A cylindrical container closed at both ends, has a radius of 7cm and height 5cm [Take π = 22/7]. What is the volume of the container?

Nyocha: WAEC SSCE - General Mathematics - 1990 (Objective) Ihe Ọmụmụ: General Mathematics

Ajụjụ 1 Ripọtì

A cylindrical container closed at both ends, has a radius of 7cm and height 5cm [Take π = 22/7]. What is the volume of the container?

Akọwa Nkọwa
To find the volume of a cylindrical container, we use the formula V = πr^2h, where V is the volume, r is the radius, and h is the height of the cylinder. In this problem, the radius of the container is given as 7cm, and the height is given as 5cm. Substituting these values into the formula, we get: V = πr^2h V = (22/7)(7^2)(5) V = (22/7)(49)(5) V = 22(5)(7) V = 770 Therefore, the volume of the container is 770 cm^3. So, the correct answer is option (E) 770cm^3.

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