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Ajụjụ 1 Ripọtì
Calculate the quantity of heat for copper rod whose thermal capacity is 400Jk−1 for a temperature change of 60ºC to 80ºC
Akọwa Nkọwa
To calculate the quantity of heat absorbed or released by a substance, we can use the formula:
Q = C × ΔT
where:
Given:
First, calculate the change in temperature:
ΔT = Final temperature - Initial temperature = 80°C - 60°C = 20°C
Now, substitute the values into the formula to find the quantity of heat:
Q = 400 J/°C × 20°C
Calculate the answer:
Q = 8000 J
Since the options provided are in kilojoules (KJ), we need to convert joules (J) to kilojoules (1 KJ = 1000 J):
Q = 8000 J ÷ 1000 = 8 KJ
Therefore, the quantity of heat for the copper rod, given the specified conditions, is 8 KJ.
Ajụjụ 2 Ripọtì
Two tuning forks of frequencies 6Hz and 4Hz respectively are sounded together. The beat frequency is
Akọwa Nkọwa
When two sound waves of slightly different frequencies are sounded together, they interfere with each other in such a way that the intensity of the sound alternates between loud and soft. This phenomenon is known as "beats". The number of beats heard per second is called the "beat frequency".
The beat frequency can be calculated by subtracting the frequency of one wave from the frequency of the other. Mathematically, it is represented as:
Beat Frequency (fbeat) = | f1 - f2 |
Where:
In this case:
Using the formula:
fbeat = | 6Hz - 4Hz | = | 2Hz | = 2Hz
Therefore, the beat frequency is 2Hz. This means that you would hear 2 beats per second when the tuning forks of frequencies 6Hz and 4Hz are sounded together.
Ajụjụ 3 Ripọtì
The mechanical advantage of the machine shown above
Akọwa Nkọwa
Mechanical advantage of a machine = LOADEFFORT
In this case of a wedge, we can consider the dimensions given:
Load distance (height of the machine): 15 cm
Effort distance (movement of the effort): 0.5 cm
M.A = 150.5 = 30.0
Ajụjụ 4 Ripọtì
The simple form of the lead acid accumulator often has a negative pole of
Akọwa Nkọwa
The simple form of the lead acid accumulator often has a negative pole of lead plate. In a lead-acid battery, the key components include two electrodes and an electrolyte. The **negative pole**, also known as the cathode during discharge, is typically made of **lead (Pb)**, which is in the form of a **lead plate**. When the battery is in use or discharging, this lead reacts with sulphuric acid (the electrolyte) to create lead sulfate.
To break it down further:
Thus, by analyzing the composition and reactions within a lead-acid battery, it is clear that the **negative pole** is made from a **lead plate**.
Ajụjụ 5 Ripọtì
Mouth part adapted for piercing and sucking is found in
Akọwa Nkọwa
The mouthpart adapted for piercing and sucking is found in the mosquito. Mosquitoes have a specialized mouth structure called a proboscis. This proboscis is long and slender, allowing mosquitoes to puncture the skin of their hosts and suck blood. The proboscis is a complex structure that contains several needle-like parts that make the piercing and sucking process efficient and effective.
Ajụjụ 6 Ripọtì
The fourth overtone of a closed pipes is 900Hz, its fundamental frequency is
Akọwa Nkọwa
To solve this problem, let's first understand how sound works in a closed pipe. A closed pipe has one end closed and another end open. Sound waves inside such a pipe create standing waves, where nodes (points of no movement) and antinodes (points of maximum movement) are formed.
For a closed pipe, the fundamental frequency (also called the first harmonic) has one node at the closed end and one antinode at the open end. The wavelength is four times the length of the pipe.
The overtone sequence for a closed pipe includes only odd harmonics: 1st (fundamental), 3rd, 5th, 7th, etc. The nth overtone is the 2nth + 1 harmonic. The equation for the frequency of a harmonic in a closed pipe is:
f_n = n * f_1, where f_n is the frequency of the nth harmonic and f_1 is the fundamental frequency
In this case, the fourth overtone corresponds to the 9th harmonic because 2 * 4 + 1 = 9. Therefore, we have:
900 Hz = 9 * f_1
To find the fundamental frequency (f_1), we solve for f_1:
f_1 = 900 Hz / 9
f_1 = 100 Hz
Therefore, the fundamental frequency is 100 Hz.
Ajụjụ 7 Ripọtì
In a solar panel, solar beam is concentrated by using
Akọwa Nkọwa
In a solar panel system, the type of mirror used to concentrate solar beams is the Concave Mirror.
Explanation:
A concave mirror is a type of mirror that curves inward, like the inside of a bowl. This shape is very effective at focusing light. When sunlight hits a concave mirror, the mirror's shape causes the light beams to converge, or come together, at a single point known as the focus. This concentrated light can then be used to generate heat or electricity more efficiently.
Why not the others?
A convex mirror curves outward and disperses light beams rather than concentrating them.
A plane mirror has a flat surface and reflects light at the same angle it receives it, meaning it doesn't concentrate the beams.
A triangular mirror is not typically used in solar applications for concentrating light as its shape is not conducive to focusing beams effectively.
Therefore, a concave mirror is best suited for concentrating solar beams in solar panel systems.
Ajụjụ 8 Ripọtì
When a charged ebonite rod is brought near a charged glass rod, there will be
Akọwa Nkọwa
When a charged ebonite rod is brought near a charged glass rod, there will be attraction. This is because charged objects obey the fundamental principle of electrostatics, which states that opposite charges attract each other while like charges repel each other.
An ebonite rod typically acquires a negative charge when rubbed with fur, as it gains electrons. In contrast, a glass rod usually acquires a positive charge when rubbed with silk, as it loses electrons. Therefore, when these two objects, one negatively charged and the other positively charged, are brought near each other, the opposite charges will attract.
Ajụjụ 9 Ripọtì
Infra-red thermometers work by detecting the
Akọwa Nkọwa
Infra-red thermometers work by detecting the radiation from the body and converting it to temperature. These thermometers are designed to measure the infrared radiation, also known as heat radiation, emitted by objects. All objects with a temperature above absolute zero emit infrared radiation. The thermometer's sensor captures this radiation and converts it into an electrical signal that can be read as a temperature measurement. This method allows for quick, non-contact temperature readings, which is why infrared thermometers are often used in medical settings, industrial applications, and more.
Ajụjụ 10 Ripọtì
A cell of internal resistance of 2Ω supplies current through a resistor, X if the efficiency of the cell is 75%, find the value of X.
Akọwa Nkọwa
To solve the problem, let's first understand the concept of efficiency in this context. Efficiency refers to the ratio of the useful power output to the total power output of a system. In simpler terms, it tells us how much of the power provided by the cell is being effectively used by the resistor, X.
Given that the cell has an internal resistance (r) of 2Ω and we need the efficiency to be 75%, we will follow these steps:
Efficiency (%) = (R / (R + r)) * 100
Where:
According to the problem, efficiency is 75%, so:
(X / (X + 2)) * 100 = 75
First, let’s eliminate the percentage by dividing both sides by 100:
(X / (X + 2)) = 0.75
Now, let's solve for X:
X = 0.75 * (X + 2)
X = 0.75X + 1.5
0.25X = 1.5
X = 1.5 / 0.25
X = 6 Ω
Hence, for the cell to have an efficiency of 75%, the value of the resistor X must be 6Ω.
Ajụjụ 11 Ripọtì
Rainbow is formed when sunlight undergoes
Akọwa Nkọwa
A rainbow is formed through a combination of three processes: reflection, refraction, and dispersion. Let's break down each process to understand how a rainbow forms:
1. Refraction: When sunlight enters a raindrop, it bends or changes direction. This bending of light is known as **refraction**. Different colors of sunlight bend by different amounts because they have different wavelengths.
2. Reflection: Once inside the raindrop, the light gets reflected off the inside surface of the drop. This reflection sends the light back out of the raindrop at different angles.
3. Dispersion: As the light exits the raindrop, it bends again (refraction). Because each color bends by a different amount, the sunlight is spread out into its component colors, creating a spectrum. This spreading into a spectrum is called **dispersion**.
All three processes contribute to the formation of a rainbow. The combination of **refraction, reflection, and dispersion** results in the beautiful arc of colors that we see in the sky.
Ajụjụ 12 Ripọtì
A blacksmith heated a metal whose cubic expansivity is 3.9 x 10−6 K−1 . Calculate the area expansivity.
Akọwa Nkọwa
To find the area expansivity of a metal when given its cubic expansivity, you should understand the relationship between linear, area, and cubic expansivity.
Cubic expansivity (\( \beta \)) is defined as the fractional change in volume per change in temperature, and is given by the formula:
\[ \Delta V = \beta V \Delta T \]
Area expansivity (\( \alpha_{A} \)) corresponds to the fractional change in area per change in temperature and can be derived from the linear expansivity (\( \alpha \)). The relationship between these expansivities is as follows:
\[ \text{Area Expansivity (\( \alpha_{A} \))} = 2 \times \text{Linear Expansivity (\( \alpha \))} \]
The cubic expansivity (\( \beta \)) is related to the linear expansivity by:
\[ \text{Cubic Expansivity (\( \beta \))} = 3 \times \text{Linear Expansivity (\( \alpha \))} \]
Thus, based on these relationships, we can express the area expansivity in terms of the cubic expansivity:
\(\text{Area Expansivity (\( \alpha_{A} \))} = \frac{2}{3} \times \text{Cubic Expansivity (\( \beta \))}
Given that the cubic expansivity \( \beta \) is \( 3.9 \times 10^{-6} \, \text{K}^{-1} \):
The area expansivity can be calculated as follows:
\[ \text{Area Expansivity (\( \alpha_{A} \))} = \frac{2}{3} \times 3.9 \times 10^{-6} \, \text{K}^{-1} = 2.6 \times 10^{-6} \, \text{K}^{-1} \]
Therefore, the **correct answer** is **2.6 x 10^{-6} K^{-1}**.
Ajụjụ 13 Ripọtì
The food nutrient with the highest energy value is
Akọwa Nkọwa
Fat is the food nutrient with the highest energy value, providing 9 calories per gram, while carbohydrates and proteins provide 4 calories per gram.
Fat is the body's most concentrated source of energy, providing more than twice as much potential energy as carbohydrates or proteins.However, carbohydrates burn fastest in metabolism. Fats are a type of lipid. Lipids are a group of organic compounds that are insoluble in water but soluble in organic solvents. Fats are solid at room temperature, while oils are liquid at room temperature.
Therefore, the correct answer is option C.
Ajụjụ 14 Ripọtì
The process by which plants loss water to the atmosphere is
Akọwa Nkọwa
The process by which plants lose water to the atmosphere is called transpiration.
Transpiration is a fundamental process in the life of a plant. During this process, water is absorbed by the roots from the soil and is then transported through the xylem vessels in the stem and leaves. Once in the leaves, water evaporates into the atmosphere from the surface of tiny pores known as stomata.
Here's a simple breakdown of how transpiration works:
Transpiration is crucial for a number of reasons:
Understanding transpiration is essential in fields like agriculture, where managing water resources efficiently can significantly impact plant growth and crop yield.
Ajụjụ 15 Ripọtì
Photometer is used to measure
Akọwa Nkọwa
A photometer is an instrument designed to measure the intensity of light. It is used to determine how much light is received over a particular area. Photometers are vital in various fields such as photography, astronomy, and laboratory science for ensuring that light levels are appropriate for specific applications.
The device operates by assessing the brightness or illumination coming from a light source and comparing it with a standard light. The measurement can be displayed in different units such as lumens or lux, depending on the context of the measurement.
While photometers are focused on the intensity of light, they do not measure kinetic energy of liberated electrons, the frequency of light, or the wavelength of light. These quantities are measured using other specialized instruments, such as spectrometers or frequency analyzers.
Ajụjụ 16 Ripọtì
A sonometer's fundamental note is 50Hz, what is the new frequency when the tension is four times the original?
Akọwa Nkọwa
To solve this problem, we need to understand the relationship between tension and frequency in a sonometer wire. The frequency of a vibrating string, such as one in a sonometer, is directly proportional to the square root of the tension in the string. Mathematically, this relationship is expressed as:
f ∝ √T
Where f is the frequency and T is the tension. In the given problem, the original frequency is 50 Hz, and the tension is increased to four times its original value. Let's analyze how this change in tension affects the frequency:
- Original tension = T
- New tension = 4T
Substitute the new tension into the formula:
f_new = 50 Hz × √(4T/T)
Simplify the equation:
f_new = 50 Hz × √4
f_new = 50 Hz × 2
f_new = 100 Hz
Thus, when the tension is four times the original tension, the new frequency of the sonometer's fundamental note becomes 100 Hz.
Ajụjụ 17 Ripọtì
A boy standing 408m from a wall blew a trumpet and heard the echo 2.4s later. Calculate the speed of the sound
Akọwa Nkọwa
To calculate the speed of sound, we need to understand that an echo involves a sound wave traveling to a surface and back. In this case, the sound travels from the boy to the wall and then returns.
The total distance that the sound wave travels is twice the distance from the boy to the wall because it goes to the wall and back. Therefore, the total distance is:
Total Distance = 2 x 408m = 816m
The echo was heard 2.4 seconds after the sound was made. The speed of sound can be calculated using the formula:
Speed of Sound = Total Distance / Time
Plugging in the values, we have:
Speed of Sound = 816m / 2.4s
When you perform the division, you find:
Speed of Sound = 340 m/s
Thus, the speed of the sound is 340 m/s, which is the correct answer.
Ajụjụ 18 Ripọtì
A monochromatic light is one that
Akọwa Nkọwa
A monochromatic light is one that has a single wavelength or color. This means that it consists of light waves that all have the same frequency, resulting in a uniform appearance without any variation.
Ajụjụ 19 Ripọtì
The distance between two successive crests of a water wave is 0.25m. If a particle on the surface of the water makes four complete vertical oscillations in one second. Calculate the speed of the wave.
Akọwa Nkọwa
To calculate the speed of the wave, we need to understand some fundamental wave properties: **wavelength**, **frequency**, and **wave speed**.
1. **Wavelength (\( \lambda \))**: The wavelength is the distance between two successive crests of a wave. In this case, the wavelength is given as **0.25 meters**.
2. **Frequency (\( f \))**: Frequency is the number of complete oscillations or cycles that occur per second. It is given that a particle on the surface of the water makes **four complete vertical oscillations in one second**. So, the frequency is **4 Hz (hertz)**.
3. **Wave Speed (\( v \))**: The speed of a wave is calculated using the formula:
\( v = f \times \lambda \)
Where:
\( v \) is the wave speed,
\( f \) is the frequency, and
\( \lambda \) is the wavelength.
Substitute the given values into the formula:
\( v = 4 \text{ Hz} \times 0.25 \text{ m} \)
\( v = 1 \text{ m/s} \)
Therefore, the **speed of the wave** is 1 m/s.
Ajụjụ 20 Ripọtì
Two points on a velocity-time graph have coordinates (2s, 5m/s) and (4s, 15m/s). Calculate the mean acceleration
Akọwa Nkọwa
The mean acceleration of an object is determined by the change in velocity over the change in time. This is given by the formula:
Mean Acceleration (a) = (Final Velocity - Initial Velocity) / (Final Time - Initial Time)
From the velocity-time graph, we have the following points:
Initial Point: (2s, 5m/s)
Final Point: (4s, 15m/s)
Here, the Initial Velocity is 5m/s, the Final Velocity is 15m/s, the Initial Time is 2s, and the Final Time is 4s.
Plug these values into the formula:
Mean Acceleration (a) = (15m/s - 5m/s) / (4s - 2s)
Simplifying this, we get:
Mean Acceleration (a) = 10m/s / 2s = 5m/s²
The mean acceleration is therefore 5.0 m/s².
Ajụjụ 21 Ripọtì
The gravitational force between two objects is 10N, what is the new value of the force if the distance between them is halved?
Akọwa Nkọwa
The gravitational force between two objects is determined by Newton's Law of Universal Gravitation, which can be expressed by the formula:
F = G * (m1 * m2) / r²
where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the centers of the two objects.
In this problem, it is given that the initial gravitational force is 10N. According to the formula, the gravitational force is inversely proportional to the square of the distance between the two objects.
So, if the distance between the objects is halved (i.e., r becomes r/2), then the new gravitational force F' can be calculated based on the relationship:
F' = G * (m1 * m2) / (r/2)² = G * (m1 * m2) / (r²/4) = 4 * (G * m1 * m2 / r²) = 4 * F
Since the initial force F was 10N, the new force F' when the distance is halved is:
F' = 4 * 10 = 40N
Thus, the new value of the gravitational force is 40N.
Ajụjụ 22 Ripọtì
Calculate the depth of a swimming pool if the apparent depth is 10cm. ( Refractive index of water = 1.33 )
Akọwa Nkọwa
To calculate the real depth of a swimming pool given the apparent depth, we can use the concept of refraction of light. When light passes from one medium to a denser medium, it bends towards the normal. This bending effect causes objects submerged in water to appear closer to the surface than they actually are. The formula to relate these depths is given by:
Real Depth = Apparent Depth × Refractive Index
Given the problem:
Using the formula:
Real Depth = 10 cm × 1.33
Calculating the above:
Therefore, the depth of the swimming pool is 13.3cm.
Ajụjụ 23 Ripọtì
The acceleration of a free fall due to gravity is not a constant everywhere on the Earth's surface because
Akọwa Nkọwa
The elliptical shape of the Earth: The Earth is not a perfect sphere; it is slightly flattened at the poles and bulging at the equator. This shape causes variations in gravitational acceleration.
Ajụjụ 24 Ripọtì
Convert 60ºC to degree Fahrenheit
Akọwa Nkọwa
To convert temperatures from Celsius to Fahrenheit, we use the formula:
F = (C × 9/5) + 32
Here, F represents the temperature in Fahrenheit, and C represents the temperature in Celsius.
Let's use this formula to convert 60ºC to Fahrenheit:
F = (60 × 9/5) + 32
First, multiply 60 by 9/5:
60 × 9/5 = 108
Next, add 32 to 108:
108 + 32 = 140
Therefore, 60ºC is equal to 140ºF.
Ajụjụ 25 Ripọtì
An effort of 40N is applied on a machine to lift a mass of 60kg. Determine the mechanical advantage of the machine [ g = 10ms2 ]
Akọwa Nkọwa
To determine the Mechanical Advantage (MA) of a machine, we use the formula:
MA = Load / Effort
Here, the Load is the weight of the mass being lifted, and the Effort is the force applied on the machine.
First, we need to calculate the Load. The Load is obtained by multiplying the mass of the object by the acceleration due to gravity (g = 10 m/s2).
So, the Load (weight of the mass) is:
Load = Mass × Gravity = 60 kg × 10 m/s2 = 600 N
The Effort given is 40 N.
Now, we can calculate the Mechanical Advantage:
MA = Load / Effort = 600 N / 40 N = 15
Therefore, the Mechanical Advantage of the machine is 15.
Ajụjụ 26 Ripọtì
The process of adding impurities to a semiconductor material to increase its conductivity is
Akọwa Nkọwa
The process you are referring to is called doping. In simple terms, doping is the method of intentionally introducing impurities into an extremely pure semiconductor to change its electrical properties, which increases its conductivity.
Semiconductors, like silicon or germanium, are materials that have electrical conductivity between conductors (like metals) and insulators (like glass). By adding impurities, we can control and enhance their ability to conduct electricity. These impurities are atoms of other elements that either have more or fewer electrons in their outer energy levels compared to those in the semiconductor.
When you add impurities with more electrons, it creates an n-type semiconductor because of the extra *negative* charge carriers (electrons). Conversely, adding impurities with fewer electrons makes a p-type semiconductor, as it creates 'holes' which act as positive charge carriers.
This process of doping is essential for creating various semiconductor devices, like diodes, transistors, and integrated circuits, which are foundational components in all electronic devices. Hence, doping plays a crucial role in the functionality and efficiency of electronic systems.
Ajụjụ 27 Ripọtì
If the displacement of a car is proportional to the square of time, then the car is moving with
Akọwa Nkọwa
When we say that the displacement of a car is proportional to the square of time (d ∝ t²), it indicates a relationship between displacement (d) and time (t). This relationship is characteristic of motion where there is constant acceleration. Essentially, it means that the car is not moving at a constant speed (velocity) but is accelerating at a constant rate.
The mathematical representation of this scenario can be expressed using the formula for displacement under uniform acceleration:
d = ut + (1/2)at².
In this equation:
When the displacement is directly proportional to the square of time (d ∝ t²), it implies that the second term of the equation, which contains the (1/2)at² part, dominates the relationship. Thus, the initial velocity (u) is typically zero or negligible, making the entire displacement dependent on how time squared interacts with acceleration.
Therefore, the car is moving with uniform acceleration.
Ajụjụ 28 Ripọtì
The bursting of water pipes during very cold weather, when the water in the pipes form ice could be attributed to
Akọwa Nkọwa
The bursting of water pipes during very cold weather is primarily attributed to the expansion of water on freezing.
Here's why this happens:
1. **Normal water behavior below freezing:** Typically, when most substances freeze, they contract because the molecules get closer together. However, water behaves differently due to its unique molecular structure. As water freezes, it forms a crystalline structure that makes ice less dense than liquid water, causing it to expand.
2. **Effect of expansion:** When water inside a pipe freezes, it expands. This expansion puts tremendous pressure on the pipe walls because the solid ice takes up more space than the liquid water. Most pipes are rigid and do not have enough room to accommodate the expanded volume of ice.
3. **Resulting pressure:** The increased pressure caused by the expanding ice can cause the pipe to crack or burst, especially if there is no other outlet for the water or ice to expand into.
In summary, pipes burst during cold weather primarily due to the expansion of water as it freezes, which creates pressure that the pipe cannot withstand. This phenomenon is due to the unique property of water where it expands upon freezing, unlike most other substances which contract in their solid form.
Ajụjụ 29 Ripọtì
When a bus is accelerating, it must be
Akọwa Nkọwa
When a bus is accelerating, it is primarily changing its velocity. This is because velocity is a vector quantity, which means it includes both the speed and the direction of the object's movement. Acceleration refers to any change in this velocity. Therefore, the bus could be increasing its speed, decreasing its speed (which is also known as deceleration), or changing its direction. All these aspects involve a change in velocity.
Let's break it down further:
Changing its Speed: If the bus is speeding up or slowing down, it results in a change in the magnitude of its velocity, contributing to acceleration.
Changing its Direction: Even if the bus maintains a constant speed, if it changes direction (like taking a turn), its velocity is altered because direction is a part of velocity. This results in acceleration.
Changing its Position: While a change in position happens during acceleration, it is not the defining feature of acceleration. An object can change its position even if it is moving with constant velocity and not accelerating.
So, the key component here for acceleration is the change in velocity, which encompasses changes in speed, direction, or both.
Ajụjụ 30 Ripọtì
What is the inductance reactance of a coil of 7H when connected to a 50Hz a.c circuit?
Akọwa Nkọwa
To determine the inductive reactance of a coil, we use the formula:
Inductive Reactance (XL) = 2πfL
Where:
Given:
Substituting the given values into the formula:
XL = 2 × π × 50 × 7
Calculating this:
XL = 2 × 3.14159 × 50 × 7
XL ≈ 2 × 3.14159 × 350
XL ≈ 2 × 1099.557
XL ≈ 2199.114
Therefore, the inductive reactance of the coil is approximately 2200Ω.
Ajụjụ 31 Ripọtì
Akọwa Nkọwa
When you insert a sheet of an insulating material between the plates of an air capacitor, the capacitance will increase.
Here's why:
C = ε₀ * (εr) * (A/d)
Therefore, inserting an insulating material as a dielectric enhances the capacitor's ability to store charge, ultimately resulting in an increase in capacitance.
Ajụjụ 32 Ripọtì
Using the diagram above, calculate the relative density of x, if the density of methanol is 800kgm−3
Akọwa Nkọwa
density of methanol = 800kgm−3 → 0.8gcm−3
At equilibrium, the density of methanol = the density of liquid x
ρ x h x g = ρ x x hx x g
0.8 x 7.1 = ρ x x 14.2
ρ x = 0.8×7.114.2 = 0.4gcm−3
∴ , the relative density of liquid x = 0.4
Relative density of X = density of liquid xdensity of methanol = 0.40.8 = 0.5
Ajụjụ 33 Ripọtì
The energy stored in the above capacitor is
Akọwa Nkọwa
The energy stored in the capacitor = 12 q2C
Where C = 2F, q = 3C
= 12 322 = 94 = 2.25J
Ajụjụ 34 Ripọtì
A medium texture soil with high organic matter is
Akọwa Nkọwa
A medium texture soil with high organic matter is best described as loamy soil. Here's why:
Loamy soil is a type of soil that is characterized by a balanced mixture of sand, silt, and clay particles. Because of this blend, loamy soil is not too coarse like sandy soil, nor is it too compact and dense like clay soil, making it a medium texture.
Moreover, loamy soil is renowned for its high organic matter content. This means that it contains a significant amount of decomposed plant and animal residues, which enrich the soil and provide essential nutrients for plant growth. This high organic content enhances the soil's fertility and structure, enabling it to retain moisture yet drain well, making it ideal for farming and gardening.
In conclusion, due to its balanced texture and richness in organic matter, loamy soil is the best fit for a medium-textured soil with high organic matter.
Ajụjụ 35 Ripọtì
The velocity ratio of an inclined plane at 60º to the horizontal is
Akọwa Nkọwa
The concept of an inclined plane is all about simplifying the forces involved in moving or holding a load. The **velocity ratio (VR)** for an inclined plane is defined as the ratio of the distance moved by the effort to the distance moved by the load. This can also be expressed in terms of the lengths involved in the triangle made by the inclined plane.
For an inclined plane placed at an angle **θ** to the horizontal, the velocity ratio is given by the formula:
VR = 1/sin(θ)
Given that the inclined plane is at an angle of **60º**:
First, find the sine of 60º:
sin(60º) = √3/2 (approximately 0.866)
Now, substitute this value into the formula for VR:
VR = 1/sin(60º) ≈ 1/0.866 ≈ 1.155
The **velocity ratio** for an inclined plane at **60º** to the horizontal is **approximately 1.155**.
Ajụjụ 36 Ripọtì
Akọwa Nkọwa
In a series resonant circuit, the current flowing in the circuit is at its maximum. Let me explain why:
In a series resonant circuit, we have a resistor (R), inductor (L), and capacitor (C) connected in series with an AC source. At a particular frequency called the resonant frequency, these circuits exhibit some unique characteristics. This resonant frequency is determined by the values of the inductor and capacitor and is given by the formula:
f₀ = 1 / (2π√(LC))
At the resonant frequency:
Thus, in a series resonant circuit, when it is operating at its resonant frequency, the current flowing is at its maximum.
Ajụjụ 37 Ripọtì
Two capacitors of 0.0003μF and 0.0006μF are connected in series, find their combined capacitance.
Akọwa Nkọwa
When capacitors are connected in series, the formula to find their combined capacitance \(C_{\text{total}}\) is given by:
\[ \frac{1}{C_{\text{total}}} = \frac{1}{C_1} + \frac{1}{C_2} \]
where \(C_1\) and \(C_2\) are the capacitances of the individual capacitors. In this case, \(C_1 = 0.0003 \, \mu\text{F}\) and \(C_2 = 0.0006 \, \mu\text{F}\).
First, calculate the reciprocal of each capacitance:
\[ \frac{1}{C_1} = \frac{1}{0.0003} \]
\[ \frac{1}{C_2} = \frac{1}{0.0006} \]
Calculating each value:
\[ \frac{1}{0.0003} = \frac{10^6}{3} \] and \[ \frac{1}{0.0006} = \frac{10^6}{6} \]
Now, add these values together:
\[ \frac{1}{C_{\text{total}}} = \frac{10^6}{3} + \frac{10^6}{6} = \frac{10^6 \times 2}{6} + \frac{10^6 \times 1}{6} = \frac{10^6 \times 3}{6} = \frac{10^6}{2} \]
Finally, take the reciprocal of the resulting value to find \(C_{\text{total}}\):
\[ C_{\text{total}} = \frac{2}{10^6} = 0.0002 \, \mu\text{F} \]
So, the combined capacitance of the two capacitors in series is 0.0002 μF.
Ajụjụ 38 Ripọtì
Calculate the upthrust on a spherical ball of volume 4.2 x 10−4 m3 when totally immersed in a liquid of density 1028kgm−3
Akọwa Nkọwa
Upthrust(Force) = volume of object x density of liquid x g = V x ρ x g
U = 4.2 x 10−4 x 1028 x 10 ≊ 4.3N
Ajụjụ 39 Ripọtì
A load of 300N is to be lifted by a machine with a velocity ratio of 2 and an efficiency of 60%. What effort will be applied to lift the load?
Akọwa Nkọwa
To determine the effort needed to lift a load using a machine, we first need to understand some key concepts: **Load**, **Effort**, **Velocity Ratio** (VR), and **Efficiency**.
1. **Load** is the force or weight that needs to be lifted by the machine. In this case, the load is 300N.
2. **Velocity Ratio (VR)** is the ratio of the distance moved by the effort to the distance moved by the load. Given here as 2.
3. **Efficiency** of a machine is expressed as a percentage and is the ratio of the useful work output to the input work done by the effort. Here, the efficiency is 60% or 0.60 as a decimal.
The formula to calculate the **Effort** is derived from the relationship between these factors:
\[ \text{Efficiency} = \frac{\text{Mechanical Advantage (MA)}}{\text{Velocity Ratio (VR)}} \]
Where:
\[ \text{Mechanical Advantage (MA)} = \frac{\text{Load}}{\text{Effort}} \]
From the above, we have:
\[ \text{MA} = \text{VR} \times \text{Efficiency} \]
Replacing with the given values:
\[ MA = 2 \times 0.60 = 1.2 \]
Now, calculate the **Effort** using the relation:
\[ \text{Effort} = \frac{\text{Load}}{\text{MA}} \]
\[ \text{Effort} = \frac{300N}{1.2} = 250N \]
Therefore, the **Effort** needed to lift the load is 250N.
Ajụjụ 40 Ripọtì
Which of the following operates based on magnetic effect of electric current?
Akọwa Nkọwa
The device that operates based on the magnetic effect of electric current is the Dynamo.
To explain further, let's look at the concept of the magnetic effect of electric current:
A Dynamo is a device that converts mechanical energy into electrical energy. It operates based on the phenomenon called electromagnetic induction, which occurs due to the magnetic effect of electric current. When a coil of wire within the dynamo rotates in the presence of a magnetic field, it induces an electric current in the coil. Thus, the operation of a dynamo relies on the interaction between electric current and magnetic fields.
To contrast with other options:
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