Modulus Inequalities
Bayani Gaba-gaba
A modulus inequality asks not for an exact distance from zero, but for a range of distances: which values lie within a certain reach, or beyond it. The answer is always an interval or a pair of intervals, and once you see the distance picture, deciding which is effortless.
In this lesson you will solve \(|x|
Manufura
- Solve, graphically or algebraically, inequalities involving the modulus, such as k|ax + b| > c and k|ax + b| <= |cx + d|.
Takardar Darasi
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Nazarin Darasi
Barka da kammala darasi akan Modulus Inequalities. Yanzu da kuka bincika mahimman raayoyi da raayoyi, lokaci yayi da zaku gwada ilimin ku. Wannan sashe yana ba da ayyuka iri-iri Tambayoyin da aka tsara don ƙarfafa fahimtar ku da kuma taimaka muku auna fahimtar ku game da kayan.
Za ka gamu da haɗe-haɗen nau'ikan tambayoyi, ciki har da tambayoyin zaɓi da yawa, tambayoyin gajeren amsa, da tambayoyin rubutu. Kowace tambaya an ƙirƙira ta da kyau don auna fannoni daban-daban na iliminka da ƙwarewar tunani mai zurfi.
Yi wannan ɓangaren na kimantawa a matsayin wata dama don ƙarfafa fahimtarka kan batun kuma don gano duk wani yanki da kake buƙatar ƙarin karatu. Kada ka yanke ƙauna da duk wani ƙalubale da ka fuskanta; maimakon haka, ka kallesu a matsayin damar haɓaka da ingantawa.
- Solve |x - 3| < 2. A. x < 1 or x > 5 B. 1 < x < 5 C. -5 < x < -1 D. x < 5 Answer: B
- The inequality |x| > c (c > 0) is equivalent to: A. -c < x < c B. x < -c or x > c C. x > c only D. x < c Answer: B
- Solve |2x - 1| > 5. A. -2 < x < 3 B. x < -2 or x > 3 C. x > 3 only D. -3 < x < 2 Answer: B
- Solve 3|x + 1| < 12. A. -5 < x < 3 B. x < -5 or x > 3 C. -4 < x < 4 D. -3 < x < 5 Answer: A
- Which is a valid way to write the solution of |x| > 4? A. -4 > x > 4 B. x < -4 or x > 4 C. -4 < x < 4 D. x = 4 Answer: B
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Akwai a cikin manhajar Green Bridge
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