Write as a single fraction: \(\frac{5}{6r} - \frac{3}{4r}\)

Nyocha: WAEC SSCE - General Mathematics - 1993 (Objective) Ihe Ọmụmụ: General Mathematics

Ajụjụ 1 Ripọtì

Write as a single fraction: \(\frac{5}{6r} - \frac{3}{4r}\)

Akọwa Nkọwa
To add or subtract fractions, we need to have a common denominator. Here, we have denominators of 6r and 4r. The least common multiple (LCM) of 6r and 4r is 12r. So, we need to convert each fraction so that it has a denominator of 12r. \(\frac{5}{6r} - \frac{3}{4r} = \frac{5 \cdot 4}{6r \cdot 4} - \frac{3 \cdot 3}{4r \cdot 3}\) Simplifying the resulting fractions, we get: \(\frac{20}{24r} - \frac{9}{12r} = \frac{20}{24r} - \frac{18}{24r}\) Now, we can combine the fractions by subtracting the numerators and keeping the same denominator: \(\frac{20}{24r} - \frac{18}{24r} = \frac{2}{24r}\) Finally, we can simplify the resulting fraction by dividing the numerator and the denominator by 2: \(\frac{2}{24r} = \frac{1}{12r}\) Therefore, the answer is:
1/12r

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