\log a}\), and you will see how it follows directly from the power law.

Ebumnobi

  1. Solve equations of the form a to the power x equals b.

Nkuzi Olu

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Maapụ uche

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Kaadị ncheta

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Akwụkwọ Ọmụmụ

Exponential equations describe doubling times, decay, interest and population change. To answer when does it reach a certain value, you must solve for an exponent, and logarithms are the only clean way to do it. This skill rests directly on the laws of logarithms you have just met.

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Nnyocha Ọmụmụ

Ekele diri gi maka imecha ihe karịrị na Solving Exponential Equations. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.

Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.

Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.

  1. To solve a^x = b, the first step is to: A. divide both sides by a B. take logarithms of both sides C. square both sides D. subtract b Answer: B
  2. Solving 2^x = 10 gives x equal to: A. log 2 / log 10 B. log 10 / log 2 C. log(10/2) D. 10/2 Answer: B
  3. To 2 decimal places, the solution of 2^x = 10 is: A. 2.32 B. 3.32 C. 5.00 D. 1.43 Answer: B
  4. Solve e^x = 7 (to 2 decimal places). A. 0.85 B. 1.95 C. 2.71 D. 7.00 Answer: B
  5. The step x log a = log b leads to x equal to: A. log b - log a B. log b / log a C. log(b - a) D. log a / log b Answer: B

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