WAEC SSCE - Physics - 1995 (Objective)

Question 1 Rapport

How much heat is required to convert 20 g of ice at 0^oC to water at the same temperature? (Specific latent heat of ice = 336 J g^-1)

1.35 x 10³J

5.38 x 10³J

6.72 x 10³J Bonne réponse

7.06 x 10³J

8.06 x 10³J

Détails de la réponse

To convert ice at 0°C to water at the same temperature, we need to supply heat energy to the ice to overcome the latent heat of fusion. The amount of heat energy required is given by: Q = mL where Q is the heat energy, m is the mass of ice, and L is the specific latent heat of fusion of ice. In this case, the mass of ice is 20 g and the specific latent heat of fusion of ice is 336 J g^-1. So, the heat energy required is: Q = 20 g x 336 J g^-1 = 6,720 J Therefore, the amount of heat required to convert 20 g of ice at 0°C to water at the same temperature is 6.72 x 10^3 J. Therefore, the correct option is (c) 6.72 x 10^3 J.






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