JAMB UTME - Physics - 1987
Ajụjụ 1 Ripọtì
Ajụjụ 2 Ripọtì
Akọwa Nkọwa
since, F = ma = kgms-1 = N
kgms-1 = Ns
Ajụjụ 4 Ripọtì
Ajụjụ 5 Ripọtì
Akọwa Nkọwa
20 = 60×V60+V
V = 30cm
similarly, UV = height of objectheight of image
6030 = 3h
h = 1.5cm
Ajụjụ 7 Ripọtì
What type of reaction is represented by the following scheme?
\[ {}^{2}_{1}X + {}^{2}_{1}Y + {}^{3}_{2}Z + {}^{1}_{0}n + \text{energy} \]Ajụjụ 8 Ripọtì
Akọwa Nkọwa
Ajụjụ 9 Ripọtì
The fig above represents the main sequence of energy conversion at Kainji dam. What is the efficiency of the system?
Akọwa Nkọwa
Ajụjụ 11 Ripọtì
Akọwa Nkọwa
Ajụjụ 12 Ripọtì
Akọwa Nkọwa
= 2 x 0.3
= 0.6ms-1
Ajụjụ 13 Ripọtì
Akọwa Nkọwa
K.E = 12 mv2 = 200m joules
%converted = 200m1000m x 100
= 20%
Ajụjụ 14 Ripọtì
A galvanometer of resistance \(20\,\Omega\) is to be provided with a shunt that \(\frac{1}{10}\) of the whole current in a circuit passes through the galvanometer. The resistance of the shunt is
Ajụjụ 15 Ripọtì
When the length I of a piece of wire under constant tension is varied, the relationship of the frequency of the vibration \( \alpha \)/ is
Akọwa Nkọwa
Ajụjụ 16 Ripọtì
Akọwa Nkọwa
Fm = (40 x 10 x sin 45) - (40 x 10 x 0.25 x cos 45)
= 212N
Ajụjụ 17 Ripọtì
Two capacitance of \(6\,\mu\text{F}\) and \(8\,\mu\text{F}\) are connected in series. What additional capacitance must be connected in series with this combination to give a total of \(3\,\mu\text{F}\)
Ajụjụ 18 Ripọtì
The velocity time graph above describes the motion of a particle between two points P and Q. What is the distance between P and Q?
Akọwa Nkọwa
Ajụjụ 19 Ripọtì
Ajụjụ 20 Ripọtì
A cube of side 10cm and mass 0.5kg floats in a liquid with only \( \frac{1}{5} \) of its height above the liquid surface. What is the relative density of the liquid?
Akọwa Nkọwa
volume of cube = 103cm3
volume of liquid displaced = 45 x 1000
= 800cm3
density of liquid displaced;
= 500800
= 0.625cm-1
Ajụjụ 21 Ripọtì
Akọwa Nkọwa
= (0 x 4) + (12 x 0.1 x 4 x 4)
= 0.8m
workdone = force x distance
= 40 x 0.8
= 32J
Ajụjụ 22 Ripọtì
Ajụjụ 23 Ripọtì
Akọwa Nkọwa
Ajụjụ 24 Ripọtì
Akọwa Nkọwa
F1 = 3Fo
= 3 x 40 = 120Hz
F2 = 5Fo
= 5 x 40
= 200Hz
Ajụjụ 25 Ripọtì
Akọwa Nkọwa
Ajụjụ 26 Ripọtì
Akọwa Nkọwa
Ajụjụ 29 Ripọtì
Akọwa Nkọwa
= (2 x 333000) + (2 x 2090 x 2)
= 674 360J
Ajụjụ 30 Ripọtì
Akọwa Nkọwa
3 x 4 x 10-5 = V2−125125×(120−20)
V2 = 126.50cm3
Ajụjụ 31 Ripọtì
A 50kg block is dropped from a point 10cm above as shown in the fig above. if the force constant of the spring is 4.0 x 104Nm-1, find the maximum compression of the spring [g = 10ms-2]
Ajụjụ 32 Ripọtì
Akọwa Nkọwa
1.33 = real depth1
real depth = 1.33cm
Ajụjụ 33 Ripọtì
Akọwa Nkọwa
Ajụjụ 34 Ripọtì
Akọwa Nkọwa
= 0.5 x 40 x 2 x 60
= 2400J
Ajụjụ 35 Ripọtì
Akọwa Nkọwa
= 60000−(4800×10)4800
= 2.5ms-2
Ajụjụ 36 Ripọtì
Ajụjụ 38 Ripọtì
Ajụjụ 39 Ripọtì
Akọwa Nkọwa
thrust = m(v−u)t x t1
270 = m(300 - 0)
m = 0.90kg
Ajụjụ 40 Ripọtì
Akọwa Nkọwa
Ajụjụ 41 Ripọtì
Akọwa Nkọwa
4.5cm .... θ
0cm ....0oC
4.5−020−0 = 0−0100−0
θ = 22.5oC
Ajụjụ 42 Ripọtì
Ajụjụ 43 Ripọtì
Akọwa Nkọwa
mh x ch x θ h = mc x cc x θ c
mh x ch x (θ - 20) = mc x cc x (20 - 10)
ch = cc ; mc = 3mh
therefore, θ = 50oC
Ajụjụ 44 Ripọtì
In the figure above, M and N are insulated metal spheres in contact. A negatively charged ebonite rod P is I brought near M. When M and N are Separated and the rod is taken away, which of the following statements is correct
Akọwa Nkọwa
Ajụjụ 45 Ripọtì
Akọwa Nkọwa
R = √129
= 11.36km
Ajụjụ 46 Ripọtì
Akọwa Nkọwa
(75 - 73.5) x 8 = (X - 74) x 6
X = 76cm
Ajụjụ 47 Ripọtì
The fig above shows two connected bodies of masses M1 and M2 in equilibrium under gravity. The tension in the upper string is
Ajụjụ 48 Ripọtì
