Perpendicular Lines
Gbogbo ọrọ náà
Two lines are perpendicular when they meet at a right angle, and in coordinate geometry this gives a beautifully simple rule: their gradients multiply to give \(-1\). Knowing this lets you find the equation of a line at right angles to any given line.
In this lesson (Extended tier) you will find the gradient and equation of a straight line perpendicular to a given line, using the rule that perpendicular gradients multiply to \(-1\).
Ebumnobi
- Find the gradient and equation of a straight line perpendicular to a given line.
Nkuzi Olu
Gee ntị na nkuzi a na ngwa
Maapụ uche
E seela isiokwu a ka ị hụ otu echiche si ejikọta.
Mepee maapụ uche na ngwa
Kaadị ncheta
Omume ncheta ngwa ngwa n'ihe a na-anwale n'isiokwu a.
Mee omume kaadị ndị a na ngwa
Akwụkwọ Ọmụmụ
Ndetu Nkuzi Zuru Ezu di na Ngwa Green Bridge
Nweta ngwa Green Bridge CBT na ekwenti gi ma o bu kompiuta maka ulo akwukwo IGCSE zuru oke: akwukwo ule ndi gara aga, usoro nyocha, eserese uche, kaadi omumu na nkuzi olu.
Nnyocha Ọmụmụ
Ekele diri gi maka imecha ihe karịrị na Perpendicular Lines. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.
Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.
Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.
- What is true of the gradients of two perpendicular lines? A. They are equal B. They add to 0 C. They multiply to -1 D. One is always 0 Answer: C
- A line has gradient 2. The gradient of a perpendicular line is: A. 2 B. -2 C. 1/2 D. -1/2 Answer: D
- A line has gradient -3. The gradient of a perpendicular line is: A. 3 B. 1/3 C. -1/3 D. -3 Answer: B
- The line perpendicular to y = 2x + 1 through (0, 3) is: A. y = 2x + 3 B. y = -1/2 x + 3 C. y = -2x + 3 D. y = 1/2 x + 3 Answer: B
- The perpendicular gradient is found by taking the: A. same value B. negative C. reciprocal D. negative reciprocal Answer: D
Rue ajuju ndi a n'ime ngwa ahu
Rue ajuju ndi a n'ime ngwa ahu
Akwụkwọ A Na-atụ Aro
Mụtakwuo ihe site na isi mmalite mepere emepe
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Akụkụ akwụkwọ
Find the Equation of a Line
Find an equation of the line given the slope and y y -intercept
"Elementary Algebra: Find the Equation of a Line" by OpenStax, OpenStax, Rice University, licensed under CC BY 4.0 (https://creativecommons.org/licenses/by/4.0/). Source: https://openstax.org/books/elementary-algebra/pages/4-6-find-the-equation-of-a-line. Access for free at https://openstax.org/books/elementary-algebra/pages/1-introduction
Ndị otu ndị ọzọ bipụtara ha n'okpuru ikike mepere emepe, anyị na-ekele ha dị ka ha si chọọ. Njikọ na-emepe saịtị ha.
Meecha Ajụjụ Ule Ọmarịcha
Ị chọrọ ime ajụjụ ule ọmarịcha gbasara Perpendicular Lines? Budata ngwa Green Bridge CBT iji nweta ajụjụ ule ọmarịcha na nyocha zuru ezu gbasara isiokwu a.
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Ihe nile ichoro iji nwee ihe ịga nke ọma na JAMB, WAEC & NECO.
