WAEC SSCE - General Mathematics - 2009…

A box contains black, white and red identical balls. The probability of picking a black ball at random from the box is $\frac{3}{10}$ and the probability of picking a white ball at random is $\frac{2}{5}$. If there are 30 balls in the box, how many of them are red?

9 Richtige Antwort

Antwortdetails

The probability of picking a black ball at random from the box is $\frac{3}{10}$ and the probability of picking a white ball at random is $\frac{2}{5}$. Let's assume that there are x red balls in the box. Since there are a total of 30 balls, we can write: number of black balls + number of white balls + number of red balls = total number of balls $\frac{3}{10}(30) + \frac{2}{5}(30) + x = 30$ Simplifying the above equation gives: 9 + 12 + x = 30 x = 30 - 9 - 12 x = 9 Therefore, there are 9 red balls in the box.

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Frage 4 Bericht

If 9^2x = $\frac{1}{3}$(27^x), find x

-1 Richtige Antwort

-2

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Lies die Unterrichtsnotiz zu Solution Of Linear Equations (WAEC)

Lies die Unterrichtsnotiz zu Indices (WAEC)

Solution Of Linear Equations

Indices

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Frage 5 Bericht

Find the value of x in the diagram

50^o

30^o

22^o

17^o Richtige Antwort

Antwortdetails

Lies die Unterrichtsnotiz zu Circles (WAEC)

Lies die Unterrichtsnotiz zu Number Bases (JAMB)

Circles

Number Bases

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Frage 6 Bericht

The angles of triangle are (x + 10)^o, (2x - 40)^o and (3x - 90)^o. Which of the following accurately describes the triangle?

it is a scalene triangle

it is right angled isosceles triangle

t is an equilateral triangle Richtige Antwort

It is an isosceles triangle but not right angled

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Lies die Unterrichtsnotiz zu Triangles And Polygons (WAEC)

Triangles And Polygons

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Frage 7 Bericht

Find the value of x in the diagram

50^o

60^o

70^o Richtige Antwort

80^o

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Lies die Unterrichtsnotiz zu Circles (WAEC)

Lies die Unterrichtsnotiz zu Angles (WAEC)

Lies die Unterrichtsnotiz zu Triangles And Polygons (WAEC)

Circles

Angles

Triangles And Polygons

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Frage 8 Bericht

solve $\frac{2x + 1}{6} - \frac{3x - 1}{4}$ = 0

1 Richtige Antwort

$\frac{1}{5}$

-$\frac{1}{5}$

-1

Antwortdetails

To solve the equation $\frac{2x + 1}{6} - \frac{3x - 1}{4} = 0$, we need to simplify the left-hand side and solve for x. First, we need to find a common denominator for the two fractions. The smallest common multiple of 6 and 4 is 12, so we can rewrite the equation as: \[\frac{2x+1}{6}\cdot \frac{2}{2} - \frac{3x-1}{4}\cdot \frac{3}{3} = 0\] Simplifying, we get: \[\frac{4x+2}{12} - \frac{9x-3}{12} = 0\] Combining the fractions, we get: \[\frac{4x+2-(9x-3)}{12} = 0\] Simplifying further, we get: \[\frac{-5x+5}{12} = 0\] Multiplying both sides by 12, we get: \[-5x+5=0\] Adding 5 to both sides, we get: \[-5x=-5\] Dividing both sides by -5, we get: \[x=1\] Therefore, the solution to the equation is x = 1.

Lies die Unterrichtsnotiz zu Solution Of Linear Equations (WAEC)

Lies die Unterrichtsnotiz zu Algebraic Fractions (WAEC)

Lies die Unterrichtsnotiz zu Simple Operations On Algebraic Expressions (WAEC)

Solution Of Linear Equations

Algebraic Fractions

Simple Operations On Algebraic Expressions

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Frage 9 Bericht

If $\frac{3}{2x} - \frac{2}{3x} = 4$, solve for x

$\frac{4}{5}$

$\frac{4}{13}$

$\frac{5}{24}$ Richtige Antwort

$\frac{13}{24}$

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Lies die Unterrichtsnotiz zu Algebraic Fractions (WAEC)

Algebraic Fractions

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Frage 10 Bericht

The pie chart shows the distribution of 4320 students who graduated from four departments in a university. How many students graduated from the science department?

840

864 Richtige Antwort

920

960

Antwortdetails

To find the number of students who graduated from the science department, we need to look at the pie chart and determine the percentage of students that belong to that department. From the pie chart, we can see that the science department occupies 20% of the entire circle. To find the number of students in the science department, we need to calculate 20% of 4320, which can be done by multiplying 4320 by 0.20. 20% of 4320 = 0.20 x 4320 = 864 Therefore, the number of students who graduated from the science department is 864. So, the correct answer is option B: 864.

Lies die Unterrichtsnotiz zu Mensuration (JAMB)

Mensuration

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Frage 11 Bericht

The diameter of a bicycle wheel is 42cm. If the wheel makes 16 complete revolution, what will be the total distance covered by the wheel? [Take $\pi \frac{22}{7}$

672cm

1056cm

2112cm Richtige Antwort

4224cm

Antwortdetails

The distance covered by the wheel is equal to the circumference of the wheel multiplied by the number of revolutions made. The circumference of the wheel can be calculated using the formula: circumference = diameter x pi circumference = 42cm x 22/7 circumference = 132cm Therefore, the distance covered by the wheel in 16 complete revolutions is: distance = circumference x number of revolutions distance = 132cm x 16 distance = 2112cm So, the answer is (c) 2112cm.

Lies die Unterrichtsnotiz zu Volumes (WAEC)

Lies die Unterrichtsnotiz zu Areas (WAEC)

Volumes

Areas

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Frage 12 Bericht

If log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log ($\frac{28}{3}$)

2x + y - z

2x + z - y Richtige Antwort

x + y - 2x

x + x - y

Antwortdetails

We can use logarithmic rules to solve this question. Let's first express log($\frac{28}{3}$) in terms of x, y, and z. log($\frac{28}{3}$) = log(28) - log(3) We know that: log(28) = log(4 × 7) = log(4) + log(7) = 2x + z log(3) = y Therefore: log($\frac{28}{3}$) = 2x + z - y So the correct answer is 2x + z - y.

Lies die Unterrichtsnotiz zu Logarithms (WAEC)

Logarithms

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Frage 13 Bericht

In the diagram, IG is parallel to JE, JEF = 120^o and FHG = 130^o, fins the angle marked t

40^o

70^o Richtige Antwort

80^o

100^o

Antwortdetails

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Frage 14 Bericht

If (2x + 3)³ = 125, find the value of x

1 Richtige Antwort

Antwortdetails

We are given that (2x + 3)³ = 125. We can rewrite 125 as 5³. Therefore, we have: (2x + 3)³ = 5³ Taking the cube root of both sides, we get: 2x + 3 = 5 Solving for x, we get: 2x = 2 x = 1 Therefore, the value of x is 1. Answer: (a) 1.

Lies die Unterrichtsnotiz zu Indices (WAEC)

Indices

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Frage 15 Bericht

In an examination, Kofi scored x% in Physics, 50% in Chemistry and 70% in Biology. If his mean score for the three subjects was 55%, find x

45 Richtige Antwort

Antwortdetails

Kofi's mean score for the three subjects was 55%, so the total percentage score for the three subjects is 3 x 55 = 165%. Let's assume that Kofi scored x% in Physics. Then, the total percentage score for Physics, Chemistry and Biology would be: x + 50 + 70 = 165 Simplifying the equation, we get: x = 165 - 50 - 70 x = 45 Therefore, Kofi scored 45% in Physics. So the correct option is (B) 45.

Lies die Unterrichtsnotiz zu Change Of Subject Of A Formula/Relation (WAEC)

Lies die Unterrichtsnotiz zu Modular Arithmetic (WAEC)

Change Of Subject Of A Formula/Relation

Modular Arithmetic

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Frage 16 Bericht

From the diagram which of the following statements are correct? i. XQ is a radius of a circle centre Q. ii. /XQ/ = /QY/. iii. /QX/ = /XY/

i only

inand ii only Richtige Antwort

ii and iii only

i, ii and iii

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Lies die Unterrichtsnotiz zu Circles (WAEC)

Lies die Unterrichtsnotiz zu Statistics (WAEC)

Circles

Statistics

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Frage 17 Bericht

A bucket holds 10 litres of water. How many buckets of water will fill a reservoir of size 8m x 7m x 5m.(1 litre = 1000cm³)`

280

2800

28000 Richtige Antwort

Antwortdetails

The volume of the reservoir can be found by multiplying its dimensions: 8m x 7m x 5m = 280 m^3 Since 1 liter is equal to 1000 cubic centimeters (cm^3), 1 cubic meter is equal to 1,000,000 cubic centimeters. Therefore, the reservoir has a volume of: 280 m^3 x 1,000,000 cm^3/m^3 = 280,000,000 cm^3 Each bucket can hold 10 liters of water or 10,000 cubic centimeters (cm^3) of water since 1 liter is equal to 1000 cm^3. Therefore, the number of buckets needed to fill the reservoir is: 280,000,000 cm^3 ÷ 10,000 cm^3/bucket = 28,000 buckets Therefore, the answer is 28,000.

Lies die Unterrichtsnotiz zu Logical Reasoning (WAEC)

Lies die Unterrichtsnotiz zu Representation Of Data (JAMB)

Logical Reasoning

Representation Of Data

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Frage 18 Bericht

The interior angles of a pentagon are (2^x + 5)^o, (x + 20)^o, x^o, (3x - 20)^o and (x + 15)^o. Find the value of x

80^o

70^o

65^o Richtige Antwort

40^o

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Lies die Unterrichtsnotiz zu Solution Of Linear Equations (WAEC)

Lies die Unterrichtsnotiz zu Indices (WAEC)

Solution Of Linear Equations

Indices

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Frage 19 Bericht

in the diagram, angle 20^o is subtended at the centre of the circle, find the value of x

30^o

50^o Richtige Antwort

80^o

100^o

Antwortdetails

In the given diagram, we have a circle with center O and angle 20^o subtended at the center. We need to find the value of x. Firstly, we know that the angle subtended at the center of a circle is twice the angle subtended at the circumference by the same arc. Therefore, angle AOB = 2 × 20^o = 40^o Also, we know that angle in a semicircle is a right angle. So, angle AOC = 90^o. Using the fact that the angles in a triangle add up to 180^o, we can find angle BOC as follows: angle BOC = 180^o - angle AOB - angle AOC = 180^o - 40^o - 90^o = 50^o Since angle BOC is an angle at the circumference that subtends the arc BC, which is equal to x degrees, we have: x = angle BOC = 50^o Therefore, the value of x is 50^o. Answer is correct.

Lies die Unterrichtsnotiz zu Circles (WAEC)

Circles

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Frage 20 Bericht

Find the value to which N3000.00 will amount in 5 years at 6% per annum simple interest

N3,900.00 Richtige Antwort

N3,750.00

N3,600.00

N3,300

Antwortdetails

Simple interest is calculated as the product of the principal, the rate of interest, and the time duration. From the question, we have a principal of N3000.00, an interest rate of 6%, and a duration of 5 years. Using the formula for simple interest, we can find the interest accrued over the 5 years as: Interest = (P * R * T) / 100 = (3000 * 6 * 5) / 100 = N900.00 The total value to which N3000.00 will amount to after 5 years is the sum of the principal and the interest, which is: Total = Principal + Interest = 3000 + 900 = N3900.00 Therefore, N3000.00 will amount to N3900.00 after 5 years at 6% per annum simple interest. So the correct answer is option A, N3,900.00.

Lies die Unterrichtsnotiz zu Modular Arithmetic (WAEC)

Lies die Unterrichtsnotiz zu Ratio, Proportions And Rates (WAEC)

Modular Arithmetic

Ratio, Proportions And Rates

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Frage 21 Bericht

The pie chart shows the distribution of 4320 students who graduated from four departments in a university. If a student is picked at random from the four departments, what id the probability that he is not from the education department?

$\frac{3}{10}$

$\frac{2}{9}$

$\frac{5}{18}$

$\frac{7}{10}$ Richtige Antwort

Antwortdetails

To find the probability that a student picked at random is not from the education department, we need to find the total number of students who are not from the education department and divide it by the total number of students in all departments. From the pie chart, we can see that the education department has 30% of the total students. Therefore, the remaining three departments have a total of 70% of the total students. To find the probability of picking a student who is not from the education department, we divide the percentage of students who are not in the education department by 100%: Probability = $\frac{70}{100}$ = $\frac{7}{10}$ Therefore, the probability that a student picked at random is not from the education department is $\frac{7}{10}$. The correct option is: $\frac{7}{10}$.

Lies die Unterrichtsnotiz zu Variation (JAMB)

Lies die Unterrichtsnotiz zu Probability (WAEC)

Lies die Unterrichtsnotiz zu Mensuration (JAMB)

Lies die Unterrichtsnotiz zu Surds (radicals) (WAEC)

Variation

Probability

Mensuration

Surds (radicals)

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Frage 22 Bericht

Express the square root of 0.000144 in the standard form

1.2 x 10^-4

1.2 x 10^-3

1.2 x 10^-2 Richtige Antwort

1.2 x 10^-1

Antwortdetails

Lies die Unterrichtsnotiz zu Number Bases (WAEC)

Lies die Unterrichtsnotiz zu Number Bases (JAMB)

Number Bases

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Frage 23 Bericht

Given that sin 60^o = $\frac{\sqrt{3}}{2}$ and cos 60^o = $\frac{1}{2}$, evaluate $\frac{1 - sin 60^o}{1 + cos 60^o}$

$\frac{2 + \sqrt{3}}{3}$

$\frac{1 - \sqrt{3}}{3}$

$\frac{1 + \sqrt{3}}{3}$

$\frac{2 - \sqrt{3}}{3}$ Richtige Antwort

Antwortdetails

Lies die Unterrichtsnotiz zu Sine, Cosine And Tangent Of An Angle (WAEC)

Sine, Cosine And Tangent Of An Angle

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Frage 24 Bericht

If /XY/ = 50m, how far cast of X is Y?

25.5m

40.6m

40.8m

43.3m Richtige Antwort

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Lies die Unterrichtsnotiz zu Circles (WAEC)

Lies die Unterrichtsnotiz zu Triangles And Polygons (WAEC)

Circles

Triangles And Polygons

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Frage 25 Bericht

Simplify: (3$\frac{1}{2} + 4\frac{1}{3}) \div (\frac{5}{6} - \frac{2}{3}$)

1$\frac{1}{4}$

8$\frac{1}{2}$

47 Richtige Antwort

Antwortdetails

We will start by simplifying the expression inside the parenthesis first. 3$\frac{1}{2}$ + 4$\frac{1}{3}$ = (7/2) + (13/3) To add these two fractions, we need a common denominator. Multiplying the denominators together gives us 6, so: (7/2) + (13/3) = (21/6) + (26/6) = 47/6 Now, let's simplify the expression in the denominator: $\frac{5}{6} - \frac{2}{3}$ = $\frac{5}{6} - \frac{4}{6}$ = $\frac{1}{6}$ Finally, we can substitute these values into the original expression: (3$\frac{1}{2}$ + 4$\frac{1}{3}$) ÷ ($\frac{5}{6}$ - $\frac{2}{3}$) = (47/6) ÷ (1/6) When dividing fractions, we can multiply the first fraction by the reciprocal of the second: (47/6) ÷ (1/6) = (47/6) x (6/1) = 47 Therefore, the answer is 47.

Lies die Unterrichtsnotiz zu Number Bases (WAEC)

Lies die Unterrichtsnotiz zu Modular Arithmetic (WAEC)

Number Bases

Modular Arithmetic

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Frage 26 Bericht

PQRS is a trapezium. QR//PS, /PQ/ = 5cm, /OR/ = 6cm, /PS/ = 10cm and angle QPS = 42^o. Calculate, correct to the nearest cm², the area of the trapezium (h = 3.35cm² )

27cm² Richtige Antwort

30cm²

36cm²

37cm²

Antwortdetails

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Frage 27 Bericht

Find the quadratic equation whose roots are -$\frac{1}{2}$ and 3

2x² - 2x + 3 = 0

2x² - 2x - 3 = 0

2x² - 5x - 3 = 0 Richtige Antwort

3x² - 5x - 3 = 0

Antwortdetails

To find the quadratic equation given its roots, we use the fact that for a quadratic equation of the form ax² + bx + c = 0, the roots are given by the formula: x = (-b ± √(b² - 4ac)) / 2a If the roots are given as α and β, then the quadratic equation can be written as: (x - α)(x - β) = 0 Expanding the above equation gives: x² - (α + β)x + αβ = 0 Therefore, to find the quadratic equation whose roots are -$\frac{1}{2}$ and 3, we substitute α = -$\frac{1}{2}$ and β = 3 into the equation: x² - (α + β)x + αβ = 0 x² - (-$\frac{1}{2}$ + 3)x + (-$\frac{1}{2}$ × 3) = 0 Simplifying the above equation, we get: 2x² - 5x - 3 = 0 Therefore, the quadratic equation whose roots are -$\frac{1}{2}$ and 3 is 2x² - 5x - 3 = 0. The correct option is (C) 2x² - 5x - 3 = 0.

Lies die Unterrichtsnotiz zu Quadratic Equations (WAEC)

Quadratic Equations

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Frage 28 Bericht

PQRS is a trapezuim. QR//PS, /PQ/ = 5cm, /OR/ = 6cm, /PS/ = 10cm and angle QPS = 42^o. Calculate the perpendicular distance between the parallel sides

3.35cm Richtige Antwort

3.73cm

4.50cm

4.62cm

Antwortdetails

Lies die Unterrichtsnotiz zu Algebraic Expressions (WAEC)

Algebraic Expressions

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Frage 29 Bericht

In the diagram, /TP/ = 12cm and it is 6cm from O, the centre of the circle, Calculate < TOP

120^o

90^o Richtige Antwort

60^o

45^o

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Lies die Unterrichtsnotiz zu Circles (WAEC)

Circles

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Frage 30 Bericht

In a particular year, the exchange rate of naira (N) varies directly with the Dollars{$}. If N1122 is equivalent to $8, find the Naira equivalent of $36

N8976

N5049 Richtige Antwort

N140.25

N31.17

Antwortdetails

The exchange rate of naira (N) varies directly with the Dollars($). This means that the exchange rate is constant, and we can set up a proportion to solve the problem. If N1122 is equivalent to $8, we can write: N1122/$8 = x/$36 where x is the Naira equivalent of $36. To solve for x, we can cross-multiply and simplify: N1122 x 36 = $8 x x 40392 = 8x x = 40392/8 = 5049 Therefore, the Naira equivalent of $36 is N5049. So, the correct option is (B) N5049.

Lies die Unterrichtsnotiz zu Variation (WAEC)

Lies die Unterrichtsnotiz zu Variation (JAMB)

Variation

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Frage 31 Bericht

Each of the interior angles of a regular polygon is 140^o. Calculate the sum of all the interior angles of the polygon

1080^o

1260^o Richtige Antwort

1800^o

2160^o

Antwortdetails

In a regular polygon with n sides, each interior angle measures: \begin{align*} 180^\circ - \frac{360^\circ}{n} \end{align*} Since each interior angle of this polygon is 140^o, we can equate the above formula to 140^o: \begin{align*} 180^\circ - \frac{360^\circ}{n} &= 140^\circ\\ \frac{360^\circ}{n} &= 40^\circ\\ n &= \frac{360^\circ}{40^\circ}\\ n &= 9 \end{align*} Therefore, the given polygon is a nonagon (a polygon with nine sides). The sum of the interior angles of a polygon with n sides can be calculated using the formula: \begin{align*} S &= (n-2)180^\circ \end{align*} Substituting n=9 into this formula, we get: \begin{align*} S &= (9-2)180^\circ\\ &= 7\cdot180^\circ\\ &= 1260^\circ \end{align*} Therefore, the sum of all the interior angles of the given polygon is 1260^o. Hence, the correct option is: - 1260^o

Lies die Unterrichtsnotiz zu Indices (WAEC)

Indices

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Frage 32 Bericht

The capacity of a water tank is 1,800 litres. If the tank is in form of a cuboid with base 600cm by 150 cm. Find the height of the tank

2cm

20cm Richtige Antwort

200cm

2000cm

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Lies die Unterrichtsnotiz zu Euclidean Geometry (JAMB)

Lies die Unterrichtsnotiz zu Areas (WAEC)

Euclidean Geometry

Areas

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Frage 33 Bericht

The following is the graph of a quadratic friction, find the co-ordinates of point P

(0, 4) Richtige Antwort

(4, 0)

(0, -4)

(-4, 0)

Antwortdetails

Lies die Unterrichtsnotiz zu Quadratic Equations (WAEC)

Lies die Unterrichtsnotiz zu Graphs Of Linear And Quadratic Functions (WAEC)

Quadratic Equations

Graphs Of Linear And Quadratic Functions

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Frage 34 Bericht

Arrange the following numbers in descending orders of magnitude: 22_three, 34_five, 21_six

21_six, 22_three, 34_five,

21_six, 34_five, 22_three

22_three, 34_five, 21_six

34_five, 21_six, 22_three Richtige Antwort

Antwortdetails

To compare these numbers, we need to convert all of them to the same base. Let's convert them all to base 10 for simplicity: - 22_three = 2\*3¹ + 2\*3⁰ = 6 + 2 = 8 - 34_five = 3\*5¹ + 4\*5⁰ = 15 + 4 = 19 - 21_six = 2\*6¹ + 1\*6⁰ = 12 + 1 = 13 So, in base 10, the numbers are 8, 19, and 13. To arrange them in descending order of magnitude, we simply sort them from largest to smallest: - 19, 13, 8 Therefore, the correct answer is: 34_five, 21_six, 22_three

Lies die Unterrichtsnotiz zu Number Bases (WAEC)

Number Bases

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Frage 35 Bericht

The following is the graph of a quadratic friction, find the value of x when y = 0

1, 2

1, 4 Richtige Antwort

2, 3

1, 6

Antwortdetails

Lies die Unterrichtsnotiz zu Quadratic Equations (WAEC)

Quadratic Equations

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Frage 36 Bericht

What is the median of the following scores: 22 35 41 63 74 82

52 Richtige Antwort

Antwortdetails

To find the median of a set of numbers, we first need to arrange them in ascending or descending order. In this case, arranging the numbers in ascending order gives us: 22, 35, 41, 63, 74, 82 The median is the middle number in the set when the numbers are arranged in order. Since we have an even number of numbers in this set, there are two middle numbers: 41 and 63. To find the median, we take the average of these two numbers: Median = (41 + 63) / 2 = 104 / 2 = 52 Therefore, the median of the scores is 52.

Lies die Unterrichtsnotiz zu Euclidean Geometry (JAMB)

Euclidean Geometry

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Frage 37 Bericht

An arc of a circle subtends an angle of 60^o at the centre. If the radius of the circle is 3cm, find , in terms of $\pi$, the length of the arc

$\pi$cm Richtige Antwort

2$\pi$cm

3$\pi$cm

6$\pi$cm

Antwortdetails

When an angle in degrees is subtended at the center of a circle, the length of the arc it cuts out is given by: $$\text{Length of arc} = \frac{\text{angle}}{360^\circ} \times 2\pi r$$ where r is the radius of the circle. In this case, the angle is 60° and the radius is 3 cm. Substituting these values into the formula above, we get: $$\text{Length of arc} = \frac{60}{360^\circ} \times 2\pi (3\text{ cm}) = \frac{1}{6} \times 6\pi = \pi \text{ cm}$$ Therefore, the length of the arc, in terms of π, is π cm. Hence, the correct option is: $\pi$cm.

Lies die Unterrichtsnotiz zu Circles (WAEC)

Circles

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Frage 38 Bericht

In the diagram, \SQ\ = 4cm, \PT\ = 7cm. /TR/ = 5cm and ST//OR. If /SP/ = xcm, find the value of x

5.6 Richtige Antwort

6.5

6.6

6.8

Antwortdetails

Lies die Unterrichtsnotiz zu Polynomials (JAMB)

Lies die Unterrichtsnotiz zu Sets (JAMB)

Polynomials

Sets

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Frage 39 Bericht

If a positive integer, list the values of x which satisfy the equation 3x - 4 < 6 and x - 1 > 0

{1, 2, 3}

{2, 3} Richtige Antwort

{2, 3, 4}

{2, 3, 4, 5}

Antwortdetails

Lies die Unterrichtsnotiz zu Linear Inequalities (WAEC)

Lies die Unterrichtsnotiz zu Surds (radicals) (WAEC)

Linear Inequalities

Surds (radicals)

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Frage 40 Bericht

Simplify; $\frac{1}{2}\sqrt{32} - \sqrt{18} \sqrt{2}$

zero Richtige Antwort

$\sqrt{2}$

2$\sqrt{2}$

4\(\sqrt{2}\0

Antwortdetails

Lies die Unterrichtsnotiz zu Positive And Negative Integers, Rational Numbers (WAEC)

Lies die Unterrichtsnotiz zu Surds (radicals) (WAEC)

Positive And Negative Integers, Rational Numbers

Surds (radicals)

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Frage 41 Bericht

If M and N are two fixed points in a plane. Find the locus L = [P : PM = PN]

a line equal to MN

line parallel to MN

Perpendicular bisector of MN Richtige Antwort

A circle centre P, radius MN

Antwortdetails

Lies die Unterrichtsnotiz zu Loci (JAMB)

Lies die Unterrichtsnotiz zu Loci (WAEC)

Lies die Unterrichtsnotiz zu Coordinate Geometry (JAMB)

Loci

Coordinate Geometry

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Frage 42 Bericht

If 85% of x is N3230, what is the value of x?

N2745.50

N3714.50

N3800.00 Richtige Antwort

N4845.00

Antwortdetails

We can solve this problem using a proportion. If 85% of x is N3230, that means we can write: 0.85x = N3230 To solve for x, we need to isolate x on one side of the equation. We can do this by dividing both sides by 0.85: x = N3230 ÷ 0.85 Using a calculator, we get: x ≈ N3800.00 Therefore, the value of x is N3800.00.

Lies die Unterrichtsnotiz zu Percentages (WAEC)

Lies die Unterrichtsnotiz zu Positive And Negative Integers, Rational Numbers (WAEC)

Percentages

Positive And Negative Integers, Rational Numbers

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Frage 43 Bericht

Simplify (x - 3y)² - (x + 3y)²

2(x + 3y)

(2x - 3y)

-12xy Richtige Antwort

6xy

Antwortdetails

Lies die Unterrichtsnotiz zu Algebraic Expressions (WAEC)

Lies die Unterrichtsnotiz zu Quadratic Equations (WAEC)

Algebraic Expressions

Quadratic Equations

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Frage 44 Bericht

Express 2.7864 x 10^-3 to 2 significant figures

0.28

0.27

0.0028 Richtige Antwort

0.0027

Antwortdetails

To express 2.7864 x 10^-3 to 2 significant figures, we need to round off the number to the second significant digit from the left. Since the first significant digit is 2, and the second significant digit is 7, we will look at the third digit, which is 8. Since 8 is greater than or equal to 5, we round up the second significant digit (7) by 1. Therefore, the number becomes 0.0028. So, the answer is 0.0028.

Lies die Unterrichtsnotiz zu Positive And Negative Integers, Rational Numbers (WAEC)

Lies die Unterrichtsnotiz zu Number Bases (WAEC)

Positive And Negative Integers, Rational Numbers

Number Bases

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Frage 45 Bericht

Two sets are disjoint if

they are both empty

their union is an empty set

their intersection is an empty set Richtige Antwort

one of them is a subset of the other

Antwortdetails

Two sets are said to be disjoint if their intersection is an empty set. In other words, if there are no common elements between the sets, they are said to be disjoint. For example, the sets {1,2,3} and {4,5,6} are disjoint since their intersection is an empty set {} or ∅. On the other hand, the sets {1,2,3} and {2,3,4} are not disjoint since they have elements in common, namely 2 and 3.

Lies die Unterrichtsnotiz zu Sets (WAEC)

Lies die Unterrichtsnotiz zu Sets (JAMB)

Sets

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Frage 46 Bericht

If c and k are the roots of 6 - x - x² = 0, find c + k

-1 Richtige Antwort

-3

Antwortdetails

Lies die Unterrichtsnotiz zu Modular Arithmetic (WAEC)

Lies die Unterrichtsnotiz zu Quadratic Equations (WAEC)

Modular Arithmetic

Quadratic Equations

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WAEC SSCE - General Mathematics - 2009 (Objective)