Solving Equations And Inequalities
Resumen
An equation is a question about a number: which value makes these two expressions agree? Solving it is the process of stripping away everything that has been done to the unknown until it stands alone. That is the mechanical half of this topic. The other half is harder and worth more marks: turning a situation described in words, or drawn as a shape, into the equation in the first place.
You will solve linear equations, including those with brackets and with the unknown on both sides, solve quadratic equations by factorising, solve two linear simultaneous equations in two variables, find approximate solutions from a graph, translate simple situations or procedures into algebraic expressions or formulae, derive and solve equations from geometrical problems and problems set in context, and solve linear inequalities and represent the solution set on a number line. On the Extension Tier you will add completing the square and the quadratic formula, simultaneous equations where one is quadratic, inequalities in two variables and quadratic inequalities, and the graphical representation of a solution set.
Objetivos
- [Core] solve linear equations in one unknown algebraically
- [Core] find approximate solutions using a graph (Notes: including use of brackets and those with the unknown on both sides of the equation)
- [Core] solve quadratic equations algebraically by factorising
- [Core] find approximate solutions using a graph
- [Extension] including completing the square and by using the quadratic formula
- [Core] solve two linear simultaneous equations in two variables algebraically
- [Core] find approximate solutions using a graph
- [Extension] including one linear and one quadratic
- [Core] translate simple situations or procedures into algebraic expressions or formulae
- [Core] derive an equation (or two simultaneous equations), solve the equation(s) and interpret the solution (Notes: including the solution of geometrical problems and problems set in context)
- [Core] solve linear inequalities in one variable
- [Core] represent the solution set on a number line
- [Extension] solve linear inequalities in one or two variable(s), and quadratic inequalities in one variable
- [Extension] represent the solution set on a number line and on a graph (Notes: students should know the conventions of an open circle on a number line for a strict inequality and a closed circle for an included boundary. In graphical work the convention of a dashed line for strict inequalities and a solid line for an included inequality will be required)
Mapa mental
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Nota de la lección
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Evaluación de la lección
Felicitaciones por completar la lección del Solving Equations And Inequalities. Ahora que has explorado el conceptos e ideas clave, es hora de poner a prueba tus conocimientos. Esta sección ofrece una variedad de prácticas Preguntas diseñadas para reforzar su comprensión y ayudarle a evaluar su comprensión del material.
Te encontrarás con una variedad de tipos de preguntas, incluyendo preguntas de opción múltiple, preguntas de respuesta corta y preguntas de ensayo. Cada pregunta está cuidadosamente diseñada para evaluar diferentes aspectos de tu conocimiento y habilidades de pensamiento crítico.
Utiliza esta sección de evaluación como una oportunidad para reforzar tu comprensión del tema e identificar cualquier área en la que puedas necesitar un estudio adicional. No te desanimes por los desafíos que encuentres; en su lugar, míralos como oportunidades para el crecimiento y la mejora.
- Circle the equation with roots 4 and -8. A. 4x(x - 8) = 0 B. (x - 4)(x + 8) = 0 C. x^2 - 32 = 0 D. (x + 4)(x - 8) = 0 Answer: B
- A number line shows a closed circle at -7, an open circle at 6, and the values between them shaded. Which inequality does it show? A. -7 < x < 6 B. -7 is less than or equal to x, and x < 6 C. -7 < x, and x is less than or equal to 6 D. -7 is less than or equal to x, and x is less than or equal to 6 Answer: B
- Solve 5(x + 4) = 3(x + 7) + 2. A. x = 0.5 B. x = 1.5 C. x = 3 D. x = 21.5 Answer: B
- How many solutions does x^2 = 5x have? A. none B. one C. two D. infinitely many Answer: C
- Which method must be used to solve the pair 4x + y = -3 and y = x^2 + 2x + 5? A. adding the two equations B. subtracting the two equations C. substitution D. trial and improvement Answer: C
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