JAMB UTME - Economics - 2018

Economics seeks to study the relationship between ends and means. Ends are unlimited while the means are limited. Scarcity means resources are limited in relation to the ends. Economics therefore seek is concerned with allocating limited resources among the competing and unlimited wants.

The different types of capital include: Fixed capital, which are assets not used up in the course of production. Circulatory or Working capitals are assets which are used up in the process of production Eg. Raw materials, fuel etc Social capital is the assets provided by the government that aid production. Examples include electricity, water etc.

Saving capital is not a type of capital

Total budget = N100,000,000

  Portion of pie chart covered in degree = 360

  Expenditure on manufacturing = x/N100,000,000 × 3600 = 360

  3600x = 360 × N100,000,000

  x = 360×N100,000,000/3600

  x=N10,000,000

  Therefore, the budget allocated to Manufacturing is N10,000,000

  Total budget = N100,000,000

  Portion of pie chart covered in degree = 720

  Expenditure on Agriculture = x/N100,000,000 × 3600 = 720

  3600x = 720 × N100,000,000

  x = 720 × N100,000,000/3600

  x = N20,000,000

  Therefore, the budget allocated to Agriculture is N20,000,000

  Ratio of expenditure on Manufacturing to Agriculture;

  Ratio = 10,000,000:20,000,000

  =1:2

External economies of scale are economies of scale which a firm enjoys by virtue of being in an industry or environment where for instance, similar firms are located, as this question asks about. They are still economies of scale though, so technically B could also be correct. This is one of those tricky questions.

When a group data is involved, cumulative frequency is used. The formula will be:

  Median=[(N+1)/2]th

  For member of odd number items. That is, where N is odd

  Median=([N/2[N/2+1]th)/2

  For member of odd number items. That is, where N is odd

  Solution:

When a group data is involved, cumulative frequency is used. The formula will be:

  Median=[(N+1)/2]th

  For member of odd number items. That is, where N is odd

  Median=([N/2[N/2+1]th)/2

  For member of odd number items. That is, where N is odd

  Solution: