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Pregunta 1 Informe
(a) State an indicator suitable for the titration of;
(i) dilute HCl and NaOH\(_{3(aq)}\)
(ii) dilute CH\(_3\)COOH and KOH\(_{(aq)}\)
(iii) dilute HCl and NH\(_{3(aq)}\).
Give a reason for your answer in each case.
(b) Calculate the volume of water that would be added to 50 cm\(^3\) of 0.10 mol dm\(^{-3}\) of HCI to dilute it to 0.010 mol dm \(^{-3}\)
(c) Name one gas that could be used to demonstrate the fountain experiment.
(a) Suitable indicators for the titrations
(b) Volume of water to add for dilution
Using \(C_1V_1 = C_2V_2\):
\[0.10 \times 50 = 0.010 \times V_2\]
\[V_2 = \frac{0.10 \times 50}{0.010} = 500\text{ cm}^3\]
Volume of water added \(= 500 - 50 = 450\text{ cm}^3\).
(c) Gas for the fountain experiment
Ammonia (NH3), because it is extremely soluble in water (hydrogen chloride gas may also be used).
Detalles de la respuesta
(a) Suitable indicators for the titrations
(b) Volume of water to add for dilution
Using \(C_1V_1 = C_2V_2\):
\[0.10 \times 50 = 0.010 \times V_2\]
\[V_2 = \frac{0.10 \times 50}{0.010} = 500\text{ cm}^3\]
Volume of water added \(= 500 - 50 = 450\text{ cm}^3\).
(c) Gas for the fountain experiment
Ammonia (NH3), because it is extremely soluble in water (hydrogen chloride gas may also be used).
Pregunta 2 Informe
All your burette readings (initial and final) as well as the size size of your pipette, must be recorded but no account of experimental procedure is required. All calculations must be done in your answer book.
A is a solution containing \(1.04\text{ g HCl}\) per \(500\text{ cm}^3\) of solution. B was prepared by diluting \(50.0\text{ cm}^3\) of a saturated solution of \(\mathrm{Na}_2\mathrm{CO}_3\) at room temperature to \(1000\text{ cm}^3\)
(a) Put A into the burette and titrate it against \(20.0\text{ cm}^3\) or \(25.0\text{ cm}^3\) portions of B using methyl orange as indicator. Repeat the titration to obtain consistent titres. Tabulate your results and calculate the average volume of acid used.
9b) From your results and information provided above, calculate the;
(i) concentration of A in \(\mathrm{mol\,dm}^{-3}\)
(ii) concentration of B in \(\mathrm{mol\,dm}^{-3}\)
(iii) solubility of \(\mathrm{Na}_2\mathrm{CO}_3\) in \(\mathrm{mol\,dm}^{-3}\)
(iv) volume of \(\mathrm{CO}_2\) that would be liberated from \(1\text{ dm}^3\) of B if the titration were carried out at s.t.p.
The equation for the reaction is \(\mathrm{Na}_2\mathrm{CO}_{3(aq)} + 2\mathrm{HCl}_{(aq)} \to 2\mathrm{NaCl}_{(aq)} + \mathrm{H}_2\mathrm{O}_{(l)} + \mathrm{CO}_{2(g)}\)
[H = 1; C = 12; O = 16; Na = 23; Cl = 35.5; Molar volume of gas at s.t.p = \(22.4\text{ dm}^3\)]
(a) Titration results
| Rough | 1 | 2 | 3 | |
|---|---|---|---|---|
| Final reading (cm3) | 25.00 | 24.90 | 34.90 | 24.90 |
| Initial reading (cm3) | 0.00 | 0.00 | 10.00 | 0.00 |
| Volume of A used (cm3) | 25.00 | 24.90 | 24.90 | 24.90 |
Average volume of acid A used = (24.90 + 24.90 + 24.90) / 3 = 24.90 cm3.
Equation: Na2CO3(aq) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g)
(b)(i) Concentration of A
A contains 1.04 g HCl per 500 cm3 = 2.08 g dm-3. Molar mass of HCl = 1 + 35.5 = 36.5 g mol-1.
CA = 2.08 / 36.5 = 0.057 mol dm-3.
(b)(ii) Concentration of B
n(HCl) = 0.057 × 24.90 / 1000 = 1.42 × 10-3 mol. From the equation, n(Na2CO3) = half of n(HCl) = 7.10 × 10-4 mol in the 25.0 cm3 portion of B.
CB = 7.10 × 10-4 × 1000 / 25.0 = 0.0284 mol dm-3.
(b)(iii) Solubility of Na2CO3
B was made by diluting 50.0 cm3 of the saturated solution to 1000 cm3, a 20-fold dilution.
Solubility = 0.0284 × 20 = 0.568 mol dm-3.
(b)(iv) Volume of CO2 from 1 dm3 of B at s.t.p.
n(Na2CO3) in 1 dm3 of B = 0.0284 mol, and each mole gives 1 mole of CO2.
V(CO2) = 0.0284 × 22.4 = 0.64 dm3.
Detalles de la respuesta
(a) Titration results
| Rough | 1 | 2 | 3 | |
|---|---|---|---|---|
| Final reading (cm3) | 25.00 | 24.90 | 34.90 | 24.90 |
| Initial reading (cm3) | 0.00 | 0.00 | 10.00 | 0.00 |
| Volume of A used (cm3) | 25.00 | 24.90 | 24.90 | 24.90 |
Average volume of acid A used = (24.90 + 24.90 + 24.90) / 3 = 24.90 cm3.
Equation: Na2CO3(aq) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g)
(b)(i) Concentration of A
A contains 1.04 g HCl per 500 cm3 = 2.08 g dm-3. Molar mass of HCl = 1 + 35.5 = 36.5 g mol-1.
CA = 2.08 / 36.5 = 0.057 mol dm-3.
(b)(ii) Concentration of B
n(HCl) = 0.057 × 24.90 / 1000 = 1.42 × 10-3 mol. From the equation, n(Na2CO3) = half of n(HCl) = 7.10 × 10-4 mol in the 25.0 cm3 portion of B.
CB = 7.10 × 10-4 × 1000 / 25.0 = 0.0284 mol dm-3.
(b)(iii) Solubility of Na2CO3
B was made by diluting 50.0 cm3 of the saturated solution to 1000 cm3, a 20-fold dilution.
Solubility = 0.0284 × 20 = 0.568 mol dm-3.
(b)(iv) Volume of CO2 from 1 dm3 of B at s.t.p.
n(Na2CO3) in 1 dm3 of B = 0.0284 mol, and each mole gives 1 mole of CO2.
V(CO2) = 0.0284 × 22.4 = 0.64 dm3.
Pregunta 3 Informe
Credit will be given for strict adherence to the instructions, for observations precisely recorded, and for accurate inferences. All tests, Observations, and inferences must be clearly entered in your answer book, in ink, at the time they are made.
C is a mixture of two inorganic salts. Carry out the following exercises on C. Record your observations and identify any gas(es) evolved. State the conclusion you draw from the result of each test.
(a) Put all of C in a test tube and add about \(10\ \text{cm}^3\) of distilled water. Stir, filter, and keep the filtrate and the residue.
(b) Put the residue into a test tube and add about \(5\ \text{cm}^3\) of dilute HCl. Shake to dissolve
(i) To about \(2\ \text{cm}^3\) of the solution, add \(\mathrm{NaOH_{(aq)}}\) in drops and then in excess
(ii) To another \(2\ \text{cm}^3\) portion of the solution, add \(\mathrm{NH_{3(aq)}}\) in drops and then in excess.
(c) To about \(2\ \text{cm}^3\) portion of the filtrate, add few drops of dilute \(\mathrm{HNO_3}\), and then \(\mathrm{AgNO_{3(aq)}}\) a followed by aqueous \(\mathrm{NH_3}\) in excess.
Results for specimen C
| Test | Observation | Inference |
|---|---|---|
| (a) Add about 10 cm3 of distilled water to all of C, stir and filter. | C dissolves partly. A white residue remains on the filter paper and a colourless filtrate is obtained. | C contains a water-soluble salt and a water-insoluble white salt. |
| (b) Add dilute HCl to the residue and shake. | Effervescence occurs and the residue dissolves, giving a colourless solution. The colourless gas turns limewater milky. | The gas is carbon dioxide, CO2. A carbonate ion, CO32−, is present in the insoluble salt. |
| (b)(i) To 2 cm3 of the solution from (b), add NaOH(aq) dropwise and then in excess. | A white gelatinous precipitate forms. The precipitate dissolves in excess NaOH(aq). | Zn2+, Al3+ or Pb2+ may be present. |
| (b)(ii) To a fresh 2 cm3 portion of the solution from (b), add NH3(aq) dropwise and then in excess. | A white gelatinous precipitate forms. The precipitate dissolves in excess aqueous ammonia. | Zn2+ is confirmed. |
| (c) To 2 cm3 of the filtrate, add dilute HNO3, then AgNO3(aq), followed by excess NH3(aq). | There is no visible reaction with dilute HNO3. A white precipitate forms on adding AgNO3(aq); it dissolves in excess NH3(aq). | Cl− is present and is confirmed. |
Conclusion: C is a mixture of insoluble zinc carbonate, ZnCO3, and a soluble chloride salt.
Detalles de la respuesta
Results for specimen C
| Test | Observation | Inference |
|---|---|---|
| (a) Add about 10 cm3 of distilled water to all of C, stir and filter. | C dissolves partly. A white residue remains on the filter paper and a colourless filtrate is obtained. | C contains a water-soluble salt and a water-insoluble white salt. |
| (b) Add dilute HCl to the residue and shake. | Effervescence occurs and the residue dissolves, giving a colourless solution. The colourless gas turns limewater milky. | The gas is carbon dioxide, CO2. A carbonate ion, CO32−, is present in the insoluble salt. |
| (b)(i) To 2 cm3 of the solution from (b), add NaOH(aq) dropwise and then in excess. | A white gelatinous precipitate forms. The precipitate dissolves in excess NaOH(aq). | Zn2+, Al3+ or Pb2+ may be present. |
| (b)(ii) To a fresh 2 cm3 portion of the solution from (b), add NH3(aq) dropwise and then in excess. | A white gelatinous precipitate forms. The precipitate dissolves in excess aqueous ammonia. | Zn2+ is confirmed. |
| (c) To 2 cm3 of the filtrate, add dilute HNO3, then AgNO3(aq), followed by excess NH3(aq). | There is no visible reaction with dilute HNO3. A white precipitate forms on adding AgNO3(aq); it dissolves in excess NH3(aq). | Cl− is present and is confirmed. |
Conclusion: C is a mixture of insoluble zinc carbonate, ZnCO3, and a soluble chloride salt.
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