WAEC SSCE - Physics - 1988 (Objective)

Question 1 Rapport

A given mass of gas has a pressure of 80Nm^-2 at a temperature of 47^oC. If the temperature is reduced to 27^oC with the volume remaining constant, the new pressure is

46.0 Nm^-2

75.0 Nm^-2 Bonne réponse

80.0 Nm^-2

85.3 Nm^-2

139.4 Nm^-2

Détails de la réponse

The given gas is at a pressure of 80 Nm^-2 and a temperature of 47^oC. To find the new pressure at a temperature of 27^oC with constant volume, we can use the ideal gas law: P₁/T₁ = P₂/T₂ where P₁ is the initial pressure, T₁ is the initial temperature, P₂ is the final pressure, and T₂ is the final temperature. Substituting the given values into the equation, we have: 80 Nm^-2 / (47 + 273) K = P₂ / (27 + 273) K Simplifying the equation, we get: P₂ = 80 Nm^-2 × (27 + 273) K / (47 + 273) K P₂ = 75 Nm^-2 Therefore, the new pressure at a temperature of 27^oC with constant volume is 75 Nm^-2.






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