Mathematics - 9260 OxfordAQA

Solving Equations And Inequalities

Übersicht

An equation is a question about a number: which value makes these two expressions agree? Solving it is the process of stripping away everything that has been done to the unknown until it stands alone. That is the mechanical half of this topic. The other half is harder and worth more marks: turning a situation described in words, or drawn as a shape, into the equation in the first place.

You will solve linear equations, including those with brackets and with the unknown on both sides, solve quadratic equations by factorising, solve two linear simultaneous equations in two variables, find approximate solutions from a graph, translate simple situations or procedures into algebraic expressions or formulae, derive and solve equations from geometrical problems and problems set in context, and solve linear inequalities and represent the solution set on a number line. On the Extension Tier you will add completing the square and the quadratic formula, simultaneous equations where one is quadratic, inequalities in two variables and quadratic inequalities, and the graphical representation of a solution set.

Ziele

  1. [Core] solve linear equations in one unknown algebraically
  2. [Core] find approximate solutions using a graph (Notes: including use of brackets and those with the unknown on both sides of the equation)
  3. [Core] solve quadratic equations algebraically by factorising
  4. [Core] find approximate solutions using a graph
  5. [Extension] including completing the square and by using the quadratic formula
  6. [Core] solve two linear simultaneous equations in two variables algebraically
  7. [Core] find approximate solutions using a graph
  8. [Extension] including one linear and one quadratic
  9. [Core] translate simple situations or procedures into algebraic expressions or formulae
  10. [Core] derive an equation (or two simultaneous equations), solve the equation(s) and interpret the solution (Notes: including the solution of geometrical problems and problems set in context)
  11. [Core] solve linear inequalities in one variable
  12. [Core] represent the solution set on a number line
  13. [Extension] solve linear inequalities in one or two variable(s), and quadratic inequalities in one variable
  14. [Extension] represent the solution set on a number line and on a graph (Notes: students should know the conventions of an open circle on a number line for a strict inequality and a closed circle for an included boundary. In graphical work the convention of a dashed line for strict inequalities and a solid line for an included inequality will be required)

Mindmap

Dieses Thema ist als Karte dargestellt, damit die Zusammenhange sichtbar werden.

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Lektionshinweis

Take a number, multiply it by 6 and subtract 12, and you get 0. What was the number? Nobody solves this by algebra: you add 12 back, then divide by 6, and get 2. That is the entire principle. An equation records a sequence of operations applied to an unknown, and solving it means applying the inverse operations in the reverse order. The formal rule, do the same thing to both sides, is a way of keeping that honest when the sequence gets complicated.

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Unterrichtsbewertung

Herzlichen Glückwunsch zum Abschluss der Lektion über Solving Equations And Inequalities. Jetzt, da Sie die wichtigsten Konzepte und Ideen erkundet haben,

Sie werden auf eine Mischung verschiedener Fragetypen stoßen, darunter Multiple-Choice-Fragen, Kurzantwortfragen und Aufsatzfragen. Jede Frage ist sorgfältig ausgearbeitet, um verschiedene Aspekte Ihres Wissens und Ihrer kritischen Denkfähigkeiten zu bewerten.

Nutzen Sie diesen Bewertungsteil als Gelegenheit, Ihr Verständnis des Themas zu festigen und Bereiche zu identifizieren, in denen Sie möglicherweise zusätzlichen Lernbedarf haben.

  1. Circle the equation with roots 4 and -8. A. 4x(x - 8) = 0 B. (x - 4)(x + 8) = 0 C. x^2 - 32 = 0 D. (x + 4)(x - 8) = 0 Answer: B
  2. A number line shows a closed circle at -7, an open circle at 6, and the values between them shaded. Which inequality does it show? A. -7 < x < 6 B. -7 is less than or equal to x, and x < 6 C. -7 < x, and x is less than or equal to 6 D. -7 is less than or equal to x, and x is less than or equal to 6 Answer: B
  3. Solve 5(x + 4) = 3(x + 7) + 2. A. x = 0.5 B. x = 1.5 C. x = 3 D. x = 21.5 Answer: B
  4. How many solutions does x^2 = 5x have? A. none B. one C. two D. infinitely many Answer: C
  5. Which method must be used to solve the pair 4x + y = -3 and y = x^2 + 2x + 5? A. adding the two equations B. subtracting the two equations C. substitution D. trial and improvement Answer: C

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