Mathematics - Additional - 0606 CIE

Completing The Square And The Vertex

Gbogbo ọrọ náà

Completing the square rewrites a quadratic so that its turning point is visible at a glance. From the rewritten form you can read off the maximum or minimum value and the line of symmetry without any further work.

In this lesson you will find the maximum or minimum value of a quadratic by completing the square, and use it to sketch the graph or find the range for a given domain.

Ebumnobi

  1. Find the maximum or minimum value of a quadratic function by completing the square or by differentiation.
  2. Use the maximum or minimum value to sketch the graph of the function or to determine its range for a given domain.

Nkuzi Olu

Gee ntị na nkuzi a na ngwa

Maapụ uche

E seela isiokwu a ka ị hụ otu echiche si ejikọta.

Mepee maapụ uche na ngwa

Kaadị ncheta

Omume ncheta ngwa ngwa n'ihe a na-anwale n'isiokwu a.

Mee omume kaadị ndị a na ngwa

Akwụkwọ Ọmụmụ

The completed-square form instantly gives the vertex and range of a quadratic, which is central to graph sketching and optimisation.

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Nnyocha Ọmụmụ

Ekele diri gi maka imecha ihe karịrị na Completing The Square And The Vertex. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.

Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.

Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.

  1. Complete the square: x^2 - 4x + 1 = A. (x - 2)^2 - 3 B. (x - 2)^2 + 1 C. (x - 4)^2 - 3 D. (x + 2)^2 - 3 Answer: A
  2. The vertex of y = (x - 2)^2 - 3 is: A. (2, 3) B. (2, -3) C. (-2, -3) D. (-2, 3) Answer: B
  3. For y = (x - 2)^2 - 3, the minimum value is: A. 2 B. -2 C. -3 D. 3 Answer: C
  4. In a(x - h)^2 + k, the vertex is a maximum when: A. a > 0 B. a < 0 C. a = 0 D. k > 0 Answer: B
  5. The line of symmetry of y = (x - 2)^2 - 3 is: A. x = -2 B. x = 2 C. y = -3 D. x = 3 Answer: B

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