Cargando....






Mantén pulsado para arrastrar.
Haz clic aquí para cerrar

JAMB UTME - Mathematics - 1985

Pregunta 1 Informe

The ratio of the length of two similar rectangular blocks is 2 : 3. If the volume of the larger block is 351cm3, then the volume of the other block is

234.00 cm3

526.50 cm3

166.00 cm3

687cm3

Detalles de la respuesta

Let x represent total vol. 2 : 3 = 2 + 3 = 5
$\frac{3}{5}$ x = 351
x = $\frac{351 \times 5}{3}$
= 585
Volume of smaller block = $\frac{2}{3}$ x 585
= 234.00

Lee la nota de la lección en Polynomials (JAMB)

Polynomials

Ver respuesta

Pregunta 2 Informe

22\( \frac{1}{2} \)% of the Nigerian Naira is equal to 17\( \frac{1}{10} \)% of a foreign currency M. What is the conversion rate of the M to the Naira?

1M = 1

\frac{15}{57}

N

1M = 38

\frac{1}{4}

N

1M = 1

\frac{18}{57}

N

1M = 384

\frac{3}{4}

N

Detalles de la respuesta

N = 22 $\frac{1}{2}$ %, M = 17 $\frac{1}{10}$ %
M = $\frac{171}{10}$ %, N = $\frac{45}{2}$
$\frac{45}{2}$ x $\frac{10}{171}$
= $\frac{225}{171}$
= 1 $\frac{54}{171}$
= 1 $\frac{18}{57}$

Lee la nota de la lección en Percentages (WAEC)

Lee la nota de la lección en Financial Arithmetic (WAEC)

Percentages

Financial Arithmetic

Ver respuesta

Pregunta 3 Informe

If \(a\left\{\frac{x+1}{x-2}-\frac{x-1}{x+2}\right\}=6x\). Find a in its simplest form

x2 - 1

x2 + 1

x2 + 4

x2 - 4

1

Detalles de la respuesta

a{ $\frac{x + 1}{x - 2} - \frac{x - 1}{x + 2}$ } = a{ $\frac{(x + 1) (x + 2) - (x - 1) (x - 2)}{(x - 2) (x + 2)}$ }
= 6
$\frac{6 x}{x^{2} - 4}$ = 6x
a = x2 - 4

Lee la nota de la lección en Algebraic Expressions (WAEC)

Algebraic Expressions

Ver respuesta

Pregunta 4 Informe

If the hypotenuse of right angled isosceles triangle is 2, what is the length of each of the other sides?

\sqrt{2}

\frac{1}{2}

22

1

2 - 1

Detalles de la respuesta

45o = $\frac{x}{2}$ , Since 45o = $\frac{1}{\sqrt{2}}$
x = 2 x $\frac{1}{\sqrt{2}}$
= $\frac{2 \sqrt{2}}{2}$
= $\sqrt{2}$

Lee la nota de la lección en Angles And Intercepts On Parallel Lines (WAEC)

Lee la nota de la lección en Statistics (WAEC)

Lee la nota de la lección en Angles (WAEC)

Angles And Intercepts On Parallel Lines

Ver respuesta

Pregunta 5 Informe

In the figure, the area of the shaded segment is

3

π

9

\frac{\sqrt{3}}{4}

3

π - 3 \frac{\sqrt{3}}{4}

\frac{(\sqrt{3 - π)}}{4}

π + \frac{9 \sqrt{3}}{4}

Detalles de la respuesta

Area of sector = $\frac{120}{360} \times π \times (3)^{2} = 3 π$

Area of triangle = $\frac{1}{2} \times 3 \times 3 \times \sin 120^{o}$

= $\frac{9}{2} \times \frac{\sqrt{3}}{2} = \frac{9 \sqrt{3}}{4}$

Area of shaded portion = 3 $π - \frac{9 \sqrt{3}}{4}$

= 3 $π - 3 \frac{\sqrt{3}}{4}$

Lee la nota de la lección en Volumes (WAEC)

Lee la nota de la lección en Loci (WAEC)

Ver respuesta

Pregunta 6 Informe

PRSQ is a trapezium of area 14cm2 in which PQ||RS. If PQ = 4cm and SR = 3cm, Find the area of SQR in cm2

7.0

6.0

5.2

5.0

Detalles de la respuesta

Area of trapezium = 14cm2
Area of trapezium = $\frac{1}{2}$ (a + b)h
14 = $\frac{1}{2}$ (4 + 3)h
14 = $\frac{7}{2}$ h
h = $\frac{14 \times 2}{7}$
= 4
Area of SQR = $\frac{1}{2}$ (3 x 4)
= $\frac{12}{2}$
= 6.0

Ver respuesta

Pregunta 8 Informe

The number of goals scored by a football team in 20 matches is shown below:

No. of goals	0	1	2	3	4	5
No. of matches	3	5	7	3	1	0

What are the values of the mean and the mode respectively?

(1.75, 5)

(1.75, 2)

(1.75, 1)

(65, 74)

Detalles de la respuesta

$\begin{array}{cc} x & f & f x \\ 0 & 3 & 0 \\ 1 & 5 & 5 \\ 2 & 7 & 14 \\ 3 & 4 & 12 \\ 4 & 1 & 4 \\ 5 & 0 & 0 \end{array}$
$\sum f$ = 20
$\sum f x$ = 35
Mean = $\frac{\sum f x}{\sum f}$
= $\frac{35}{20}$
= $\frac{7}{4}$
= 1.75
Mode = 2
= 1.75, 2

Lee la nota de la lección en Probability (WAEC)

Lee la nota de la lección en Statistics (WAEC)

Probability

Ver respuesta

Pregunta 9 Informe

In the equation below, Solve for x if all the numbers are in base 2: \(\frac{11}{x} = \frac{1000}{x+101}\)

101

11

110

111

10

Detalles de la respuesta

$\frac{11}{x}$ = $\frac{1000}{x + 101}$ = 11(x + 101)
1000x = 11x + 1111
1000x - 11x = 1111
101x = 1111
x = $\frac{1111}{101}$
x = 11

Lee la nota de la lección en Number Bases (WAEC)

Number Bases

Ver respuesta

Pregunta 10 Informe

Without using table, calculate the value of 1 + sec2 30o

2

\frac{1}{3}

\frac{2}{15}

\frac{5}{3}

3

\frac{1}{2}

Detalles de la respuesta

1 + sec2 30o = sec 30o
= $\frac{2}{\sqrt{3}}$
$\frac{(2)^{2}}{3}$
= $\frac{4}{3}$
1 + sec2 30o = sec 30o
= 1 + $\frac{4}{\sqrt{3}}$
= 2 $\frac{1}{3}$

Lee la nota de la lección en Sine, Cosine And Tangent Of An Angle (WAEC)

Lee la nota de la lección en Introductory Calculus (WAEC)

Lee la nota de la lección en Loci (JAMB)

Lee la nota de la lección en Matrices And Determinants (JAMB)

Sine, Cosine And Tangent Of An Angle

Introductory Calculus

Matrices And Determinants

Ver respuesta

Pregunta 11 Informe

Two points X and Y both on latitude \(60^\circ\text{S}\) have longitude \(147^\circ\text{E}\) and \(153^\circ\text{W}\) respectively. Find to the nearest kilometer the distance between X and Y measured along the parallel of latitude (Take \(2\pi R = 4 \times 10^4\text{ km}\), where R is the radius of the earth)

16667km

28850km

8333km

2233km

Detalles de la respuesta

Length of an area = $\frac{θ}{360}$ × 2 $π$ r
Longitude difference = 147 + 153 = 300oN
distance between xy = $\frac{θ}{360}$ × 2 $π$ R cos60o
= $\frac{300}{360}$ × 4 × 104 × $\frac{1}{2}$
= 1.667 × 104km (1667 km)

Lee la nota de la lección en Circles (WAEC)

Ver respuesta

Pregunta 12 Informe

A bag contains 4 white balls and 6 red balls. Two balls are taken from the bag without replacement. What is the probability that they are both red?

\frac{2}{3}

\frac{2}{15}

\frac{1}{2}

\frac{1}{3}

Detalles de la respuesta

P(R1) = $\frac{6}{10}$
= $\frac{2}{3}$
P(R1 n R11) = P(both red)
$\frac{3}{5}$ x $\frac{5}{9}$
= $\frac{1}{3}$

Lee la nota de la lección en Probability (WAEC)

Lee la nota de la lección en Probability (JAMB)

Probability

Probability

Ver respuesta

Pregunta 13 Informe

Find the area of a regular hexagon inscribed in a circle of radius 8cm

16

\sqrt{3}

cm2

96

\sqrt{3}

cm2

192

\sqrt{3}

cm2

16

\sqrt{3}

cm2

33cm2

Detalles de la respuesta

Area of a regular hexagon = 8 x 8 x sin 60o
= 32 x $\frac{\sqrt{3}}{2}$ =
Area = 16 $\sqrt{3}$ x 6 = 96 $\sqrt{3}$ cm2

Lee la nota de la lección en Areas (WAEC)

Ver respuesta

Pregunta 15 Informe

In a restaurant, the cost of providing a particular type of food is partly constant and partially inversely proportional to the number of people. If cost per head for 100 people is 30k and the cost for 40 people is 60k, Find the cost for 50 people?

15k

20k

50k

40k

45k

Detalles de la respuesta

C = a + k
$\frac{1}{N}$ = c
= $\frac{a N + k}{N}$
CN = aN + K
30(100) = a(100) + k
3000 = 100a + k.......(i)
60(40) = a(40) + k
2400 = 40a + k.......(ii)
eqn (i) - eqn (ii)
600 = 60a
a = 10
subt. for a in eqn (i) 3000 = 100(10) + K
3000 - 1000 = k
k = 2000
CN = 10N + 2000. when N = 50,
50C = 10(50) + 2000
50C = 500 + 2000
C = $\frac{2500}{50}$
= 50k

Lee la nota de la lección en Variation (WAEC)

Lee la nota de la lección en Linear Inequalities (WAEC)

Linear Inequalities

Ver respuesta

Pregunta 16 Informe

Find correct to two decimals places \(100 + \frac{1}{100} + \frac{3}{1000} + \frac{27}{10000}\)

100.02

1000.02

100.22

100.01

100.51

Detalles de la respuesta

100 + $\frac{1}{100}$ + $\frac{3}{1000}$ + $\frac{27}{10000}$
$\frac{1000, 000 + 100 + 30 + 27}{10000}$ = $\frac{1, 000.157}{10000}$
= 100.02

Lee la nota de la lección en Number Bases (WAEC)

Lee la nota de la lección en Areas (WAEC)

Number Bases

Ver respuesta

Pregunta 17 Informe

At what real value of x do the curves whose equations are y = x3 + x and y = x2 + 1 intersect?

-2

2

-1

9

1

Detalles de la respuesta

y = x3 + x and y = x2 + 1
$\begin{array}{cc} x & - 2 & - 1 & 0 & 1 & 2 \\ Y = x^{3} + x & - 10 & - 2 & 0 & 2 & 10 \\ y = x^{2} + 1 & 5 & 2 & 1 & 2 & 5 \end{array}$
The curves intersect at x = 1

Lee la nota de la lección en Coordinate Geometry (JAMB)

Lee la nota de la lección en Quadratic Equations (WAEC)

Coordinate Geometry

Quadratic Equations

Ver respuesta

Pregunta 18 Informe

\((\sqrt{2} + 4\sqrt{2})(\sqrt{3} + \sqrt{2})(\sqrt{3} + \sqrt{2})\) is equal to

1

(

\sqrt{2} + 4 \sqrt{2}

)

(6

\sqrt{2}

8

Detalles de la respuesta

( $\sqrt{2} + 4 \sqrt{2}$ ) ( $\sqrt{3} + \sqrt{2}$ ) ( $\sqrt{3} + \sqrt{2}$ )
( $\sqrt{3} + \sqrt{2}$ + ( $\sqrt{3} + \sqrt{2}$ ) = 3 + ( $\sqrt{6} - \sqrt{6}$ ) - 2
= 1

Ver respuesta

Pregunta 19 Informe

Write h in terms of a, b, c, d if \(a = \frac{b(1-ch)}{a-dh}\)

h = $\frac{a - b}{a d}$

h = $\frac{1 - b}{a d - b c}$

h = $\frac{(a - b)^{2}}{a d - b c}$

h =

\frac{a - b}{a d - b c}

h = $\frac{b - a}{a b - d c}$

Detalles de la respuesta

a = $\frac{b (1 - c h)}{a - d h}$
a = $\frac{b - b c h}{1 - d h}$
= a - adh
= b - bch
a - b = bch + adn
a - b = adh
a - b = h(ad - bc)
h = $\frac{a - b}{a d - b c}$

Ver respuesta

Pregunta 20 Informe

Solve the simultaneous equations 2x - 3y + 10 = 10x - 6y = 5

x = 2

\frac{1}{2}

, y = 3

\frac{1}{2}

x =

\frac{1}{2}

, y =

\frac{3}{2}

x = 2

\frac{1}{4}

, y = 3

\frac{1}{2}

x = 2

\frac{1}{3}

, y = 3

\frac{1}{2}

x = 2

\frac{1}{3}

, y = 2

\frac{1}{2}

Detalles de la respuesta

2x - 3y = -10; 10x - 6y = -5
2x - 3y = -10 x 2
10x - 6y = 5
4x - 6y = -20 .......(i)
10x - 6y = 5.......(ii)
eqn(ii) - eqn(1)
6x = 15
x = $\frac{15}{6}$
= $\frac{5}{2}$
x = 2 $\frac{1}{2}$
Sub. for x in equ.(ii) 10( $\frac{5}{2}$ ) - 6y = 5
y = 3 $\frac{1}{2}$

Lee la nota de la lección en Solution Of Linear Equations (WAEC)

Solution Of Linear Equations

Ver respuesta

Pregunta 22 Informe

Solve the following equation \( \frac{2}{2r-1} - \frac{5}{3} = \frac{1}{r+2} \)

(

\frac{5}{2}

, 1)

(5, -4)

(2, 1)

(1,

\frac{- 5}{2}

)

(

\frac{- 5}{2}

, 1)

Detalles de la respuesta

$\frac{2}{2 r - 1}$ - $\frac{5}{3}$ = $\frac{1}{r + 2}$
$\frac{2}{2 r - 1}$ - $\frac{1}{r + 2}$ = $\frac{5}{3}$
$\frac{2 r + 4 - 2 r + 1}{2 r - 1 (r + 2)}$ = $\frac{5}{3}$
$\frac{5}{(2 r + 1) (r + 2)}$ = $\frac{5}{3}$
5(2r - 1)(r + 2) = 15
(10r - 5)(r + 2) = 15
10r2 + 20r - 5r - 10 = 15
10r2 + 15r = 25
10r2 + 15r - 25 = 0
2r2 + 3r - 5 = 0
(2r2 + 5r)(2r + 5) = r(2r + 5) - 1(2r + 5)
(r - 1)(2r + 5) = 0
r = 1 or $\frac{- 5}{2}$

Lee la nota de la lección en Solution Of Linear Equations (WAEC)

Solution Of Linear Equations

Ver respuesta

Pregunta 23 Informe

If \( \cos \theta = \frac{\sqrt{3}}{2} \) and \( \theta \) is less than 90^o. Calculate \( \cos \frac{90-\theta}{\sin^2\theta} \)

\frac{4}{\sqrt{3}}

\sqrt{\frac{3}{2}}

\sqrt{\frac{76}{2}}

4

\sqrt{\frac{76}{2}}

Detalles de la respuesta

cos $\frac{90 - θ}{s i n^{2} θ}$
= $\frac{\tan θ}{s i n^{2} θ}$
Sin2 $θ$ = $\frac{1}{4}$
$\frac{c o s (90 - θ)}{s i n^{2} θ}$
= $\frac{1}{\sqrt{3}}$
= $\frac{4}{\sqrt{3}}$

Lee la nota de la lección en Sine, Cosine And Tangent Of An Angle (WAEC)

Lee la nota de la lección en Trigonometry (JAMB)

Sine, Cosine And Tangent Of An Angle

Trigonometry

Ver respuesta

Pregunta 24 Informe

If \(e^x = 1 + \frac{x}{2} + \frac{x^2}{1.2} + \frac{x^3}{1.2.3} + .....\) Find \(\frac{1}{e^x}\)

1 -

\frac{x}{2}

+

\frac{x^{2}}{{1.2}^{3}}

+

\frac{x^{3}}{2^{4} .3}

+ .........

1 -

\frac{x}{2}

+

\frac{x^{2}}{{1.2}^{3}}

+

\frac{x^{4}}{2.4.3}

+ ..

1 +

\frac{x}{2}

+

\frac{x^{2}}{1.2}

+

\frac{x^{3}}{1.2.3}

+

\frac{x^{4}}{1.23.4}

+ .........

1 - x +

\frac{x^{2}}{{1.2}^{3}}

+

\frac{x^{3}}{2^{4} .3}

+ .........

1 +

\frac{x}{2}

+

\frac{x^{2}}{{1.2}^{3}}

+

\frac{x^{4}}{1.2.6}

+ ........

Detalles de la respuesta

ex = 1 + $\frac{x}{2}$ + $\frac{x^{2}}{1.2}$ + $\frac{x^{3}}{1.2.3}$ + $\frac{x^{4}}{1.23.4}$

Ver respuesta

Pregunta 25 Informe

In the figure, GHIJKLMN is a cube of side a. Find the length of HN.

\sqrt{3 a}

3a

3a2

a

\sqrt{2}

a

\sqrt{3}

Detalles de la respuesta

HJ2 = a2 + a2 = 2a2

HJ = $\sqrt{2 a^{2}} = a \sqrt{2}$

HN2 = a2 + (a $\sqrt{2}$ )2 = a2 + 2a2 = 3a2

HN = $\sqrt{3 a^{2}}$

= a $\sqrt{3}$ cm

Lee la nota de la lección en Polynomials (JAMB)

Lee la nota de la lección en Mensuration (JAMB)

Lee la nota de la lección en Inequalities (JAMB)

Polynomials

Mensuration

Inequalities

Ver respuesta

Pregunta 26 Informe

If two fair coins are tossed, what is the probability of getting at least one head?

\frac{1}{4}

\frac{1}{2}

1

\frac{43}{78}

\frac{3}{4}

Detalles de la respuesta

Prob. of getting at least one head
Prob. of getting one head + prob. of getting 2 heads
= $\frac{1}{4}$ + $\frac{2}{4}$
= $\frac{3}{4}$

Ver respuesta

Pregunta 28 Informe

In the figure, MNQP is a cyclic quadrilateral. MN and Pq are produced to meet at X and NQ and MP are produced to meet at Y. If MNQ = \(86^\circ\) and NQP = \(122^\circ\) find (\(x^\circ\), \(y^\circ\))

28

^{\circ}

, 36

^{\circ}

36

^{\circ}

, 28

^{\circ}

43

^{\circ}

, 61

^{\circ}

61

^{\circ}

, 43

^{\circ}

36

^{\circ}

, 43

^{\circ}

Detalles de la respuesta

y $^{\circ}$ = 180 $^{\circ}$ - (86 $^{\circ}$ + 58 $^{\circ}$ )

180 - 144 = 36 $^{\circ}$

x $^{\circ}$ = 180 - (94 + 58)

180 -152 = 28

(x $^{\circ}$ , y $^{\circ}$ ) = (28 $^{\circ}$ , 36 $^{\circ}$ )

Lee la nota de la lección en Polynomials (JAMB)

Lee la nota de la lección en Differentiation (JAMB)

Lee la nota de la lección en Inequalities (JAMB)

Polynomials

Differentiation

Inequalities

Ver respuesta

Pregunta 30 Informe

A solid sphere of radius 4cm has a mass of 64kg. What will be the mass of a shell of the same metal whose internal and external radii are 2cm and 3cm respectively?

5kg

16kg

19kg

6kg

Detalles de la respuesta

$\frac{1 \sqrt{3}}{(\frac{1}{2})^{2}}$
= $\frac{4}{\sqrt{3}}$
= $\frac{\sqrt{3}}{\sqrt{3}}$
= $\frac{4 \sqrt{3}}{\sqrt{3}}$
m = 64kg, V = $\frac{4 π r^{3}}{3}$
= $\frac{4 π (4)^{3}}{3}$
= $\frac{256 π}{3}$ x 10-6m3
density(P) = $\frac{Mass}{Volume}$
= $\frac{64}{\frac{256 π}{3 \times 10^{- 6}}}$
= $\frac{64 \times 3 \times 10^{- 6}}{256}$
= $\frac{3}{4 \times 10^{- 6}}$
m = PV = $\frac{3}{4 π \times 10^{- 6}}$ x $\frac{4}{3}$ $π$ [32 - 22] x 10-6
$\frac{3}{4 \times 10^{- 6}}$ x $\frac{4}{3}$ x 5 x 10-6
= 5kg

Ver respuesta

Pregunta 34 Informe

John gives one-third of his money to Janet who has ₦105.00. He then finds that his money is reduced to one-fourth of what Janet now has. Find how much money john has at first

₦45.00

₦48.00

₦52.00

₦60.00

₦53.00

Detalles de la respuesta

Let x be John's money, Janet already had ₦105, $\frac{1}{3}$ of x was given to Janet
Janet now has $\frac{1}{3^{2}}$ x + 105 = $\frac{x + 315}{3}$
John's money left = $\frac{2}{3}$ x
= $\frac{\frac{1}{4} (x + 315)}{3}$
= $\frac{2}{3}$
24x = 3x + 945
∴ x = 45

Lee la nota de la lección en Fractions, Decimals And Approximations (WAEC)

Fractions, Decimals And Approximations

Ver respuesta

Pregunta 35 Informe

If three numbers P, Q, R are in ratio 6 : 4 : 5, find the value of \( \frac{3p-q}{4q+r} \)

3

2

2

3

2

3

18

Detalles de la respuesta

P : Q : r = 6 : 4 : 5
5 = 6 + 4 + 5
= 15
P = $\frac{6}{15}$ , q = $\frac{4}{15}$ , r = $\frac{5}{15}$ = $\frac{1}{3}$
To find $\frac{3 p - q}{4 q + r}$
3p - q = 3 x $\frac{6}{15}$ - $\frac{4}{15}$
$\frac{18}{15}$ - $\frac{4}{15}$ = $\frac{14}{15}$
∴ 4q + r = 4 x $\frac{4}{15}$ + $\frac{5}{15}$
$\frac{16}{15}$ = $\frac{16}{15}$ + $\frac{5}{15}$
= $\frac{21}{15}$
$\frac{14}{15}$ x $\frac{15}{21}$ = $\frac{14}{21}$
= $\frac{2}{3}$

Ver respuesta

Pregunta 36 Informe

What is the probability that a number chosen at random from the intergers between 1 and 10 inclusive is either a prime or a multiple of 3?

\frac{7}{10}

\frac{3}{5}

\frac{4}{5}

\frac{3}{10}

Detalles de la respuesta

Simple Space: (1, 2, 3, 4, 5, 6, 7, 8, 9, 10 = 10)
Prime: (2, 3, 5, 7)
multiples of 3: (3, 6, 9)
Prime or multiples of 3: (2, 3, 5, 6, 7, 9 = 6)
Probability = $\frac{6}{10}$
= $\frac{3}{5}$

Lee la nota de la lección en Probability (WAEC)

Probability

Ver respuesta

Pregunta 37 Informe

List all integers satisfying the inequality \( -2 \le 2x - 6 < 4 \)

2, 3, 4, 5

2, 3, 4

2, 5

3, 4, 5

4, 5

Detalles de la respuesta

-2 $\leq$ 2x - 6 < 4 = 2x - 6 < 4

= 2x < 10

= x < 5

2x $\geq$ -2 + 6 $\geq$

= x $\geq$ 2

∴ 2 $\leq$ x < 5 [2, 3, 4]

Lee la nota de la lección en Inequalities (JAMB)

Inequalities

Ver respuesta

Pregunta 38 Informe

In \( \triangle \) XYZ, XKZ = 90^O, XK = 15cm, XY = 35cm and YK = 8cm. Find the area of \( \triangle \) XYZ

190 sq.cm

20 sq.cm

210 sq.cm

160sq.cm

320sq.cm

Detalles de la respuesta

By Pythagoras, KZ2 = 252 - 52

KZ2 = (25 + 15)(25 - 15) = 400

KZ = $\sqrt{400}$ = 20

area of XYZ = $\frac{1}{2} \times 28 \times 15$

= 210 sq. cm

Ver respuesta

Pregunta 39 Informe

Make c the subject of formula \(v = 1 - \frac{a}{5}\left(b + \frac{3c}{7}\right)\)

[

\frac{7}{3}

+

\frac{5}{a}

(v - 1)] + b

[

\frac{7 b}{3}

+

\frac{5}{a}

(v - 1)]

\frac{7}{3}

[b +

\frac{5}{a}

(v - 1)]

\frac{7}{3}

[b +

\frac{5 v - 1}{a}

]

Change Of Subject Of A Formula/Relation

Solution Of Linear Equations

Ver respuesta

Pregunta 40 Informe

a sum of money was invested at 8% per annum simple interest. If after 4 years the money amounts to N330.00. Find the amount originally invested

N180.00

n165.00

N150.00

N250.00

N200.00

Detalles de la respuesta

S.I = $\frac{P T R}{100}$

T = 4yrs, R = 8%, a = N330.00

330 - P = $\frac{P T R}{100}$ , A = P + I

i.e. A = P + $\frac{P T R}{100}$

330 = P + $\frac{P (4) (8)}{100}$

33000 = 32P + 100p

132P = 33000

P = N250.00

Lee la nota de la lección en Positive And Negative Integers, Rational Numbers (WAEC)

Positive And Negative Integers, Rational Numbers

Ver respuesta

Pregunta 41 Informe

In \( \triangle \) XYZ, XY = 13cm, YZ = 9cm, XZ = 11cm and XYZ = \( \theta \). Find cos\( \theta \)^o

\frac{4}{39}

\frac{43}{39}

\frac{209}{3}

\frac{43}{78}

Detalles de la respuesta

cos $θ$ = $\frac{13^{2} + 9^{2} - 11^{2}}{2 (13) (9)}$
= $\frac{169 + 81 - 21}{26 \times 9}$
cos $θ$ = $\frac{129}{26 \times 9}$
= $\frac{43}{78}$

Lee la nota de la lección en Introductory Calculus (WAEC)

Lee la nota de la lección en Trigonometry (JAMB)

Introductory Calculus

Trigonometry

Ver respuesta

Pregunta 42 Informe

Arrange the following numbers in ascending order of magnitude \( \frac{6}{7} \), \( \frac{13}{15} \), 0.8650

$\frac{6}{7}$ < 0.865 < $\frac{13}{15}$

$\frac{13}{15}$ < $\frac{6}{7}$ < 0.865

$\frac{6}{7}$ < $\frac{13}{15}$ < 0.865

0.865 < $\frac{6}{7}$ < $\frac{13}{15}$

Detalles de la respuesta

$\frac{6}{7}$ , $\frac{13}{15}$ , 0.8650

In ascending order, we have 0.8571, 0.8650, 0.8666

i.e. $\frac{6}{7}$ < 0.8650 < $\frac{13}{15}$

Lee la nota de la lección en Fractions, Decimals And Approximations (WAEC)

Fractions, Decimals And Approximations

Ver respuesta

Pregunta 43 Informe

In a class of 120 students, 18 of them scored an A grade in mathematics. If the section representing the A grade students on a pie chart has angle Zo at the centre of the circle, what is Z?

15

27

50

52

54

Detalles de la respuesta

Total students = 120
grade = 18
Zo = $\frac{18}{120}$ x $\frac{360}{1}$
= 54o

Ver respuesta

Pregunta 46 Informe

In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = \( \theta^\circ \) and RQP = \( \phi^\circ \), which of the following relationships between \( \theta^\circ \) and \( \phi^\circ \) is correct

θ

^{\circ}

+

ϕ

^{\circ}

= 902

ϕ

^{\circ}

= 902 - 2

θ

^{\circ}

θ

^{\circ}

=

ϕ

^{\circ}

ϕ

^{\circ}

= 2

θ

^{\circ}

θ

^{\circ}

+ 2

ϕ

^{\circ}

Detalles de la respuesta

180 - $ϕ$ $^{\circ}$ = $θ$ $^{\circ}$ + $ϕ$ $^{\circ}$ (Sum of opposite interior angle equal to its exterior angle)

180 = 2 $ϕ$ + $θ$ $^{\circ}$

Lee la nota de la lección en Introductory Calculus (WAEC)

Lee la nota de la lección en Trigonometry (JAMB)

Lee la nota de la lección en Circles (WAEC)

Introductory Calculus

Trigonometry

Ver respuesta

Pregunta 47 Informe

If the quadratic function 3x2 - 7x + R is a perfect square, find R

\frac{49}{24}

\frac{49}{12}

\frac{49}{13}

\frac{49}{3}

\frac{49}{36}

Detalles de la respuesta

3x2 - 7x + R. Computing the square, we have
x2 - $\frac{7}{3}$ = - $\frac{R}{3}$
( $\frac{x}{1} - \frac{7}{6}$ )2 = - $\frac{R}{3}$ + $\frac{49}{36}$
$\frac{- R}{3}$ + $\frac{49}{36}$ = 0
R = $\frac{49}{36}$ x $\frac{3}{1}$
= $\frac{49}{12}$

Lee la nota de la lección en Fractions, Decimals, Approximations And Percentage (JAMB)

Lee la nota de la lección en Quadratic Equations (WAEC)

Fractions, Decimals, Approximations And Percentage

Quadratic Equations

Ver respuesta

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

19

20

21

22

23

24

25

26

27

28

29

30

31

32

33

34

35

36

37

38

39

40

41

42

43

44

45

46

47