Mathematics - Additional - 0606 CIE

Simultaneous Equations

Gbogbo ọrọ náà

Solving two linear equations together is familiar ground. Now one of the equations becomes non-linear, perhaps a curve such as a circle or a parabola. Geometrically you are finding where a straight line meets a curve, and there can be two crossing points, one (a tangent) or none.

In this lesson you will learn the reliable substitution method: rearrange the linear equation, substitute it into the non-linear one, and solve the quadratic that results. The classic example, a line meeting a circle, shows the whole process and connects neatly to coordinate geometry.

Ebumnobi

  1. Solve simultaneous equations in two unknowns by elimination or substitution, including cases with one linear and one non-linear equation.

Nkuzi Olu

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Maapụ uche

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Kaadị ncheta

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Akwụkwọ Ọmụmụ

Whenever a straight-line relationship meets a curved one, you are solving a linear and a non-linear equation together: a supply line crossing a demand curve, a path meeting a boundary, a sightline touching a circle. The substitution method here is the workhorse for all such problems and feeds directly into the circle-and-line topics later in the course.

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Nnyocha Ọmụmụ

Ekele diri gi maka imecha ihe karịrị na Simultaneous Equations. Ugbu a na ị na-enyochakwa isi echiche na echiche ndị dị mkpa, ọ bụ oge iji nwalee ihe ị ma. Ngwa a na-enye ụdị ajụjụ ọmụmụ dị iche iche emebere iji kwado nghọta gị wee nyere gị aka ịmata otú ị ghọtara ihe ndị a kụziri.

Ị ga-ahụ ngwakọta nke ụdị ajụjụ dị iche iche, gụnyere ajụjụ chọrọ ịhọrọ otu n’ime ọtụtụ azịza, ajụjụ chọrọ mkpirisi azịza, na ajụjụ ede ede. A na-arụpụta ajụjụ ọ bụla nke ọma iji nwalee akụkụ dị iche iche nke ihe ọmụma gị na nkà nke ịtụgharị uche.

Jiri akụkụ a nke nyocha ka ohere iji kụziere ihe ị matara banyere isiokwu ahụ ma chọpụta ebe ọ bụla ị nwere ike ịchọ ọmụmụ ihe ọzọ. Ekwela ka nsogbu ọ bụla ị na-eche ihu mee ka ị daa mba; kama, lee ha anya dị ka ohere maka ịzụlite onwe gị na imeziwanye.

  1. Solving y = x + 1 and x^2 + y^2 = 25 leads to which quadratic in x? A. x^2 + x - 12 = 0 B. x^2 - x - 12 = 0 C. 2x^2 + 25 = 0 D. x^2 + 1 = 25 Answer: A
  2. The points of intersection of y = x + 1 and x^2 + y^2 = 25 are: A. (4, 5) and (-3, -2) B. (-4, -3) and (3, 4) C. (0, 1) and (5, 6) D. (3, -4) and (-4, 3) Answer: B
  3. To solve one linear and one non-linear equation, the best first step is to: A. Add the two equations B. Square the linear equation C. Substitute the linear equation into the non-linear one D. Multiply the equations Answer: C
  4. Solving y = 2x - 1 and y = x^2 - 4 gives the x-values: A. 3 and -1 B. 1 and -3 C. 2 and -2 D. 4 and -1 Answer: A
  5. If a line meets a curve at exactly one point, the line is: A. A chord B. A tangent C. Parallel to an axis D. Outside the curve Answer: B

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Ị chọrọ ime ajụjụ ule ọmarịcha gbasara Simultaneous Equations? Budata ngwa Green Bridge CBT iji nweta ajụjụ ule ọmarịcha na nyocha zuru ezu gbasara isiokwu a.

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