JAMB UTME - Physics - 2010
Tambaya 1 Rahoto
The diagram above shows a velocity - time graph. The statement that is true about this motion is that the car
Bayanin Amsa
Looking at the velocity-time graph, we can see that the slope of the graph represents the acceleration of the car. When the slope is horizontal, the car has no acceleration (zero acceleration). Between points F and G, the slope is horizontal, which means the car has no acceleration during this time. Therefore, the correct statement is that the car has no acceleration between points F and G.
Tambaya 2 Rahoto
An object is weighted at different locations on the earth. What will be the right observation?
Bayanin Amsa
When an object is weighed at different locations on the Earth, its weight changes but its mass remains constant. Mass is the amount of matter present in an object, while weight is the force exerted on an object due to gravity. The weight of an object depends on the acceleration due to gravity, which varies depending on the location on the Earth. Therefore, is correct: the mass is constant while the weight varies.
Tambaya 3 Rahoto
Two cars moving in the same direction have speeds of 100 kmh-1 and 130 kmh-1 what is the velocity of the faster car as measured by an observer in the slower car?
Bayanin Amsa
The velocity of the faster car as measured by an observer in the slower car can be found by taking the difference between the velocities of the two cars. Since both cars are moving in the same direction, the relative velocity of the faster car with respect to the slower car is given by: 130 km/h - 100 km/h = 30 km/h Therefore, the answer is: 30 kmh-1
Tambaya 4 Rahoto
If a wire 30 cm long is extended to 30.5 cm by a force of 300 N. find the strain energy of wire
Bayanin Amsa
Energy stored in a stretched wire (strain energy)
= average force x extension
= (1)/2 Fe
= (1)/2 x 300 N (30.5 - 30.0) x 10-2 m
= (300)/2 x 0.5 x 10-2 = 0.75J
Tambaya 5 Rahoto
The radioisotope 23592U
decays by emitting two alpha particles, three beta particles and a gamma ray. What is the mass and atomic number of the resulting element?
Tambaya 6 Rahoto
Three capacitors of capacitance 2μF, 4μFand 8μF are connected in parallel and a P.D of 6V is maintained across each capacitor, the total energy stored is
Bayanin Amsa
C = C1 + C2 + C3
= 2 + 4 + 8 = 14μF
V = 6V
Energy = 1/2CV21/2 x 14 x 10-6 x 62
= 2.52 x 10-4 J
Tambaya 7 Rahoto
Two metals P and Q of length l1 and l2 are heated through the same temperature difference. If the ratio of the linear expansivities of P to Q is 2:3 and the ratio of lengths is 3:4. What is the ratio of increase in length of P to Q?
Bayanin Amsa
When two different materials are heated through the same temperature difference, the length of the materials changes. This change in length due to temperature is called thermal expansion. The amount of thermal expansion depends on the material's coefficient of linear expansion, which is denoted by alpha (α). From the problem, we know that the ratio of the linear expansivities of P to Q is 2:3, which means that alpha of P is (2/3) times alpha of Q. Also, the ratio of the lengths of P to Q is 3:4. Let's assume the original lengths of P and Q are 3x and 4x respectively. When heated, the increase in length of P will be αP × l1 = (2/3)αQ × l1 = (2/3)αQ × (3x), since length of P is 3x and the ratio of linear expansivities is 2:3. Similarly, the increase in length of Q will be αQ × l2 = αQ × (4x), since length of Q is 4x. Now, to find the ratio of increase in length of P to Q, we divide the increase in length of P by the increase in length of Q: [(2/3)αQ × (3x)] / [αQ × (4x)] = (2/3) × (3/4) = 1/2 Therefore, the ratio of increase in length of P to Q is 1:2. Hence, the answer is (C) 1:2.
Tambaya 8 Rahoto
The pressure of one mole of an ideal gas of volume 10-2 m3 at a temperature of 27°c is
[molar gas constant = 8.3 J mol-1 k-1]
Bayanin Amsa
T = 27 + 273 = 300 K, volume, V = 10-2 m3 molar gass constant, R = 8.3 Jmol- 1k - 1 number of mole, n = 1
PV = NRT
i.e P = (NRT)/V = (1 x 8.3 x 300)/10-2
= 2.49 x 105 Nm-1
Tambaya 9 Rahoto
During a thunderstorm, the sound is heard over a long time. this phenomenon is referred to as
Bayanin Amsa
When a thunderstorm happens, lightning produces a sudden shockwave that moves through the air as sound waves. Sometimes, these sound waves can bounce off of surfaces such as buildings or mountains and reflect back to the listener, which creates a prolonged sound called reverberation. Diffraction is the bending of sound waves around obstacles, and refraction is the change in direction of sound waves as they pass through materials of different densities. Superposition is the phenomenon that occurs when two or more waves meet and their amplitudes combine, creating a new wave. Therefore, the correct answer to the question is "reverberation."
Tambaya 10 Rahoto
Which of the following is a pure semiconductor?
Bayanin Amsa
The pure semiconductor among the options given is "silicon". A semiconductor is a material that has an electrical conductivity between that of a conductor and an insulator. Silicon is a widely used semiconductor material in electronics due to its abundance and desirable electrical properties. Carbon is not a semiconductor, and transistors are electronic devices made using semiconductor materials, but they are not semiconductors themselves. Phosphorus is also not a pure semiconductor, but it can be used as a dopant to modify the electrical properties of a semiconductor material such as silicon.
Tambaya 11 Rahoto
When a positively charged rod is brought nearer the cap of a positively charged electroscope, the leaves divergence will
Bayanin Amsa
When a positively charged rod is brought near the cap of a positively charged electroscope, the leaves divergence will increase or become more pronounced. This is because the electroscope becomes more positively charged, which leads to increased repulsion between the leaves, causing them to move further apart. Therefore, the correct answer is "diverge".
Tambaya 12 Rahoto
A machine of velocity ratio 6 requires an effort of 400 N to raise a load of 800 N through I m. Find the efficiency of the machine
Bayanin Amsa
The efficiency of a machine is the ratio of the output work to the input work. In this case, the output work is the work done on the load and the input work is the work done by the effort. Given that the velocity ratio of the machine is 6, this means that for every 6 meters of rope pulled by the machine, the load is raised by 1 meter. Therefore, the distance moved by the effort is 6 times the distance moved by the load. Hence, the input work done by the effort is: Input work = effort × distance moved by effort Input work = 400 N × 6 m Input work = 2400 J The work done on the load is the output work. Since the load is raised through a height of 1 m, the output work done on the load is: Output work = load × distance moved by load Output work = 800 N × 1 m Output work = 800 J Therefore, the efficiency of the machine is: Efficiency = output work / input work Efficiency = 800 J / 2400 J Efficiency = 1/3 Efficiency = 0.333 Converting to a percentage, we get: Efficiency = 0.333 × 100% Efficiency = 33.3% Therefore, the answer is 33.3%.
Tambaya 13 Rahoto
The diagram above shows a balanced metre bridge, the value of x is
Bayanin Amsa
1/R = 1/8 + 1/8 = 2/8
∴ R = 4Ω
l/l1 = R/R1
(x)/(100-x) = 4/8
4(100-x) = 8x
400-4x = 8x
400 = 8x + 4x = 12x
x = 400/12 = 33.3cm
Tambaya 14 Rahoto
THe velocity of sound in air at 16oC is 340ms-1. What will it be when the pressure is doubled and its temperature raised to 127oC?
Bayanin Amsa
The velocity of sound in air, V∝√T, where T is absolute temperature
Thus V = K√T or K = V/T
V is independent of pressure and density at a fixed temperature.
∴ V1/√T1 = V2/√T2
T1 = 16 + 273 = 289K, V1 = 340ms-1
T2 = 127 + 273 = 400K, V2 = ?
| 340 | = | V2 |
| √289 | √400 |
| ∴ V2 = | 340√400 |
| _√289 |
= 400m/s
Tambaya 15 Rahoto
In a hydraulic press, the pump piston exerts a pressure of 100 pa on the liquid. what force is exerted in the second piston of cross sectional area 3 m2?
Bayanin Amsa
The hydraulic press works on the principle of Pascal's law, which states that the pressure applied at any point in an enclosed fluid is transmitted uniformly in all directions. In this case, the pump piston exerts a pressure of 100 Pa on the liquid. This pressure is transmitted through the liquid and acts equally in all directions, including on the second piston. The force exerted on the second piston can be calculated using the formula: Force = Pressure x Area where pressure is the pressure applied by the pump piston, and area is the cross-sectional area of the second piston. Substituting the values given in the question, we get: Force = 100 Pa x 3 m^2 Simplifying the equation, we get: Force = 300 N Therefore, the force exerted on the second piston is 300 N.
Tambaya 16 Rahoto
If a container is filled with ice to the brim, what happens to the level of water when the ice completely melts?
Bayanin Amsa
When a container is filled with ice to the brim, some portion of the ice stays above the water level, and some portion of the ice stays below the water level. The portion of ice that is above the water level will melt and occupy the same amount of space as it did in its solid state. However, the portion of ice that is below the water level will melt and the resulting water will occupy less space than the ice did in its solid state because ice has a lower density than water. Therefore, when all the ice melts, the water level in the container will actually decrease slightly. Thus, the correct answer is: "the level of water drops."
Tambaya 17 Rahoto
The sound of an electricity bell dies down slowly when air is slowly pumped out from a bottle because
Bayanin Amsa
Sound wave requires a material medium for its propagation. so when air is being pumped out the density of the medium is being reduced and the sound dies down. when all the air has been pumped out of the glass, no sound will be heard, as sound sound cannot travel through vacuum
Tambaya 18 Rahoto
A bob of weight 0.1 N hangs from a massless string of length 50 cm. A variable horizontal force which increase from zero is applied to pull the bob until the string makes an angle of 60o with the vertical. The work done is
Bayanin Amsa
Length of the string
L = y + x = 0.5m
∴ x = L - y
= distance moved in the direction of force (which is the weight) when the body is released But cos 60o = y/0.5
∴ y = 0.5cos60 = 0.5 x 1/2 = 0.25
∴ x = l - y = 0.5 - 0.25 = 0.25m
Work done = force x distance moved in the direction of force.
= 0.1 x 0.25 = 0.0252J
Tambaya 19 Rahoto
One special advantage of alcohol over mercury as a thermometric liquid is its
Bayanin Amsa
The low freezing point of alcohol, -115°c enable low temperatures to be measured. mercury freezes at 39°c, and cannot be used in countries like Russia where winter temperatures of -40°c are common
Tambaya 20 Rahoto
The diagram above represents balls in an undulating surface. Which of the following option represents positions of stable equilibrium?
Bayanin Amsa
In the given diagram, the balls are in positions where they are influenced by gravity and potential energy. In order for a position to be considered a stable equilibrium position, the ball must return to that position when displaced slightly from it. Looking at the diagram, we can see that positions III, VI, and IX are at the bottom of valleys, where the balls would naturally come to rest and be in a stable equilibrium. Therefore, the correct answer is option III, VI, and IX.
Tambaya 21 Rahoto
In the diagram above, if the south-poles of two magnets strokes steel bar, the polarities at T and V will respectively be
Bayanin Amsa
IN magnetisation by stroking, the last touched has a pole opposite to that of the magnet used. Therefore, the poles T and V are N and N respectively
Tambaya 22 Rahoto
In a discharge tube, most of the gas is pumped out so that electricity is conducted at
Bayanin Amsa
A discharge tube is a device that consists of a partially evacuated tube containing a gas at low pressure, and electrodes at each end. When a high voltage is applied across the electrodes, the gas inside the tube becomes ionized and conducts electricity, producing a glowing plasma. In order for this to happen, most of the gas inside the tube needs to be pumped out, leaving only a small amount of gas at low pressure. Therefore, the correct answer is low pressure.
Tambaya 23 Rahoto
Two inductors of inductances 5 mll and 15 mll are connected in series and a current of 5A flows through them. the total energy stored in the inductor is
Bayanin Amsa
Total inductance,L = L1 + L2 = m
15 + 5 = 20mH = (20)H/1000
1 = 5A
Energy of inductor, (1)/2 L I2
= (1)/2 X (20)/1000 X 5-2
= 0.25 J
Tambaya 24 Rahoto
A car moves with an initial velocity of 25 ms-1 and reaches a velocity of 45 ms-1 in 10s. what is the acceleration of the car?
Bayanin Amsa
To calculate the acceleration of the car, we can use the formula: acceleration = (final velocity - initial velocity) / time In this case, the final velocity is 45 m/s, the initial velocity is 25 m/s, and the time is 10 seconds. Plugging these values into the formula, we get: acceleration = (45 m/s - 25 m/s) / 10 s acceleration = 20 m/s / 10 s acceleration = 2 m/s^2 Therefore, the acceleration of the car is 2 m/s^2. Answer: 2 ms-2
Tambaya 25 Rahoto
In comparing the camera and the human eye, the film of the camera function as the
Bayanin Amsa
The film of a camera functions like the retina of the human eye. The retina is a layer of tissue at the back of the eye that contains photoreceptor cells, which detect light and convert it into neural signals that are sent to the brain for processing. Similarly, the film in a camera records the light that enters the camera and captures the image that is being taken. Both the retina and the camera film are critical in creating a visual representation of the world around us.
Tambaya 26 Rahoto
In the diagram above, a 200 W bulb is lighted by a 240 V a.c mains supply. If 1kwh is sold at ₦40, the cost of keeping the bulb lighted for a day is
Bayanin Amsa
Energy consumed = power x time
= 200W x 24hr = 4800wh
= 4.8 kwh
But 1 kwh cost N40
∴ 4.8kwh costs 4.8 x 40
= N192
Tambaya 27 Rahoto
Transistors are used for the
Bayanin Amsa
Transistors are electronic components that are commonly used for amplifying signals. They are capable of amplifying weak signals to higher levels and are therefore used in a variety of electronic devices such as radios, televisions, and computers. While transistors can be used for rectification of signals or conversion of a.c to d.c or d.c to a.c, their most common use is for signal amplification.
Tambaya 28 Rahoto
A galvanometer with full-scale deflection of 10 mA is to be converted to a voltmeter with full-scale deflection of 5v. the resistance of the galvanometer is
Bayanin Amsa
R = (Vg)/lg = G, where lg = current through galvanometer
R = resistance of the multiplier
G = resistance of the galvanometer
∴ G = (vg-R)/lg 5(1000/10) - 490 = 500 -490 = 10Ω
Tambaya 29 Rahoto
A vapour is said to be saturated when
Bayanin Amsa
A vapor is said to be saturated when a dynamic equilibrium exists between liquid molecules and the vapor molecules. This means that the rate of evaporation of liquid is equal to the rate of condensation of vapor at a given temperature and pressure. In other words, the vapor is holding as much moisture as it can at that temperature and pressure. If the temperature or pressure changes, the saturation point will also change.
Tambaya 30 Rahoto
Power supply is transmitted at a very high voltage and low current in order to
Bayanin Amsa
H eat generated in a wire carrying current, H = 12 Rt.
so, when voltage is high and current is low heat generated in the wire will be minimal.
Therefore, high voltage and low current prevent overheating of the coil.
Tambaya 31 Rahoto
A hydrometer is an instrument used in measuring
Bayanin Amsa
The instrument used in measuring relative density is hydrometer
Tambaya 32 Rahoto
The ground stated energy for the hydrogen atom is 5.44 x 10-19J . If an electron drops from zero energy to ground state, calculate the frequency of the emitted radiation. [h = 6.6 x 10-34 Js]
Bayanin Amsa
When an electron drops from a higher energy level to a lower energy level, energy is released in the form of electromagnetic radiation (photons). The frequency of the radiation can be calculated using the formula: E = hf where E is the energy of the photon, h is Planck's constant, and f is the frequency of the radiation. In this question, the energy of the photon is equal to the difference between the initial energy level (zero) and the final energy level (5.44 x 10^-19 J): E = 5.44 x 10^-19 J Planck's constant is given as h = 6.6 x 10^-34 Js. Substituting these values into the formula, we get: 5.44 x 10^-19 J = (6.6 x 10^-34 Js) x f Solving for f, we get: f = (5.44 x 10^-19 J) / (6.6 x 10^-34 Js) f ≈ 8.24 x 10^14 Hz Therefore, the frequency of the emitted radiation is approximately 8.24 x 10^14 Hz, which is not one of the given options.
Tambaya 33 Rahoto
Dispersion occurs when white light passes through a glass prism because of the
Bayanin Amsa
When white light passes through a glass prism, it gets separated into its constituent colours, forming a rainbow-like spectrum. This is because different colours of light travel at different speeds through the glass due to the phenomenon of refraction. The amount of bending of the different colours of light is different because each colour has a different wavelength and thus travels at a different speed. Therefore, the dispersion occurs due to the different speeds of the colours in the glass.
Tambaya 34 Rahoto
Two metals P and Q are heated through the same temperature difference. If the ratio of the linear expansivities of P to Q is 2:3 and the ratio of their
Length is 3: 4 respectively, the ratio of the increase in lengths of P to Q is
Tambaya 35 Rahoto
The surfaces of conveyor belts are made rough so as to
Bayanin Amsa
The surfaces of conveyor belts are made rough to prevent the loads from slipping. The rough surface provides more friction between the belt and the load, thereby preventing it from sliding off the conveyor belt. This is important for the safety of workers and to ensure that products are transported effectively without any damage or loss.
Tambaya 36 Rahoto
The small droplet of water that forms on the grass in the early hours of the morning is
Bayanin Amsa
The correct answer is "dew." Dew is formed when the temperature of the surface, such as grass or leaves, falls below the dew point temperature of the surrounding air. Water vapor in the air then condenses into small droplets on the surface. Dew is commonly seen in the early morning hours when the temperature is coolest and the humidity is highest. Hail, fog, and mist are different forms of precipitation or atmospheric moisture that form under different conditions.
Tambaya 37 Rahoto
Heat is radiated by hot objects in the form
Bayanin Amsa
Heat is a type of energy that is generated by the movement of atoms and molecules within an object. When an object is hot, it radiates this heat energy outwards in the form of electromagnetic waves. These waves are known as infrared rays. Therefore, the correct option is "infrared rays."
Tambaya 38 Rahoto
A cell of e.m.f 12V and internal resistance 4Ω is connected to an external resistor of resistance 2Ω. Find the current flow.
Bayanin Amsa
The current flow can be found using Ohm's Law, which states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. First, we can find the total resistance of the circuit by adding the external resistor to the internal resistance of the cell: total resistance = external resistance + internal resistance = 2Ω + 4Ω = 6Ω Next, we can use Ohm's Law to find the current flow: current = voltage / resistance current = 12V / 6Ω = 2A Therefore, the current flow in the circuit is 2A. Answer: 2 A
Tambaya 39 Rahoto
The wavelength of a wave traveling with a velocity of 420 ms-1 is 42 m. what is its period?
Bayanin Amsa
The formula for the speed of a wave is given by v = λ/T, where v is the velocity, λ is the wavelength, and T is the period. We are given that the velocity is 420 m/s and the wavelength is 42 m. We can use these values to solve for the period. Rearranging the formula, we get: T = λ/v Substituting the given values, we get: T = 42 m / 420 m/s Simplifying, we get: T = 0.1 s Therefore, the period of the wave is 0.1 seconds. Answer: 0.1 s
Tambaya 40 Rahoto
Which of the following has no effect on radiation?
Bayanin Amsa
Radiation depends on nature of the surface area and temperature. It is independent of density.
Tambaya 41 Rahoto
Which of the following is used for the correction of short sightedness?
Bayanin Amsa
Short-sightedness, also known as myopia, is a condition where a person is able to see nearby objects clearly but distant objects appear blurry. It is caused by an elongated eyeball or a misshapen cornea, which causes the light entering the eye to focus in front of the retina instead of on it. To correct myopia, a concave lens is used. A concave lens is thinner at the center than at the edges, which causes the light entering the eye to diverge before it reaches the cornea, allowing the image to focus correctly on the retina. Therefore, the correct answer is concave lens.
Tambaya 43 Rahoto
A stone and a feather are dropped from the same height above the earth surface. ignoring air resistance, which of the following is correct?
Bayanin Amsa
The acceleration of free fall due to gravity is independent of mass of the body. Therefore, ignoring air resistance, which affects feather more than the stone, the stone and the feather will both reach the ground at the same time
Tambaya 44 Rahoto
In Faradays law of electrolysis, a graph of the mass deposited against the quantity of electricity is plotted. The slope of the graph gives
Bayanin Amsa
The slope of the graph of the mass deposited against the quantity of electricity in Faraday's law of electrolysis gives the electrochemical equivalent. The electrochemical equivalent is a measure of the amount of substance produced by the passage of one coulomb of electricity through an electrolyte. In other words, it represents the amount of substance that is deposited or liberated at an electrode per unit charge passed through the electrolyte during electrolysis. Therefore, the correct option is "the electrochemical equivalent."
Tambaya 45 Rahoto
Three 4Ω resistors connected in parallel have a potential difference of 16 V applied across them. What is the total current in the circuit?
Bayanin Amsa
When resistors are connected in parallel, the voltage across each resistor is the same, while the total current through the circuit is the sum of the current through each resistor. In this case, we have three 4Ω resistors connected in parallel, with a potential difference of 16 V applied across them. Using Ohm's Law, we can calculate the current through one resistor as I = V/R, where V is the voltage across the resistor, and R is the resistance of the resistor. For each of the three resistors, the current through them would be I = 16 V / 4 Ω = 4 A. Since the resistors are connected in parallel, the total current through the circuit is the sum of the current through each resistor, which is 4 A + 4 A + 4 A = 12 A. Therefore, the total current in the circuit is 12 A. Answer is correct.
Tambaya 46 Rahoto
The density of a certain oil on frying becomes
0.4 kgm-3 with the volume of 20m3. what will be its initial volume when its initial density is 0.8 kgm-3 assuming no loss of oil due to spillage?
Bayanin Amsa
The density of an object is equal to its mass divided by its volume. In this case, the density of the oil after frying is 0.4 kg/m³ and its volume is 20 m³. Therefore, we can calculate the mass of the oil as: mass = density x volume = 0.4 kg/m³ x 20 m³ = 8 kg Now we can use the formula for density to find the initial volume of the oil, assuming no loss of oil due to spillage. If the initial density of the oil was 0.8 kg/m³, then we can find the initial volume as: initial volume = mass / initial density = 8 kg / 0.8 kg/m³ = 10 m³ Therefore, the initial volume of the oil was 10 m³. The correct answer is "10 kgm-3".
Tambaya 47 Rahoto
An object is embedded in a block of ice, 10 cm below the plane surface. if the refractive index of the ice is 1.50, the apparent depth below the surface is
Bayanin Amsa
When light travels from one medium to another medium of different optical density, its path gets bent at the interface between the two media. This phenomenon is called refraction. The bending occurs because the speed of light is different in each medium. The speed of light is slower in a denser medium than in a less dense one. When an object is placed in a denser medium like ice, the apparent depth of the object appears to be higher than its actual depth. The amount of apparent depth increase depends on the refractive index of the medium. The formula for the apparent depth is given by: Apparent depth = Actual depth / Refractive index Here, the actual depth is given as 10 cm, and the refractive index of ice is 1.50. By substituting these values in the formula, we get: Apparent depth = 10 / 1.50 = 6.67 cm Therefore, the answer is 6.67 cm.
Tambaya 48 Rahoto
The accurate measurement of the relative density of a substance in its powdered form is done with a beam balance and
Bayanin Amsa
To accurately measure the relative density of a substance in its powdered form, a density bottle is used. A density bottle is a specialized glass bottle designed to hold a specific volume of liquid at a specific temperature. By measuring the mass of an empty density bottle, then filling it with the powdered substance and measuring the mass again, the mass of the substance can be determined. The volume of the substance can then be determined by filling the density bottle with a liquid of known density, such as water, and measuring the mass again. The relative density can then be calculated as the mass of the substance divided by the mass of an equal volume of water.
