Science - Combined - 0653 CIE

Electrical Quantities (continued 2)

Bayani Gaba-gaba

Every time you switch on a light, charge is pushed around a circuit by a source, gives up energy in the bulb, and returns for more. The push is the electromotive force, the energy given up per coulomb is the potential difference, and the opposition to the flow is the resistance. Master these three and you can analyse and cost almost any circuit.

In this topic you will define e.m.f. and potential difference, use voltmeters, measure and calculate resistance, and link power and energy to current and voltage. You will sketch the current-voltage graphs of a resistor, a lamp and a diode, and learn to work out the cost of running appliances in kilowatt-hours.

Manufura

  1. [Core] Understand that electric circuits transfer energy from a source of electrical energy, such as an electrical cell or mains supply, to the circuit components and then into the surroundings
  2. [Core] Recall and use the equation for electrical power P = IV
  3. [Core] Recall and use the equation for electrical energy E = IVt
  4. [Core] Define the kilowatt-hour (kW h) and calculate the cost of using electrical appliances where the energy unit is the kW h

Darasin Sauti

Saurari wannan darasi a cikin manhaja

Taswirar tunani

An zana wannan batu don ka ga yadda ra'ayoyi ke hadewa.

Bude taswirar tunani a cikin manhaja

Katunan tunawa

Gwaji mai sauri kan abin da ake jarraba a wannan batu.

Yi atisayen wadannan katuna a cikin manhaja

Takardar Darasi

Electrical quantities run through every device and every electricity bill. Engineers size wires, rate appliances and design circuits using exactly these equations. In the exam this topic is rich in marks: definitions, graph sketches, and a string of calculations for resistance, power, energy and cost.

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Nazarin Darasi

Barka da kammala darasi akan Electrical Quantities (continued 2). Yanzu da kuka bincika mahimman ra'ayoyi da ra'ayoyi, lokaci yayi da zaku gwada ilimin ku. Wannan sashe yana ba da ayyuka iri-iri Tambayoyin da aka tsara don ƙarfafa fahimtar ku da kuma taimaka muku auna fahimtar ku game da kayan.

Za ka gamu da haɗe-haɗen nau'ikan tambayoyi, ciki har da tambayoyin zaɓi da yawa, tambayoyin gajeren amsa, da tambayoyin rubutu. Kowace tambaya an ƙirƙira ta da kyau don auna fannoni daban-daban na iliminka da ƙwarewar tunani mai zurfi.

Yi wannan ɓangaren na kimantawa a matsayin wata dama don ƙarfafa fahimtarka kan batun kuma don gano duk wani yanki da kake buƙatar ƙarin karatu. Kada ka yanke ƙauna da duk wani ƙalubale da ka fuskanta; maimakon haka, ka kallesu a matsayin damar haɓaka da ingantawa.

  1. The resistance of a component carrying 2 A with 12 V across it is: A. 24 ohm B. 6 ohm C. 0.17 ohm D. 10 ohm Answer: B
  2. A voltmeter should be connected: A. in series with the component B. in parallel with the component C. before the cell only D. it does not matter Answer: B
  3. The I-V graph of a resistor of constant resistance is: A. a curve flattening off B. a straight line through the origin C. zero one way only D. a horizontal line Answer: B
  4. A 60 W lamp runs for 1 hour. The energy used is: A. 60 J B. 0.06 kW h C. 60 kW h D. 3600 kW h Answer: B
  5. 1 kilowatt-hour is equal to: A. 1000 J B. 3600 J C. 3.6 MJ D. 60 J Answer: C

Yi aikin wadannan tambayoyi a cikin manhaja

Yi aikin wadannan tambayoyi a cikin manhaja

Yi Aikin Tambayoyin Gwaji

Kana son yin aikin tambayoyin gwaji kan Electrical Quantities (continued 2)? Sauke manhajar Green Bridge CBT don samun tambayoyin gwaji da cikakkun jarrabawa akan wannan batu.

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