CORE Physics (Short Course) - 9223 OxfordAQA

Motion

Bayani Gaba-gaba

A delivery van leaves a depot at half past seven and returns four hours later. Nobody followed it. Nobody watched it park, pull away, sit in traffic or take the long way round the ring road. Yet the tracker in the cab hands the depot manager a single line on a chart, and from that line alone she can say when the van was moving, when it stopped, which leg of the journey was the fastest and how far it went in total. The line is a distance-time graph, and reading one is a skill you can learn in an afternoon and use for the rest of your life.

This lesson teaches you to read that line and to do arithmetic with it. You will meet the one equation OxfordAQA prints on your equation sheet for this topic, learn why physicists insist on two words for going fast rather than one, and find out how a slope on a piece of graph paper turns into a number in metres per second. By the end you will be able to look at a set of coordinates you have never seen before and describe the journey they record, which is exactly what the examiner will ask you to do.

Manufura

  1. If an object moves in a straight line, its distance from a certain point can be represented by a distance-time graph.
  2. The speed of the object can be calculated from the gradient of a distance-time graph.
  3. The velocity, v, of an object is its speed in a given direction and is given by the equation: where s is the displacement and t is the time taken.

Taswirar tunani

An zana wannan batu don ka ga yadda ra'ayoyi ke hadewa.

Bude taswirar tunani a cikin manhaja

Takardar Darasi

Put a tracker in a vehicle and it does something quietly remarkable: it turns four hours of driving that no one observed into a single line you can read in ten seconds. Flat stretches are the traffic lights. Steep stretches are the dual carriageway. A line that bends back down towards the horizontal axis is the journey home. Physics did not invent this trick for vans; the same line describes a sprinter, a lift, a glacier and a spacecraft, and the whole of this topic is about learning to read it and to calculate with it.

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Nazarin Darasi

Barka da kammala darasi akan Motion. Yanzu da kuka bincika mahimman raayoyi da raayoyi, lokaci yayi da zaku gwada ilimin ku. Wannan sashe yana ba da ayyuka iri-iri Tambayoyin da aka tsara don ƙarfafa fahimtar ku da kuma taimaka muku auna fahimtar ku game da kayan.

Za ka gamu da haɗe-haɗen nau'ikan tambayoyi, ciki har da tambayoyin zaɓi da yawa, tambayoyin gajeren amsa, da tambayoyin rubutu. Kowace tambaya an ƙirƙira ta da kyau don auna fannoni daban-daban na iliminka da ƙwarewar tunani mai zurfi.

Yi wannan ɓangaren na kimantawa a matsayin wata dama don ƙarfafa fahimtarka kan batun kuma don gano duk wani yanki da kake buƙatar ƙarin karatu. Kada ka yanke ƙauna da duk wani ƙalubale da ka fuskanta; maimakon haka, ka kallesu a matsayin damar haɓaka da ingantawa.

  1. Which quantity is a speed together with the direction of travel? A. Distance B. Displacement C. Time D. Velocity Answer: D
  2. What does the gradient of a distance-time graph represent? A. The acceleration of the object B. The speed of the object C. The distance travelled by the object D. The total time of the journey Answer: B
  3. A distance-time graph for an object is a horizontal straight line for 20 seconds. What is the object doing during those 20 seconds? A. Moving at a constant speed B. Speeding up C. Slowing down D. At rest Answer: D
  4. A cyclist travels 900 m along a straight road at a constant speed, taking 60 s. What is her speed? A. 0.067 m/s B. 15 m/s C. 54 m/s D. 54000 m/s Answer: B
  5. The equation v = s / t is rearranged to make t the subject. Which is correct? A. t = v x s B. t = s / v C. t = v / s D. t = s x v Answer: B

Yi aikin wadannan tambayoyi a cikin manhaja

Yi aikin wadannan tambayoyi a cikin manhaja

Yi Aikin Tambayoyin Gwaji

Kana son yin aikin tambayoyin gwaji kan Motion? Sauke manhajar Green Bridge CBT don samun tambayoyin gwaji da cikakkun jarrabawa akan wannan batu.

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