JAMB UTME - Chemistry - 1994

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Tambaya 3 Rahoto

For a gas, the relative molecular mass is equal to 2Y. What is Y?

The mas of the gas

The vapour density of the gas Amsar da ta dace

The volume of the gas

The temperature of the gas

Bayanin Amsa

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

Duba Amsa

Tambaya 4 Rahoto

What volume of oxygen measured at s.t.p would be liberated on electrolysis by 9650 coulombs of electricity?

(Molar volume of gas = 22.4 dm3, F = 96,500 C mol-)

22.4 dm3

11.2 dm3

1.12 dm3

0.560 dm3 Amsar da ta dace

Bayanin Amsa

Karanta bayanin darasi akan Electrolysis (JAMB)

Electrolysis

Duba Amsa

Tambaya 5 Rahoto

At the same temperature and pressure, 50 cm3 of nitrogen gas contains the same number of molecules as?

25 cm3 of methane

40 cm3 of hydrogen

50 cm3 of ammonia Amsar da ta dace

100 cm3 of chlorine

Bayanin Amsa

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

Duba Amsa

Tambaya 6 Rahoto

Which of these metals CANNOT replace hydrogen from alkaline solutions?

Alulinium

Zinc

Tin

Iron Amsar da ta dace

Bayanin Amsa

Karanta bayanin darasi akan Metals And Their Compounds (JAMB)

Metals And Their Compounds

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Tambaya 7 Rahoto

The solubility, in moles per dm3 of 20.2 g of potassium trioxonitrate (V) dissolve in 100 g of the resulting mixture is?(K = 39, O = 16, N =14).

0.10

0.20

1.00

2.00 Amsar da ta dace

Bayanin Amsa

The first step to solve the problem is to calculate the molar mass of potassium trioxonitrate (V), which is given by: KNO₃ = (1 x 39) + (1 x 14) + (3 x 16) = 101 g/mol Next, we need to calculate the number of moles of potassium trioxonitrate (V) that are present in 20.2 g: moles of KNO₃ = mass / molar mass = 20.2 / 101 = 0.2 mol Now, we need to calculate the total mass of the resulting mixture. This is given by: mass of resulting mixture = mass of KNO₃ + mass of water = 20.2 + 100 = 120.2 g Finally, we can calculate the solubility of potassium trioxonitrate (V) in moles per dm³ by dividing the number of moles of KNO₃ by the volume of the resulting mixture in dm³. The volume of the resulting mixture is equal to 0.1 dm³ (since 100 g of water is equal to 0.1 dm³): solubility = moles / volume = 0.2 / 0.1 = 2.0 Therefore, the solubility of potassium trioxonitrate (V) in moles per dm³ is 2.0 mol/dm³, which corresponds to option (D).

Karanta bayanin darasi akan Oxidation And Reduction (JAMB)

Oxidation And Reduction

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Tambaya 8 Rahoto

The diagram above represents an atom of

magnesium Amsar da ta dace

helium

chlorine

neon

Bayanin Amsa

Karanta bayanin darasi akan Structure Of The Atom (Ghana Only) (WAEC)

Karanta bayanin darasi akan Atomic Structure And Bonding (JAMB)

Karanta bayanin darasi akan Periodic Chemistry (Ghana Only) (WAEC)

Structure Of The Atom (Ghana Only)

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Tambaya 9 Rahoto

A major effect of oil pollution in coastal waters is the?

destruction of marine life

desalination of the water

increase in the acidity of the water Amsar da ta dace

detoxification of the water

Bayanin Amsa

Karanta bayanin darasi akan Environmental Pollution (JAMB)

Environmental Pollution

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Tambaya 10 Rahoto

The ∆H for the reaction represented by the energy profile above is

-100 kJ mol--1

+ 100 kJ mol-1

+50 kJ mol-1

-50 kJ mol-1 Amsar da ta dace

Bayanin Amsa

Karanta bayanin darasi akan Energy Changes (JAMB)

Karanta bayanin darasi akan Energy And Energy Changes (WAEC)

Energy Changes

Energy And Energy Changes

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Tambaya 11 Rahoto

Which of the following are produced when ammonium trioxonitrate (V) crystals are cautiously heated in a hard glass round bottomed flask?

N2O and steam Amsar da ta dace

NO2 and ammonia

N2O2 and NO2

NO and NO2

Bayanin Amsa

Karanta bayanin darasi akan Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

Duba Amsa

Tambaya 12 Rahoto

In the diagram above the activation energy is represented by

y - x Amsar da ta dace

x - z

Bayanin Amsa

In the diagram, the activation energy is represented by the vertical distance between the reactants (energy level x) and the maximum point in the curve (energy level y). Therefore, the answer is "y - x".

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

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Tambaya 13 Rahoto

Use the diagram above to answer this question.

The reaction taking place in the flask above is known as

hydrolysis

double decomposition

dehydration Amsar da ta dace

pyrolysis

Bayanin Amsa

The reaction taking place in the flask above is dehydration. Dehydration is a chemical reaction that involves the removal of water from a molecule or compound. In the diagram, there is a reactant (the pink molecule) that loses a water molecule (H2O) and forms a new compound (the blue molecule). This process is known as dehydration, and it is represented by the removal of water (H2O) from the pink molecule, leaving behind a double bond (represented by the black line) between the two carbon atoms.

Karanta bayanin darasi akan Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

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Tambaya 14 Rahoto

One mole of a hydrocarbon contains 48 g of carbon. If it vapour density is 28, the hydrocarbon is?

an alkane

an alkene Amsar da ta dace

an alkyne

aromatic (C = 12, H = 1)

Bayanin Amsa

Karanta bayanin darasi akan Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

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Tambaya 15 Rahoto

Element X, Y and Z belong to a groups I, V and VII respectively. Which of the following is TRUE about the bond types of XZ and YZ3?

Both are electrovalent

Both are covalent

XZ is electrovalent and YZ3 is covalent Amsar da ta dace

XZ is covalent and YZ3 is electrovalent

Bayanin Amsa

The bond types of XZ and YZ can be determined based on the electronic configuration of the elements. Group I elements, such as X, have one valence electron, while Group V elements, such as Y, have five valence electrons. Group VII elements, such as Z, have seven valence electrons. To achieve stability, Group I elements tend to lose one electron to achieve a stable noble gas configuration, while Group V elements tend to gain three electrons to achieve a stable noble gas configuration. Group VII elements tend to gain one electron to achieve a stable noble gas configuration. Therefore, in the case of XZ, element X will lose one electron to element Z to form an electrovalent or ionic bond. In the case of YZ, element Y will share three electrons with element Z to form a covalent bond. Thus, the correct option is: XZ is electrovalent and YZ is covalent.

Karanta bayanin darasi akan Chemical Bonds (Ghana Only) (WAEC)

Chemical Bonds (Ghana Only)

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Tambaya 16 Rahoto

An anhydride is an oxide of non-mental?

which will not dissolve in water

whose solution in water has a pH greater than 7

whose solution in water has a pH less than 7 Amsar da ta dace

whose solution in water has a pH of 7

Bayanin Amsa

Karanta bayanin darasi akan Periodic Chemistry (Ghana Only) (WAEC)

Duba Amsa

Tambaya 17 Rahoto

Which of these solutions will give a white precipitate with a solution of barium chloride acidified with hydrochloric acid?

Sodium trioxocarbonate (IV) Amsar da ta dace

Sodium tetraoxosulphate (IV)

Sodium trioxosulphate (IV)

Sodium sulphide

Bayanin Amsa

Karanta bayanin darasi akan Acids, Bases And Salts (Ghana Only) (WAEC)

Duba Amsa

Tambaya 18 Rahoto

SO3 is NOT directly dissolved in water in the preparation of H2SO4 by the contact process because?

the reaction between SO3 and water is violently exothermic Amsar da ta dace

acid is usually added to water and never water to acid

SO3 does not dissolve in water readily

SO3 is an acid gas

Bayanin Amsa

Karanta bayanin darasi akan Acids, Bases And Salts (Ghana Only) (WAEC)

Duba Amsa

Tambaya 19 Rahoto

The general formula of alkanoates is?

RCHO

R2CO Amsar da ta dace

RCOOH

RCOOR

Bayanin Amsa

Karanta bayanin darasi akan Chemistry Of Carbon Compounds (Ghana Only) (WAEC)

Karanta bayanin darasi akan Periodic Chemistry (Ghana Only) (WAEC)

Chemistry Of Carbon Compounds (Ghana Only)

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Tambaya 20 Rahoto

\( \mathrm{MnO_4(aq) + 8H + 5Fe^{2+} \rightarrow Mn^{2+}(aq) + 5Fe^{3+}(aq) + H_2O} \). The oxidation number of maganese in the above reaction changed from

+8 to +2 Amsar da ta dace

+6 to +2

+5 to +2

+4 to +2

Bayanin Amsa

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

Karanta bayanin darasi akan Separation Of Mixtures And Purification Of Chemical Substances (JAMB)

Separation Of Mixtures And Purification Of Chemical Substances

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Tambaya 21 Rahoto

Which of the following reagents will confirm the presence of unsaturation in a compound?

Fehling's solution

Bromine water Amsar da ta dace

Tollen's reagent

Benedict's solution

Bayanin Amsa

Bromine water can confirm the presence of unsaturation in a compound. Unsaturated compounds contain multiple bonds between carbon atoms, and these double or triple bonds can readily react with bromine water (an aqueous solution of bromine) by breaking the double or triple bond and forming a colorless dibromo compound. As a result, if the compound has unsaturation, bromine water will lose its characteristic orange color upon reaction with the compound, indicating the presence of unsaturation. The other reagents listed are used for different types of chemical tests, such as reducing sugars (Fehling's and Benedict's solutions) or identifying aldehydes or ketones (Tollen's reagent).

Karanta bayanin darasi akan Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

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Tambaya 22 Rahoto

The IUPAC name of the compound above is

2,2-dimethyl but -1-yne

2,2-dmethyl but -1-ene

3,3-dimethyl but -1-ene Amsar da ta dace

3,3-dimethyl but-1-yne

Bayanin Amsa

Karanta bayanin darasi akan Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

Duba Amsa

Tambaya 23 Rahoto

20 cm3 of a 2.0 M solution of ethanoic acid was added to excess of 0.05 M sodium hydroxide. The mass of the salt produced is?(Na = 23, C = 12, O = 16, H = 1)

2.50 g

2.73 g

3.28 g Amsar da ta dace

4.54 g

Bayanin Amsa

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

Karanta bayanin darasi akan Stoichiometry And Chemical Reactions (WAEC)

Stoichiometry And Chemical Reactions

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Tambaya 24 Rahoto

MnO4(aq) + 8H + (aq) + 5Fe2+ → Mn2+(aq) + 4H2O(I). The oxidation number of manganese in the above reaction changed from?

+7 to +2 Amsar da ta dace

+6 to +2

+5 to +2

+4 to +2

Bayanin Amsa

In the given chemical reaction, MnO₄^- ion is reduced to Mn²⁺ ion, indicating a decrease in the oxidation number of manganese. To determine the change in oxidation number, we need to know the oxidation state of manganese in the reactant and product side. In MnO₄^-, oxygen has an oxidation state of -2, so the oxidation state of Mn can be calculated as follows: (+4) + 4(-2) = -8 x + (-8) = -1 (the net charge of MnO₄^-) Solving for x, the oxidation state of Mn in MnO₄^- is +7. On the product side, there are two H₂O molecules, so the oxidation state of Mn can be calculated as follows: x + 4(+2) + 2(-2) = 0 (the net charge of Mn2+) Solving for x, the oxidation state of Mn in Mn²⁺ is +2. Therefore, the oxidation state of Mn changes from +7 to +2 in the given reaction, which means that the correct answer is "+7 to +2".

Karanta bayanin darasi akan Oxidation And Reduction (JAMB)

Oxidation And Reduction

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Tambaya 25 Rahoto

8g CH4 occupies 11.2 dm3 at s.t.p. What volume would 22 g of CH3CH3 occupy under the same condition?

(C = 12, H = 1)

3.7 dm3

11.2 dm3 Amsar da ta dace

22.4 dm

33.6 dm3

Bayanin Amsa

Karanta bayanin darasi akan Stoichiometry And Chemical Reactions (WAEC)

Stoichiometry And Chemical Reactions

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Tambaya 26 Rahoto

A mixture of sand, ammonium chloride and sodium chloride is best separated by?

sublimation followed by addition of water and filteration Amsar da ta dace

sublimation followed by addition of water and evaporation

addition of water followed by filtration and sublimation

addition of water followed by crystallization and sublimation

Bayanin Amsa

The best method to separate the mixture of sand, ammonium chloride, and sodium chloride is "sublimation followed by addition of water and filtration". The mixture contains two sublimating components, sand and ammonium chloride, and one non-sublimating component, sodium chloride. Therefore, sublimation can be used to separate the mixture into two components. By heating the mixture, ammonium chloride sublimes, and can be collected on a cool surface as solid. The remaining mixture will contain sand and sodium chloride. Next, water can be added to dissolve the sodium chloride, leaving the sand as a residue. The solution containing sodium chloride can then be filtered to remove any insoluble impurities, leaving behind a clear solution of sodium chloride. Therefore, the correct option for separating the given mixture is "sublimation followed by addition of water and filtration".

Karanta bayanin darasi akan Separation Of Mixtures And Purification Of Chemical Substances (JAMB)

Separation Of Mixtures And Purification Of Chemical Substances

Duba Amsa

Tambaya 27 Rahoto

When sodium ethanoate is treated with a few drops of concentrated tetraoxosulphate(vi)acid. one of the products is

CH3COOH Amsar da ta dace

CH3COOCH3

CH3COOC2H5

C2H5COOCH3

Bayanin Amsa

When sodium ethanoate (also known as sodium acetate) is treated with concentrated tetraoxosulphate (VI) acid (also known as sulfuric acid), one of the products formed is ethanoic acid (CH3COOH). This is due to the fact that the sulfuric acid protonates the acetate ion in the sodium ethanoate solution, leading to the formation of ethanoic acid and sodium sulfate as the other product. Therefore, the correct option is: CH3COOH.

Karanta bayanin darasi akan Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

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Tambaya 28 Rahoto

Sodium chloride has no solubility product value because of its?

saline nature

high solubility Amsar da ta dace

low solubility

insolubility

Bayanin Amsa

Karanta bayanin darasi akan Acids, Bases And Salts (Ghana Only) (WAEC)

Duba Amsa

Tambaya 29 Rahoto

A solid that absorbs water from he atmosphere and forms an aqueous solution is?

hydrophilic

efforescent

deliquescent Amsar da ta dace

hygroscopic

Bayanin Amsa

Karanta bayanin darasi akan Solubility (JAMB)

Karanta bayanin darasi akan Solubility Of Substances (Ghana Only) (WAEC)

Karanta bayanin darasi akan Acids, Bases And Salts (Ghana Only) (WAEC)

Solubility

Solubility Of Substances (Ghana Only)

Duba Amsa

Tambaya 30 Rahoto

To what temperature must a gas 273 K be heated in order to double both its volume and pressure?

298 K

546 K

819 K

1092 K Amsar da ta dace

Bayanin Amsa

According to the Ideal Gas Law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin. If we want to double both the volume and pressure of the gas while keeping the number of moles constant, then we can use the combined gas law, which states: (P1V1)/T1 = (P2V2)/T2 where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume. Since we want to double both the pressure and volume, we can set: P2 = 2P1 V2 = 2V1 Substituting these values into the combined gas law, we get: (P1*2V1)/T1 = (2P1*2V1)/T2 Simplifying, we get: T2 = T1*4 So, the temperature must be quadrupled in order to double both the pressure and volume. Since the initial temperature is 273 K, we can multiply it by 4 to get the final temperature: T2 = 273 K * 4 = 1092 K Therefore, the answer is 1092 K.

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

Duba Amsa

Tambaya 31 Rahoto

In an electrolytic set-up to protect iron from corrosion, the iron is?

made cathode

made anode

used with a metal of lower electropositive potential

initially coated with tin Amsar da ta dace

Bayanin Amsa

Karanta bayanin darasi akan Electrolysis (JAMB)

Electrolysis

Duba Amsa

Tambaya 32 Rahoto

Which of the following is TRUE of Le Chatelier's Principle for an exothermic reaction?

Increase in temperature will cause an increase in the equilibrium constant

Increase in temperature will cause a decrease in the equilibrium constant Amsar da ta dace

Addition of a catalyst will cause an increase in the equilibrium constant

Addition of a catalyst will cause a decrease in the equilibrium constant

Bayanin Amsa

Le Chatelier's Principle states that if a system at equilibrium is subjected to a change in temperature, pressure, or concentration of reactants or products, then the equilibrium shifts in the direction that tends to undo the effect of the change. For an exothermic reaction, increasing the temperature will cause a shift in the equilibrium towards the reactants, in order to reduce the effect of the added heat. This means that the equilibrium constant will decrease since it is a ratio of the concentrations of products to reactants at equilibrium. Therefore, the correct answer is "Increase in temperature will cause a decrease in the equilibrium constant." The addition of a catalyst will not affect the position of the equilibrium, but it will increase the rate at which the reaction reaches equilibrium. Therefore, the statement "Addition of a catalyst will cause an increase in the equilibrium constant" is false.

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

Duba Amsa

Tambaya 33 Rahoto

A pure solid usually melts?

over a wide range of temperature

over a narrow range of temperature Amsar da ta dace

at a lower temperature than the impure one

at the same temperature as the impure one

Bayanin Amsa

In general, a pure solid usually melts over a narrow range of temperature. This is because a pure solid has a well-defined melting point, which is the temperature at which the solid transitions into its liquid state. The melting point of a pure solid is determined by its chemical composition and the strength of the intermolecular forces between its molecules. Impurities in a solid can disrupt the intermolecular forces and change the melting point of the solid. This is why impure solids may melt over a wider range of temperature or at a lower temperature than the corresponding pure solid. Therefore, if we compare the melting behavior of a pure solid and an impure solid, we can expect the pure solid to have a well-defined melting point and melt over a narrow range of temperature, while the impure solid may melt over a wider range of temperature or at a lower temperature.

Karanta bayanin darasi akan Solubility (JAMB)

Solubility

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Tambaya 34 Rahoto

An increase in temperature causes an increase in the pressure of a gas because?

it decreases the number of collision between the molecules

the molecules of the gas bombard the walls of the container more frequently

it increases the number of collision between the molecules Amsar da ta dace

it causes the molecules to combine

Bayanin Amsa

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

Duba Amsa

Tambaya 35 Rahoto

The number of electrons in the valence shell of an element of atomic number 14 is?

4 Amsar da ta dace

Bayanin Amsa

The atomic number of an element tells us the number of protons in its nucleus, which is also equal to the number of electrons in the neutral atom. The element with atomic number 14 is Silicon (Si). To determine the number of electrons in the valence shell, we need to look at the electron configuration of Silicon. The electron configuration of Silicon is 1s2 2s2 2p6 3s2 3p2. The valence shell of an atom is the outermost shell containing electrons, and in the case of Silicon, this is the 3rd shell (3s2 3p2). The number of electrons in the valence shell of Silicon is equal to the sum of the electrons in the s and p orbitals of that shell, which is 2 + 2 = 4. Therefore, the correct answer is 4, which means that Silicon has 4 valence electrons.

Karanta bayanin darasi akan Atomic Structure And Bonding (JAMB)

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Tambaya 36 Rahoto

Clothes should be properly rinsed with water after bleaching because?

the bleach decolourizes the cothes

chlorine reacts with fabrics during bleaching

the clothes are sterilized during bleaching

hydrogen chloride solution is produced during bleaching Amsar da ta dace

Bayanin Amsa

Karanta bayanin darasi akan Oxidation And Reduction (JAMB)

Oxidation And Reduction

Duba Amsa

Tambaya 37 Rahoto

The densities of two gases, X and Y, are 0.5 g dm-3 and 2.0 dm-3 respectively.

What is the rate of diffusion of X relative to Y?

0.1

0.5

2.0 Amsar da ta dace

4.0

Bayanin Amsa

Karanta bayanin darasi akan Kinetic Theory Of Matter And Gas Laws (JAMB)

Duba Amsa

Tambaya 38 Rahoto

The shape of ammonia molecule is?

trigonal planar Amsar da ta dace

octahedral

square planar

tetrahedral

Bayanin Amsa

Karanta bayanin darasi akan Atomic Structure And Bonding (JAMB)

Duba Amsa

Tambaya 39 Rahoto

When sodium is added to ethanol, the products are?

sodium hydroxide and water

sodium hydroxide and hydrogen

sodium ethoxide and water

sodium ethoxide and hydrogen Amsar da ta dace

Bayanin Amsa

When sodium is added to ethanol, the products are sodium ethoxide (NaC2H5O) and hydrogen gas (H2). This is because sodium is a highly reactive metal that reacts with ethanol to displace the hydrogen atom attached to the carbon atom in the -OH group. As a result, the hydrogen atom combines with another hydrogen atom to form hydrogen gas, while the remaining ethoxide ion combines with the sodium cation to form sodium ethoxide. Therefore, the correct option is: sodium ethoxide and hydrogen gas.

Karanta bayanin darasi akan Electrolysis (JAMB)

Karanta bayanin darasi akan Acids, Bases And Salts (JAMB)

Electrolysis

Acids, Bases And Salts

Duba Amsa

Tambaya 40 Rahoto

Which of the following compounds is a base?

CO2

CaO Amsar da ta dace

H3PO3

CH3COOCH3

Bayanin Amsa

A base is a substance that can accept hydrogen ions (H+) or donate hydroxide ions (OH-) in a chemical reaction. Among the given options, CaO is a base. When CaO dissolves in water, it reacts with water to form Ca(OH)2, a strong base that dissociates into calcium ions (Ca2+) and hydroxide ions (OH-) in solution. Therefore, CaO is a base.

Karanta bayanin darasi akan Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

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Tambaya 41 Rahoto

From the above diagram, the caustic soda in the conical flask serves to

dry ethene gas

remove carbon (iv) oxides from ethene

remove carbon (ii) oxide from ethene Amsar da ta dace

remove sulphur (iv) oxide from ethene

Bayanin Amsa

Karanta bayanin darasi akan Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

Duba Amsa

Tambaya 42 Rahoto

In the diagram above, R is a mixture of

potassium tetraxochlorate (VII) and concentrated H2SO4

potassium trioxochlorate (V) and concentrated H2SO4

potassium tetratoxomanganate (VII) and concentrated HCI

manganes (IV) oxide and concentrated HCI Amsar da ta dace

Bayanin Amsa

Karanta bayanin darasi akan Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

Duba Amsa

Tambaya 43 Rahoto

The set-up above would be useful for determining the amount of

oxygen in air

water vapour in air Amsar da ta dace

CO2 in air

arygen in air

Bayanin Amsa

Karanta bayanin darasi akan Air (JAMB)

Air

Duba Amsa

Tambaya 44 Rahoto

Which of the following atoms represents deuterium?

No protons = 1, No of neutrons = 0, No of electrons = 0

No protons = 1, No of neutrons = 0, No of electrons = 1

No protons = 1, No of neutrons = 1, No of electrons = 1 Amsar da ta dace

No protons = 1, No of neutrons = 2, No of electrons = 1

Bayanin Amsa

Deuterium is an isotope of hydrogen which has one proton and one neutron in its nucleus. Therefore, the correct answer would be the option that has one proton and one neutron, and one electron to balance the charge of the nucleus. The only option that satisfies this requirement is "No protons = 1, No of neutrons = 1, No of electrons = 1". So, the answer is.

Karanta bayanin darasi akan Structure Of The Atom (WAEC)

Structure Of The Atom

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Tambaya 45 Rahoto

Crude copper could be purified by the electrolysis of concentrated copper (II) chloride if the crude copper is?

made both the anode and the cathode

made the cathode

made the anode Amsar da ta dace

dissolved in the solution

Bayanin Amsa

Karanta bayanin darasi akan Electrolysis (JAMB)

Electrolysis

Duba Amsa

Tambaya 46 Rahoto

2HCL(ag) + CaCO3(ag) ? CaCL2(ag) + H2O(1) + CO

From the reaction above, which of the following curves represents the consumption of calcium trioxocarbonate (IV) as dilute HCL is added to it?

M Amsar da ta dace

Bayanin Amsa

Karanta bayanin darasi akan Periodic Chemistry (Ghana Only) (WAEC)

Duba Amsa

Tambaya 47 Rahoto

Which of the following is the correct order of decreasing activity of the metals Fe, Ca, Al and Na?

Fe> Ca> Al> Na

Na> Ca> Al> Fe Amsar da ta dace

Al> Fe> Na> Ca

Ca> Na> Fe>, Al

Bayanin Amsa

The reactivity of metals is related to their tendency to lose electrons and form positive ions. Metals that lose electrons easily are more reactive, while metals that don't lose electrons easily are less reactive. The order of decreasing activity of the metals Fe, Ca, Al, and Na can be determined by their position in the reactivity series. In the reactivity series, metals are listed in order of decreasing reactivity. The most reactive metals are at the top, and the least reactive metals are at the bottom. The reactivity series is based on how readily the metals react with water and dilute acids. The correct order of decreasing activity of the metals Fe, Ca, Al, and Na is: Na > Ca > Al > Fe This is because Na is the most reactive metal, followed by Ca, Al, and Fe. Therefore, is the correct answer. Na (s) + H2O (l) -> NaOH (aq) + 1/2H2 (g) Ca (s) + H2O (l) -> Ca(OH)2 (aq) + H2 (g) Al (s) + 3H2O (l) -> Al(OH)3 (aq) + 3/2H2 (g) Fe (s) + H2O (l) -> Fe(OH)2 (s) + H2 (g)

Karanta bayanin darasi akan Metals And Their Compounds (JAMB)

Metals And Their Compounds

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Tambaya 48 Rahoto

A few drops of concentrated PCI are added to about 10cm3 of a solution of pH 3.4. The pH of the resulting mixtures is?

less than 3.4

greater than 3.4

unaltered Amsar da ta dace

the same as that of pure water

Bayanin Amsa

Karanta bayanin darasi akan Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

Duba Amsa

Tambaya 49 Rahoto

Which of the following physical properties decreases down a group in the periodic table?

Atomic radius

Ionic radius Amsar da ta dace

Electropositivity

Electronegativity

Bayanin Amsa

Karanta bayanin darasi akan Atomic Structure And Bonding (JAMB)