JAMB UTME - Physics - 1987
Tambaya 1 Rahoto
Bayanin Amsa
(75 - 73.5) x 8 = (X - 74) x 6
X = 76cm
Tambaya 2 Rahoto
When the length I of a piece of wire under constant tension is varied, the relationship of the frequency of the vibration \( \alpha \)/ is
Bayanin Amsa
Tambaya 3 Rahoto
Bayanin Amsa
3 x 4 x 10-5 = V2−125125×(120−20)
V2 = 126.50cm3
Tambaya 4 Rahoto
Bayanin Amsa
mh x ch x θ h = mc x cc x θ c
mh x ch x (θ - 20) = mc x cc x (20 - 10)
ch = cc ; mc = 3mh
therefore, θ = 50oC
Tambaya 5 Rahoto
Bayanin Amsa
Tambaya 6 Rahoto
Bayanin Amsa
= 0.5 x 40 x 2 x 60
= 2400J
Tambaya 8 Rahoto
Bayanin Amsa
= (0 x 4) + (12 x 0.1 x 4 x 4)
= 0.8m
workdone = force x distance
= 40 x 0.8
= 32J
Tambaya 9 Rahoto
The velocity time graph above describes the motion of a particle between two points P and Q. What is the distance between P and Q?
Bayanin Amsa
Tambaya 10 Rahoto
Bayanin Amsa
thrust = m(v−u)t x t1
270 = m(300 - 0)
m = 0.90kg
Tambaya 11 Rahoto
Bayanin Amsa
R = √129
= 11.36km
Tambaya 12 Rahoto
Bayanin Amsa
Tambaya 13 Rahoto
Bayanin Amsa
= (2 x 333000) + (2 x 2090 x 2)
= 674 360J
Tambaya 14 Rahoto
Bayanin Amsa
F1 = 3Fo
= 3 x 40 = 120Hz
F2 = 5Fo
= 5 x 40
= 200Hz
Tambaya 15 Rahoto
A galvanometer of resistance \(20\,\Omega\) is to be provided with a shunt that \(\frac{1}{10}\) of the whole current in a circuit passes through the galvanometer. The resistance of the shunt is
Tambaya 16 Rahoto
Bayanin Amsa
Tambaya 19 Rahoto
Bayanin Amsa
since, F = ma = kgms-1 = N
kgms-1 = Ns
Tambaya 20 Rahoto
Tambaya 21 Rahoto
Tambaya 22 Rahoto
Bayanin Amsa
4.5cm .... θ
0cm ....0oC
4.5−020−0 = 0−0100−0
θ = 22.5oC
Tambaya 23 Rahoto
Tambaya 24 Rahoto
Bayanin Amsa
1.33 = real depth1
real depth = 1.33cm
Tambaya 25 Rahoto
Bayanin Amsa
Tambaya 26 Rahoto
Tambaya 27 Rahoto
Bayanin Amsa
c = 1466Jkg-1oC-1
Tambaya 28 Rahoto
Bayanin Amsa
K.E = 12 mv2 = 200m joules
%converted = 200m1000m x 100
= 20%
Tambaya 29 Rahoto
Bayanin Amsa
= 2 x 0.3
= 0.6ms-1
Tambaya 30 Rahoto
Bayanin Amsa
Tambaya 31 Rahoto
In the figure above, M and N are insulated metal spheres in contact. A negatively charged ebonite rod P is I brought near M. When M and N are Separated and the rod is taken away, which of the following statements is correct
Bayanin Amsa
Tambaya 32 Rahoto
Tambaya 33 Rahoto
The fig above represents the main sequence of energy conversion at Kainji dam. What is the efficiency of the system?
Bayanin Amsa
Tambaya 34 Rahoto
What type of reaction is represented by the following scheme?
\[ {}^{2}_{1}X + {}^{2}_{1}Y + {}^{3}_{2}Z + {}^{1}_{0}n + \text{energy} \]Tambaya 35 Rahoto
Two capacitance of \(6\,\mu\text{F}\) and \(8\,\mu\text{F}\) are connected in series. What additional capacitance must be connected in series with this combination to give a total of \(3\,\mu\text{F}\)
Bayanin Amsa
therefore, C = 24μ F
Tambaya 37 Rahoto
Tambaya 38 Rahoto
Bayanin Amsa
Tambaya 39 Rahoto
Bayanin Amsa
= 60000−(4800×10)4800
= 2.5ms-2
Tambaya 41 Rahoto
A cube of side 10cm and mass 0.5kg floats in a liquid with only \( \frac{1}{5} \) of its height above the liquid surface. What is the relative density of the liquid?
Bayanin Amsa
volume of cube = 103cm3
volume of liquid displaced = 45 x 1000
= 800cm3
density of liquid displaced;
= 500800
= 0.625cm-1
Tambaya 42 Rahoto
Bayanin Amsa
Fm = (40 x 10 x sin 45) - (40 x 10 x 0.25 x cos 45)
= 212N
Tambaya 43 Rahoto
Bayanin Amsa
20 = 60×V60+V
V = 30cm
similarly, UV = height of objectheight of image
6030 = 3h
h = 1.5cm
Tambaya 45 Rahoto
A 50kg block is dropped from a point 10cm above as shown in the fig above. if the force constant of the spring is 4.0 x 104Nm-1, find the maximum compression of the spring [g = 10ms-2]
Tambaya 46 Rahoto
The fig above shows two connected bodies of masses M1 and M2 in equilibrium under gravity. The tension in the upper string is
Tambaya 47 Rahoto
Bayanin Amsa
Tambaya 48 Rahoto
