The Mole And The Avogadro Constant
Bayani Gaba-gaba
How do chemists count something as small and as numerous as atoms? You cannot tip them onto a balance one at a time, yet reactions happen atom by atom. The answer is the mole, a counting unit so large that it lets us weigh out exact numbers of particles, and the Avogadro constant that pins down just how many a mole contains.
In this lesson you will learn what a mole is, use the link between mass, moles and molar mass, and work with the molar gas volume of 24 dm3 at room temperature and pressure. You will calculate reacting masses, gas volumes, concentrations, empirical and molecular formulae, percentage yield and percentage purity: the quantitative heart of chemistry.
Manufura
- State that concentration can be measured in g / dm3 or mol / dm3.
- [Supplement] State that the mole, mol, is the unit of amount of substance and that one mole contains 6.02 × 1023 particles, e.g. atoms, ions, molecules; this number is the Avogadro constant.
- [Supplement] Use the relationship amount of substance (mol) = mass (g) / molar mass (g / mol) to calculate: (a) amount of substance (b) mass (c) molar mass (d) relative atomic mass or relative molecular / formula mass (e) number of particles, using the value of the Avogadro constant.
- [Supplement] Use the molar gas volume, taken as 24 dm3 at room temperature and pressure, r.t.p., in calculations involving gases.
- [Supplement] Calculate stoichiometric reacting masses, limiting reactants, volumes of gases at r.t.p., volumes of solutions and concentrations of solutions expressed in g / dm3 and mol / dm3, including conversion between cm3 and dm3.
- [Supplement] Use experimental data from a titration to calculate the moles of solute, or the concentration or volume of a solution.
- [Supplement] Calculate empirical formulae and molecular formulae, given appropriate data.
- [Supplement] Calculate percentage yield, percentage composition by mass and percentage purity, given appropriate data.
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- How many particles are there in one mole of a substance? A. 6.02 x 10^23 B. 6.02 x 10^-23 C. 1000 D. 24 Answer: A
- What is the molar gas volume at room temperature and pressure? A. 12 dm3 B. 22.4 dm3 C. 24 dm3 D. 100 dm3 Answer: C
- How many moles are in 40 g of calcium? (Ar Ca = 40) A. 0.5 mol B. 1 mol C. 2 mol D. 40 mol Answer: B
- A compound has 0.4 mol C and 0.8 mol H. Its empirical formula is: A. CH B. CH2 C. C2H D. CH4 Answer: B
- A reaction gives 9 g of product from a maximum possible 12 g. The percentage yield is: A. 25% B. 75% C. 133% D. 3% Answer: B
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