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Tambaya 1 Rahoto
mcΩ = I2RTt
1000 x c x 10 = 3 x 3 x 20 x 10
0.18Jg-1oC
Tambaya 2 Rahoto
= 5 x 3600 x 0.126 x 10-6
= 2.268 x 10-3kg
Tambaya 3 Rahoto
e1 = 14 - L and e2 = 16 - L
Using, m1e1 = m2e2
2014−L = 3016−L
L = 10cm
Tambaya 4 Rahoto
In the Figure above, QR is a vertical conductor and the current I flows from R to Q, P is a point on the horizontal plane and is to the south of the wire. The direction of the magnetic field at P due to the current is
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Tambaya 8 Rahoto
= 5 x 10-4kg
Density = massarea x thickness
500 = 5×10−70.5 x thickness
thickness = 2 x 10-9m
Tambaya 9 Rahoto
The image above shows an inverted U-tube with the open end, O of one limb below the level, W of water in the tank, in order that water should begin to flow from the tank it is is necessary that
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Tambaya 10 Rahoto
mass = velocity x density
= 20 x 19
= 380g
Tambaya 12 Rahoto
In a resonance tube experiment, a tube of fixedlength in closed at one end and several turningforks of increasing frequency used to obtainresonance at the open end. If the turning fork withthe lowest frequency which gave resonance had a frequency f1 and the next turning fork to giveresonance had a frequency f2, find the ratio f2/ f1.
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Tambaya 13 Rahoto
= m(u−v)t
16 = 4(v−0)5
v = 20ms-1
Tambaya 15 Rahoto
echo time = 1 ÷ 2 = 0.5 sec.
= 0.5 x 250
= 125m
Tambaya 16 Rahoto
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Tambaya 17 Rahoto
Density x pressure = constant
D1 x P1 = D2 x P2
13.6 x 0.76 = 1 x P2
P2 = 10m
Tambaya 18 Rahoto
PQ is a thin rod on a horizontal table, RS is a plane mirror inclined at \(45^\circ C\) to the horizontal as shown above. The image of PQ as seen in the mirror by the eye T is
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Tambaya 19 Rahoto
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Tambaya 20 Rahoto
3 x 2 x 10-5 = V2−1010×100
V2 = 10.06cm3
Tambaya 21 Rahoto
Which of the following may be used to determine relative humidity in a physics laboratory?
I. Manometer
II. Wet-and-dry bulb hygrometer
III. Hair hygrometer
IV. A hydrometer.
Tambaya 22 Rahoto
Tambaya 24 Rahoto
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Tambaya 25 Rahoto
Which of the following figures gives the correct resultant R of two vectors P and Q?
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Tambaya 26 Rahoto
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Tambaya 27 Rahoto
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Tambaya 28 Rahoto
I = 2R ; I = 0.2r
24 = 0.2r
r = 0.4Ω
Tambaya 29 Rahoto
Which of the following may be used to determine the relative humidity in a physics laboratory I. Manometer
II. Wet-and-Dry Bulb Hygrometer
III. Hair Hygrometer
IV. A Hydrometer
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Tambaya 30 Rahoto
Tambaya 31 Rahoto
Tambaya 32 Rahoto
Each of the figures in the diagram above represent two current carrying conductors situated close to each other. In which two diagrams, are the forces between the two wires attractive
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Tambaya 33 Rahoto
In a resonance tube experiment, a tube fixed length is closed at one end and several tuning forks of increasing frequency used to obtain resonance at the open end. If the tuning fork with the lowest frequency which gave resonance had a frequency \(f_1\) and the next tuning fork to give resonance had a frequency \(f_2\), find the ratio \(\frac{f^2}{f^2}\).
Fλ = velocity
F1 x λ1
= F2 x
λ2
; F1 x 4λ1
= F2 x -λ2
= F2F1 = 3
Tambaya 34 Rahoto
P2 = 2P ; T1 = 2T2
therefore, P1×10002T2 = 2P2×V2T2
= 25cm
Tambaya 35 Rahoto
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Tambaya 36 Rahoto
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Tambaya 37 Rahoto
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Tambaya 38 Rahoto
= 50 x 10 x 5 = 500W
Tambaya 39 Rahoto
The speed of light in vacuum is \(3.0 \times 10^{8}\,\mathrm{ms}^{-1}\). If the refractive index of a transparent liquid is \(\frac{4}{3}\), then the speed of light in the liquid is
43 = 3×108v
v = 2.25 x 10 8ms-1
Tambaya 40 Rahoto
Tambaya 42 Rahoto
Tambaya 43 Rahoto
40.2 = 20N/C
Tambaya 44 Rahoto
1.5 = 3×104speed in glass
speed in glass = 2 x 108ms-1
Tambaya 45 Rahoto
Tambaya 46 Rahoto
The diagram above shows three circuits, the internal resistances of the batteries are negligible. which of the currents is the largest
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Tambaya 47 Rahoto
= 0.99A
IR = 10 x 10 x 10-3 x 5
R = 599 Ω
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