Tangents To A Circle
Gbogbo ọrọ náà
A tangent just grazes a circle, touching it at a single point. There is one beautiful fact that makes every tangent question solvable: the tangent is perpendicular to the radius drawn to the point where they touch. That right angle is the key that unlocks the equation of the tangent.
In this lesson you will use the radius-tangent right angle, together with the gradient rules you already know, to find the equation of a tangent at a given point on a circle, without any calculus. Find the gradient of the radius, take its negative reciprocal, and you have the gradient of the tangent.
Ebumnobi
- Solve problems involving tangents to a circle, including finding the equations of tangents (no use of calculus is expected).
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Maapụ uche
E seela isiokwu a ka ị hụ otu echiche si ejikọta.
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Mee omume kaadị ndị a na ngwa
Akwụkwọ Ọmụmụ
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Nweta ngwa Green Bridge CBT na ekwenti gi ma o bu kompiuta maka ulo akwukwo IGCSE zuru oke: akwukwo ule ndi gara aga, usoro nyocha, eserese uche, kaadi omumu na nkuzi olu.
Nnyocha Ọmụmụ
Ekele diri gi maka imecha ihe karịrị na Tangents To A Circle. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.
Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.
Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.
- A tangent to a circle is perpendicular to which line at the point of contact? A. The diameter through the centre only B. The radius at that point C. Any chord D. The x-axis Answer: B
- A circle has centre O(0,0) and passes through P(3,4). What is the gradient of the radius OP? A. 3/4 B. 4/3 C. -3/4 D. -4/3 Answer: B
- For the same circle, what is the gradient of the tangent at P(3,4)? A. 4/3 B. 3/4 C. -3/4 D. -4/3 Answer: C
- The equation of the tangent at P(3,4) to the circle centre O(0,0) is: A. y = (4/3)x B. y = -(3/4)x + 25/4 C. y = (3/4)x + 4 D. y = -(4/3)x + 8 Answer: B
- A circle has centre C(1,2) and passes through P(4,6). The tangent gradient at P is: A. 4/3 B. 3/4 C. -3/4 D. -4/3 Answer: C
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Ị chọrọ ime ajụjụ ule ọmarịcha gbasara Tangents To A Circle? Budata ngwa Green Bridge CBT iji nweta ajụjụ ule ọmarịcha na nyocha zuru ezu gbasara isiokwu a.
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