WAEC SSCE - General Mathematics - 1992…

Frage 1 Bericht

In the diagram above, PQT is an isosceles triangle.|PQ| = |QT|, ?SRQ = 75°, ?QPT = 25° and PQR is straight line. Find ?RST

20^o

50^o

55^o Richtige Antwort

70^o

75^o

Antwortdetails

Antwort anzeigen

Frage 2 Bericht

A fair die is rolled once. What is the probability of
obtaining 4 or 6?

1/12

1/6

1/3 Richtige Antwort

1/2

2/3

Antwortdetails

When you roll a fair die, there are six possible outcomes, each with an equal chance of occurring. These outcomes are the numbers 1, 2, 3, 4, 5, and 6. To find the probability of obtaining 4 or 6, we need to count how many of the outcomes correspond to these numbers. In this case, there are two outcomes that satisfy the condition, namely 4 and 6. Therefore, the probability of obtaining 4 or 6 is 2 out of 6, or 2/6. We can simplify this fraction by dividing both the numerator and denominator by their greatest common factor, which is 2. This gives us 1/3. Therefore, the probability of obtaining 4 or 6 when rolling a fair die is 1/3.

Lies die Unterrichtsnotiz zu Probability (WAEC)

Lies die Unterrichtsnotiz zu Probability (JAMB)

Probability

Antwort anzeigen

Frage 3 Bericht

Points X and Y are respectively 12m Nonh and
5m of point Z. Calculate XY

12m

13m Richtige Antwort

17m

18m

Antwortdetails

To find the distance between points X and Y, we can use the Pythagorean theorem, which states that for a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In this case, we can consider points X, Y, and Z as the vertices of a right triangle, where the right angle is at point Z. Then, XY is the hypotenuse, and we know that XZ = 12m and YZ = 5m. Therefore, we have: XY^2 = XZ^2 + YZ^2 XY^2 = 12^2 + 5^2 XY^2 = 144 + 25 XY^2 = 169 XY = √169 XY = 13m Therefore, the distance between points X and Y is 13m. So the answer is option (C) 13m.

Lies die Unterrichtsnotiz zu Inequalities (JAMB)

Lies die Unterrichtsnotiz zu Number Bases (JAMB)

Lies die Unterrichtsnotiz zu Angles (WAEC)

Inequalities

Number Bases

Angles

Antwort anzeigen

Frage 4 Bericht

Find the value of t in the diagram above

5.6cm Richtige Antwort

6.5cm

6.6cm

6.8cm

7.0cm

Antwortdetails

Using the Pythagorean theorem, we can find that the length of the hypotenuse of the right triangle on the left is: $$\sqrt{5^2+12^2} = 13$$ Since the triangle on the right is similar to the triangle on the left, we can set up the following proportion: $$\frac{5}{12} = \frac{t}{13}$$ Cross-multiplying, we get: $$12t = 65$$ Therefore: $$t = \frac{65}{12} \approx 5.4$$ So the answer is closest to 5.6cm. Therefore the correct option is (A).

Antwort anzeigen

Frage 5 Bericht

Sin 60° has the same value as I. Sin 120° II. cos 240° III. -sin 150° IV. cos 210° V. sin 240°

I only Richtige Antwort

II only

IV only

III only

IV and V only

Antwortdetails

Lies die Unterrichtsnotiz zu Sine, Cosine And Tangent Of An Angle (WAEC)

Lies die Unterrichtsnotiz zu Measures Of Dispersion (JAMB)

Sine, Cosine And Tangent Of An Angle

Measures Of Dispersion

Antwort anzeigen

Frage 6 Bericht

In the diagram above, TR = TS and ?TRS = 60^o. Find the value of x

60 Richtige Antwort

120

150

Antwortdetails

Since TR = TS and ?TRS = 60o, then ?TSR = ?TRS = 60o. Therefore, the angles of triangle TSP add up to 180o: ?TPS + ?TSP + ?TSR = 180o. Substituting the known values: x + 60 + 60 = 180. Simplifying: x = 60. Hence, the value of x is 60.

Antwort anzeigen

Frage 7 Bericht

The volume of a cone of height 9cm is 1848cm$^3$. Find its radius. [Take π = 22/7]

7cm

14cm Richtige Antwort

28cm

98cm

196cm

Antwortdetails

Lies die Unterrichtsnotiz zu Volumes (WAEC)

Volumes

Antwort anzeigen

Frage 8 Bericht

The value of tan 315°

√2/2

-1 Richtige Antwort

-√2/2

Antwortdetails

To find the value of tan 315°, we can use the identity: tan (θ + 180°) = tan θ Since tan (315° + 180°) = tan 495°, and 495° is coterminal with 135°, we have: tan 315° = tan (135° + 180°) = tan 135° Using the fact that tan 45° = 1, and tan (θ + 90°) = -cot θ, we have: tan 135° = tan (45° + 90°) = -cot 45° = -1 Therefore, the value of tan 315° is -1.

Lies die Unterrichtsnotiz zu Introductory Calculus (WAEC)

Lies die Unterrichtsnotiz zu Trigonometry (JAMB)

Introductory Calculus

Trigonometry

Antwort anzeigen

Frage 9 Bericht

A group of students measured a certain angle
(to the nearest degree) and obtained the following
results: 75^o, 76^o, 72^o, 73^o, 74^o, 79^o, 72^o, 72^o, 77^o,
72^o, 71^o, 70^o, 78^o, 73^o. Find the mode

79^o

78^o

74^o

73^o

72^o Richtige Antwort

Antwortdetails

To find the mode of the given set of data, we need to identify the value that appears most frequently. From the given set of measurements, we can see that 72^o appears 4 times, which is more than any other value. Therefore, the mode of the data set is 72^o. So, the correct option is (e) 72^o.

Lies die Unterrichtsnotiz zu Angles And Intercepts On Parallel Lines (WAEC)

Lies die Unterrichtsnotiz zu Probability (JAMB)

Lies die Unterrichtsnotiz zu Angles (WAEC)

Angles And Intercepts On Parallel Lines

Probability

Angles

Antwort anzeigen

Frage 10 Bericht

In the diagram above, O is the center of the circle PQRS and ?QPS = 36°. Find ?QOS

36^o

72^o Richtige Antwort

108^o

144^o

288^o

Antwortdetails

Lies die Unterrichtsnotiz zu Circles (WAEC)

Circles

Antwort anzeigen

Frage 11 Bericht

Find the median of the following set of scores:
65, 72, 55, 48, 78

63.5

65 Richtige Antwort

Antwortdetails

To find the median of a set of scores, we need to arrange the scores in order of magnitude from smallest to largest. The scores in this set are: 48, 55, 65, 72, 78 There are five scores in this set, so the median will be the middle score. Since the scores are already in order, we can simply find the middle score, which is 65. Therefore, the median of this set of scores is 65.

Lies die Unterrichtsnotiz zu Representation Of Data (JAMB)

Lies die Unterrichtsnotiz zu Integration (JAMB)

Lies die Unterrichtsnotiz zu Probability (WAEC)

Representation Of Data

Integration

Probability

Antwort anzeigen

Frage 12 Bericht

A ladder leans against a vertical wall at an angle
60° to the wall, if the foot of the ladder is 5 metres
away from the wall, calculate the length of the
ladder.

5√3m/3

10√3m/3

Richtige Antwort

5√3m

10m

Antwortdetails

Lies die Unterrichtsnotiz zu Introductory Calculus (WAEC)

Lies die Unterrichtsnotiz zu Circles (WAEC)

Introductory Calculus

Circles

Antwort anzeigen

Frage 13 Bericht

The curved surface area of a cylindrical tin is 704cm$^2$. Calculate the height when the radius is 8cm. [Take π = 22/7]

3.5cm

7cm

14cm Richtige Antwort

28cm

32cm

Antwortdetails

Lies die Unterrichtsnotiz zu Inequalities (JAMB)

Inequalities

Antwort anzeigen

Frage 14 Bericht

If cos θ = 5/13, what is the value of tan $\theta$ for 0 < θ < 90° ?

13/5

12/5 Richtige Antwort

5/12

Antwortdetails

We can use the following trigonometric identity: \[\tan \theta = \frac{\sin \theta}{\cos \theta}\] We are given that $\cos \theta = 5/13$. To find $\sin \theta$, we can use the Pythagorean identity: \[\sin^2 \theta + \cos^2 \theta = 1\] Substituting $\cos \theta = 5/13$, we get: \[\sin^2 \theta + \left(\frac{5}{13}\right)^2 = 1\] Simplifying, we get: \[\sin^2 \theta = 1 - \frac{25}{169} = \frac{144}{169}\] Taking the square root of both sides, we get: \[\sin \theta = \frac{12}{13}\] Substituting into the formula for $\tan \theta$, we get: \[\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{\frac{12}{13}}{\frac{5}{13}} = \boxed{\frac{12}{5}}\]

Lies die Unterrichtsnotiz zu Trigonometry (JAMB)

Lies die Unterrichtsnotiz zu Positive And Negative Integers, Rational Numbers (WAEC)

Trigonometry

Positive And Negative Integers, Rational Numbers

Antwort anzeigen

Frage 15 Bericht

Write as a single fraction $\frac{1}{1 - x} + \frac{2}{1 + x}$

$\frac{x + 3}{1 - x^2}$

$\frac{3 - x}{(1 - x)^2}$

$\frac{3 - x}{1 + x^2}$

$\frac{3 - x}{(1 + x)^2}$

$\frac{3 - x}{1 - x^2}$ Richtige Antwort

Antwortdetails

To add the fractions $\frac{1}{1-x}$ and $\frac{2}{1+x}$, we need to have a common denominator. We can obtain this by multiplying the first fraction by $(1+x)/(1+x)$ and the second fraction by $(1-x)/(1-x)$. This gives us: $$ \frac{1}{1-x} \cdot \frac{1+x}{1+x} + \frac{2}{1+x} \cdot \frac{1-x}{1-x} = \frac{1+x}{1-x^2} + \frac{2(1-x)}{1-x^2} $$ Combining the two fractions gives us: $$ \frac{1+x+2(1-x)}{1-x^2} = \frac{3-x}{1-x^2} $$ Therefore, the single fraction is $\boxed{\frac{3-x}{1-x^2}}$.

Lies die Unterrichtsnotiz zu Algebraic Fractions (WAEC)

Algebraic Fractions

Antwort anzeigen

Frage 16 Bericht

The data above shows the frequency distribution
of marks scored by a group of students in a class
test.

How many students took the test?

15 Richtige Antwort

Antwortdetails

Lies die Unterrichtsnotiz zu Representation Of Data (JAMB)

Lies die Unterrichtsnotiz zu Integration (JAMB)

Lies die Unterrichtsnotiz zu Statistics (WAEC)

Representation Of Data

Integration

Statistics

Antwort anzeigen

Frage 17 Bericht

The area of a parallelogram is 513cm$^2$ and the height is 19cm. Calculate the base.

13.5cm

25cm

27cm Richtige Antwort

54cm

108cm

Antwortdetails

The area of a parallelogram is given by the formula: Area = base × height In this problem, the area and height of the parallelogram are given as 513cm$^2$ and 19cm respectively. We can rearrange the formula to solve for the base: base = Area ÷ height Substituting the given values, we get: base = 513cm$^2$ ÷ 19cm = 27cm Therefore, the base of the parallelogram is 27cm. The answer is, 27cm.

Lies die Unterrichtsnotiz zu Areas (WAEC)

Areas

Antwort anzeigen

Frage 18 Bericht

The data below shows the number of worker?
employed in the various sections of a construction
company in Lagos.

Carpenters 24 Labourers 27
Plumbers 12 Plasterers 15
Painters 9 Messengers 3
Bricklayers 18

If one of the workers is absent on a certain day,
what is the probability that he is a bricklayer?

1/12

1/9

2/9

1/6 Richtige Antwort

1/4

Antwortdetails

The total number of workers in the company is 24+27+12+15+9+3+18 = 108. The probability of an absent worker being a bricklayer is the ratio of the number of bricklayers to the total number of workers, which is 18/108 = 1/6. Therefore, the probability that the absent worker is a bricklayer is 1/6. Answer: 1/6.

Lies die Unterrichtsnotiz zu Statistics (WAEC)

Statistics

Antwort anzeigen

Frage 19 Bericht

The angles marked in the diagram above are measured in degrees. Find x

15^o

24^o Richtige Antwort

30^o

36^o

48^o

Antwortdetails

In the given diagram, we have a triangle with two sides of equal length, which means that the angles opposite these sides are also equal. Thus, we can conclude that: 4x - 6 = 3x + 12 (using the fact that angles in a triangle add up to 180 degrees) x = 18 Therefore, the value of x is 18 degrees. Answer: (b) 24°.

Lies die Unterrichtsnotiz zu Angles And Intercepts On Parallel Lines (WAEC)

Lies die Unterrichtsnotiz zu Angles (WAEC)

Angles And Intercepts On Parallel Lines

Angles

Antwort anzeigen

Frage 20 Bericht

A regular polygon has each of its exterior angles as 18^o. How many sides has the polygon

20 Richtige Antwort

Antwortdetails

The exterior angles of a polygon add up to 360 degrees. If each exterior angle of a regular polygon is 18 degrees, then the polygon has 360/18 = 20 exterior angles. Since a regular polygon has the same number of sides as exterior angles, the polygon has 20 sides. Therefore, the answer is (d) 20.

Lies die Unterrichtsnotiz zu Sets (JAMB)

Lies die Unterrichtsnotiz zu Triangles And Polygons (WAEC)

Sets

Triangles And Polygons

Antwort anzeigen

Frage 21 Bericht

Marks	1	2	3	4	5	6	7	8	9	10
No of students	1	3	2	0	1	6	1	0	1	0

The table above shows the scores of 15 students in a Physics test.

How many students scored at least 5?

9 Richtige Antwort

Antwortdetails

Lies die Unterrichtsnotiz zu Algebraic Expressions (WAEC)

Algebraic Expressions

Antwort anzeigen

Frage 22 Bericht

What must be added to the expression x$^2$ - 18x to make it a perfect square?

81 Richtige Antwort

Antwortdetails

To make the expression x$^2$ - 18x a perfect square, we need to add a constant term. The constant term should be half of the coefficient of x squared, which is (18/2)$^2$ = 81. Therefore, we need to add 81 to the expression to make it a perfect square. Adding 81 to the expression gives: x$^2$ - 18x + 81 = (x - 9)$^2$ Thus, the answer is 81.

Lies die Unterrichtsnotiz zu Quadratic Equations (WAEC)

Quadratic Equations

Antwort anzeigen

Frage 23 Bericht

Simplify (³/₄ + ¹/₃) x 4¹/₃ + 3¹/₄

1/2

13/12

10/9

17/12

13/9 Richtige Antwort

Antwortdetails

To simplify this expression, we need to follow the order of operations, which is Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction (PEMDAS). First, we can simplify the expression inside the parentheses: (³/₄ + ¹/₃) x 4¹/₃ + 3¹/₄ = (⁹/₁₂ + ⁴/₁₂) x 4¹/₃ + 3¹/₄ = ¹³/₁₂ x 4¹/₃ + 3¹/₄ Next, we can simplify the exponent 4¹/₃. To do this, we can convert the mixed number to an improper fraction: 4¹/₃ = ^{(4 x 3) + 1}/₃ = ¹³/₃ Now we can substitute the value of 4¹/₃ into the expression: ¹³/₁₂ x 4¹/₃ + 3¹/₄ = ¹³/₁₂ x ¹³/₃ + ¹³/₄ To simplify this, we can first simplify the multiplication of fractions: ¹³/₁₂ x ¹³/₃ = ¹⁶⁹/₃₆ Now we can add the two fractions: ¹⁶⁹/₃₆ + ¹³/₄ = ¹⁶⁹/₃₆ + ³⁹/₃₆ = ²⁰⁸/₃₆ = ^13}{9 Therefore, the simplified expression is ^13}{9, which corresponds to option (E).

Antwort anzeigen

Frage 24 Bericht

Construct a quadratic equation whose roots are $-\frac{1}{2}$ and 2.

3x²-3x+2=0

3x²+3x-2=0

2x²+3x-2=0

2x²-3x+2=0

2x²-3x-2=0 Richtige Antwort

Antwortdetails

Lies die Unterrichtsnotiz zu Quadratic Equations (WAEC)

Quadratic Equations

Antwort anzeigen

Frage 25 Bericht

The data below shows the frequency distribution
of marks scored by a group of students in a class
test.

What is the modal score

4 Richtige Antwort

Antwortdetails

We find the modal score by identifying the score that occurs most frequently in the data. Looking at the frequency distribution, we can see that the score 4 appears most frequently, with a frequency of 5. Therefore, the modal score is 4.

Lies die Unterrichtsnotiz zu Euclidean Geometry (JAMB)

Euclidean Geometry

Antwort anzeigen

Frage 26 Bericht

The data below shows the frequency distribution
of marks scored by a group of students in a class
test.

Find the mean mark.

1.3

3.8 Richtige Antwort

Antwortdetails

Lies die Unterrichtsnotiz zu Integration (JAMB)

Lies die Unterrichtsnotiz zu Statistics (WAEC)

Integration

Statistics

Antwort anzeigen

Frage 27 Bericht

The value of sin 210° is

$-\frac{1}{2}$ Richtige Antwort

$-\frac{\sqrt{3}}{2}$

$\frac{1}{2}$

$\frac{\sqrt{2}}{2}$

$\frac{\sqrt{3}}{2}$

Antwortdetails

Lies die Unterrichtsnotiz zu Sine, Cosine And Tangent Of An Angle (WAEC)

Lies die Unterrichtsnotiz zu Trigonometry (JAMB)

Sine, Cosine And Tangent Of An Angle

Trigonometry

Antwort anzeigen

Frage 28 Bericht

Evaluate $\log_{10} 25 + \log_{10} 32 - \log_{10} 8$

0.2

2 Richtige Antwort

100

409

490

Antwortdetails

We can use the following property of logarithms: - $\log_{a}b + \log_{a}c = \log_{a}(bc)$ - $\log_{a}b - \log_{a}c = \log_{a}\left(\dfrac{b}{c}\right)$ Using this property, we can rewrite the expression as: \begin{align*} \log_{10} 25 + \log_{10} 32 - \log_{10} 8 &= \log_{10}(25\cdot 32) - \log_{10} 8 \\ &= \log_{10}(800) - \log_{10} 8 \\ &= \log_{10}\left(\frac{800}{8}\right) \\ &= \log_{10}(100) \\ &= 2 \end{align*} Therefore, the value of the expression is 2. Thus, the answer is (2).

Lies die Unterrichtsnotiz zu Logarithms (WAEC)

Logarithms

Antwort anzeigen

Frage 29 Bericht

The nth term of a sequence is given by 3.2$^{n-2}$. Write down the first three terms of the sequence.

2/3, 0, 6

3/2, 3, 6, Richtige Antwort

2/3, 3, 8/3

2/3, ³/₄, 6

2/3, 3, 1/3

Antwortdetails

Lies die Unterrichtsnotiz zu Sequence And Series (WAEC)

Sequence And Series

Antwort anzeigen

Frage 30 Bericht

In the diagram above PQT is a tangent to the circle QRS at Q. Angle QTR = 48° and ?QRT = 95°. Find ?QRT

48^o

45^o

37^o Richtige Antwort

32^o

30^o

Antwortdetails

Lies die Unterrichtsnotiz zu Circles (WAEC)

Lies die Unterrichtsnotiz zu Triangles And Polygons (WAEC)

Circles

Triangles And Polygons

Antwort anzeigen

Frage 31 Bericht

Let U = {1, 2, 3, 4}, P = {2, 3} and Q = {2, 4}. What is (P∩Q)'?

(1, 2, 3)

(1, 3, 4) Richtige Antwort

(2, 3)

(1, 3)

(1, 4)

Antwortdetails

In set theory, the symbol ∩ denotes the intersection of two sets, meaning the set of elements that are in both sets. Therefore, P∩Q denotes the set of elements that are in both P and Q, which is {2}. The complement of a set A, denoted by A', is the set of elements that are not in A but are in the universal set U. Therefore, (P∩Q)' denotes the set of elements that are in U but are not in P∩Q, which is {1, 3, 4}. Thus, the correct answer is: (1, 3, 4).

Lies die Unterrichtsnotiz zu Sets (WAEC)

Lies die Unterrichtsnotiz zu Sets (JAMB)

Sets

Antwort anzeigen

Frage 32 Bericht

If x varies over the set of real numbers, which of the following is illustrated in the diagram above?

-2

-3?x<2 Richtige Antwort

-3

-3?x?2

x?2

Antwortdetails

Lies die Unterrichtsnotiz zu Logical Reasoning (WAEC)

Lies die Unterrichtsnotiz zu Variation (JAMB)

Logical Reasoning

Variation

Antwort anzeigen

Frage 33 Bericht

Simplify: $(\frac{16}{81})^{\frac{1}{4}}$

8/27

1/3

4/9

2/3 Richtige Antwort

-4/3

Antwortdetails

To simplify $(\frac{16}{81})^{\frac{1}{4}}$, we need to take the fourth root of $\frac{16}{81}$. The fourth root of a number is the number that, when multiplied by itself four times, gives that number. So, to find the fourth root of $\frac{16}{81}$, we need to find a number that, when multiplied by itself four times, gives $\frac{16}{81}$. We can rewrite $\frac{16}{81}$ as $(\frac{2}{3})^4$, since $2^4=16$ and $3^4=81$. Therefore, $(\frac{16}{81})^{\frac{1}{4}} = ((\frac{2}{3})^4)^{\frac{1}{4}} = \frac{2}{3}$, which is.

Lies die Unterrichtsnotiz zu Fractions, Decimals And Approximations (WAEC)

Lies die Unterrichtsnotiz zu Number Bases (WAEC)

Fractions, Decimals And Approximations

Number Bases

Antwort anzeigen

Frage 34 Bericht

Factorize the expression 2y$^2$ + xy - 3x$^2$

2y (y + x) - 3x²

(2y - x)(2y + x)

(3x - 2y(x - y)

(2y + 3) x (y - x) Richtige Antwort

(x – y)(2y + 3x)

Antwortdetails

Lies die Unterrichtsnotiz zu Polynomials (JAMB)

Lies die Unterrichtsnotiz zu Algebraic Expressions (WAEC)

Polynomials

Algebraic Expressions

Antwort anzeigen

Frage 35 Bericht

Three balls are drawn one after the other with replacement, from a bag containing 5 red, 9white and 4 blue identical balls, What is the probability that they are one red, one white and one blue?

5/102

5/136

5/162 Richtige Antwort

5/204

5/243

Antwortdetails

The probability of drawing one red ball out of 18 balls is 5/18. Similarly, the probability of drawing one white ball is 9/18 (or 1/2) and the probability of drawing one blue ball is 4/18 (or 2/9). Since we are drawing three balls, we can find the probability of getting one red, one white, and one blue by multiplying the probabilities of each event happening together. Since we are drawing with replacement, the probabilities do not change from draw to draw. Thus, the probability of getting one red, one white, and one blue is: (5/18) x (1/2) x (2/9) = 5/162 Therefore, the answer is option C: 5/162.

Lies die Unterrichtsnotiz zu Probability (WAEC)

Lies die Unterrichtsnotiz zu Surds (radicals) (WAEC)

Probability

Surds (radicals)

Antwort anzeigen

Frage 36 Bericht

Solve the equation $\frac{m}{3} + \frac{1}{2} = \frac{3}{4} + \frac{m}{4}$

-3

-2

3 Richtige Antwort

Antwortdetails

First, we simplify both sides of the equation by getting rid of the fractions. To do this, we can multiply both sides by the least common multiple (LCM) of the denominators, which is 12. So we have: \begin{align*} \frac{m}{3} + \frac{1}{2} &= \frac{3}{4} + \frac{m}{4}\\ 4 \cdot \left(\frac{m}{3} + \frac{1}{2}\right) &= 4 \cdot \left(\frac{3}{4} + \frac{m}{4}\right)\\ \frac{4m}{3} + 2 &= \frac{9}{4} + \frac{m}{4} \end{align*} Next, we can simplify further by moving all the terms involving m to one side of the equation, and all the constant terms to the other side: \begin{align*} \frac{4m}{3} - \frac{m}{4} &= \frac{9}{4} - 2\\ \frac{16m}{12} - \frac{3m}{12} &= \frac{9}{4} - \frac{8}{4}\\ \frac{13m}{12} &= \frac{1}{4}\\ 13m &= 3\\ m &= \frac{3}{13} \end{align*} Therefore, the solution to the equation is $m = \frac{3}{13}$. So the correct answer is 3.

Lies die Unterrichtsnotiz zu Solution Of Linear Equations (WAEC)

Lies die Unterrichtsnotiz zu Fractions, Decimals, Approximations And Percentage (JAMB)

Solution Of Linear Equations

Fractions, Decimals, Approximations And Percentage

Antwort anzeigen

Frage 37 Bericht

Town P is on bearing 315^o from town Q while town R is south of town P and west of town Q. lf town R is 60km away from Q, how far is R from P?

30km

42km

45km

60km Richtige Antwort

120km

Antwortdetails

Lies die Unterrichtsnotiz zu Volumes (WAEC)

Lies die Unterrichtsnotiz zu Bearings (WAEC)

Lies die Unterrichtsnotiz zu Algebraic Expressions (WAEC)

Lies die Unterrichtsnotiz zu Angles Of Elevation And Depression (WAEC)

Lies die Unterrichtsnotiz zu Angles And Intercepts On Parallel Lines (WAEC)

Volumes

Bearings

Algebraic Expressions

Angles Of Elevation And Depression

Angles And Intercepts On Parallel Lines

Antwort anzeigen

Frage 38 Bericht

A number is chosen at random from the set (1 ,2,3
....,9, 10). What is the probability that the number
is greater than or equal to 7?

1/10

3/10

2/5 Richtige Antwort

3/5

7/10

Antwortdetails

There are 10 numbers in the set (1, 2, 3, ..., 9, 10). Out of these, the numbers that are greater than or equal to 7 are 7, 8, 9, and 10. So, there are 4 numbers that satisfy the given condition. Therefore, the probability of choosing a number that is greater than or equal to 7 is the number of numbers that satisfy the condition divided by the total number of numbers in the set, which is: 4/10 = 2/5 Hence, the probability that the number chosen at random from the set (1, 2, 3, ..., 9, 10) is greater than or equal to 7 is 2/5.

Lies die Unterrichtsnotiz zu Number Bases (WAEC)

Number Bases

Antwort anzeigen

Frage 39 Bericht

Convert 77 to a number in base two

1001 101 Richtige Antwort

111001

100110

10101

10011

Antwortdetails

Lies die Unterrichtsnotiz zu Number Bases (WAEC)

Number Bases

Antwort anzeigen

Frage 40 Bericht

In the diagram above, O is the center of the circle QOR is a diameter and ?PSR is 37°. Find ?PRQ

37^o

53^o Richtige Antwort

65^o

127^o

147^o

Antwortdetails

Since QOR is a diameter, it divides the circle into two equal halves, which means that ?QOR is a right angle (90°). Thus, we have: ?PQR = 180° - ?QOR (sum of angles in a triangle) ?PQR = 180° - 90° (since ?QOR is a right angle) ?PQR = 90° Now, we have a right triangle PQR with right angle at Q. Since we know that ?PSR is 37°, we can use the fact that the sum of angles in a triangle is 180° to find ?PRQ: ?PQR + ?QPR + ?PRQ = 180° 90° + ?QPR + 37° = 180° ?QPR = 180° - 90° - 37° ?QPR = 53° Therefore, the answer is 53°.

Lies die Unterrichtsnotiz zu Circles (WAEC)

Circles

Antwort anzeigen

Frage 41 Bericht

In the diagram above, O is the center of the circle and ?POR = 126°. Find ?PQR

234^o

117^o Richtige Antwort

72^o

63^o

54^o

Antwortdetails

Antwort anzeigen

Frage 42 Bericht

The angle of a sector of a circle of radius 8cm is 240°. This sector is bent to form a cone. Find the radius of the base of the cone.

16/3cm Richtige Antwort

15/3cm

16/5cm

8/3cm

16/10cm

Antwortdetails

The sector of the circle with an angle of 240° forms a cone. To find the radius of the base of the cone, we need to use the formula relating the arc length of the sector and the circumference of the base of the cone. The arc length of the sector is (240/360) * 2π * 8 = (4/3) * π * 8 = (32/3)π cm. The circumference of the base of the cone is equal to the arc length of the sector, so it is (32/3)π cm. We know that the circumference of a circle is equal to 2πr, where r is the radius of the circle. Therefore, we can write: (32/3)π = 2πr Simplifying the equation, we get: r = (16/3) cm So, the radius of the base of the cone is 16/3 cm. Therefore, the correct option is: 16/3cm

Lies die Unterrichtsnotiz zu Circles (WAEC)

Lies die Unterrichtsnotiz zu Coordinate Geometry (WAEC)

Circles

Coordinate Geometry

Antwort anzeigen

Frage 43 Bericht

In the diagram above, ML//PQ and NP//QR, if ?LMN = 40° and ?MNP = 55°. Find ?QPR

15^o Richtige Antwort

25^o

35^o

40^o

55^o

Antwortdetails

Antwort anzeigen

Frage 44 Bericht

The diagram above shows the shaded segment of a circle of radius 7cm. if the area of the triangle OXY is 12$\frac{1}{4}$cm$^2$, calculate the area of the segment
[Take ? = 22/7]

5/12cm²

7/12cm² Richtige Antwort

11/6cm²

2 1/3cm²

6 1/6cm²

Antwortdetails

Lies die Unterrichtsnotiz zu Circles (WAEC)

Circles

Antwort anzeigen

Frage 45 Bericht

A cliff on the bank of a river is 300 metres
high. if the angle of depression of a point on the
opposite side of the river is 60° find the width of
the river.

100m

75√3m

100√3m Richtige Antwort

200√3m

300m

Antwortdetails

Lies die Unterrichtsnotiz zu Sine, Cosine And Tangent Of An Angle (WAEC)

Lies die Unterrichtsnotiz zu Change Of Subject Of A Formula/Relation (WAEC)

Sine, Cosine And Tangent Of An Angle

Change Of Subject Of A Formula/Relation

Antwort anzeigen

Frage 46 Bericht

The data below shows the number of worker?
employed in the various sections of a construction
company in Lagos.

Carpenters 24 Labourers 27
Plumbers 12 Plasterers 15
Painters 9 Messengers 3
Bricklayers 18

If a worker is retrenched, what is the probability that he is a plumber or plasterer.

1/27

1/9

5/36

1/4 Richtige Antwort

3/4

Antwortdetails

To calculate the probability that a retrenched worker is a plumber or plasterer, we need to first find the total number of workers in the company, and then find the number of workers who are plumbers or plasterers. The total number of workers in the company is: 24 (Carpenters) + 27 (Labourers) + 12 (Plumbers) + 15 (Plasterers) + 9 (Painters) + 3 (Messengers) + 18 (Bricklayers) = 108 The number of workers who are plumbers or plasterers is: 12 (Plumbers) + 15 (Plasterers) = 27 Therefore, the probability that a retrenched worker is a plumber or plasterer is: 27 (number of plumbers and plasterers) / 108 (total number of workers) = 1/4 So the correct answer is option D: 1/4.

Lies die Unterrichtsnotiz zu Probability (WAEC)

Lies die Unterrichtsnotiz zu Sets (JAMB)

Probability

Sets

Antwort anzeigen

Frage 47 Bericht

What is the probability of throwing a number greater than 2 with a single fair die

1/6

1/3

1/2

2/3 Richtige Antwort

5/6

Antwortdetails

The total number of outcomes when rolling a fair die is 6 since there are six sides on the die. The numbers that are greater than 2 are 3, 4, 5, and 6. So, there are four possible outcomes that are greater than 2. The probability of getting a number greater than 2 with a single fair die is the number of favorable outcomes divided by the total number of possible outcomes, which is 4/6 or 2/3. Therefore, the answer is (d) 2/3.

Lies die Unterrichtsnotiz zu Probability (WAEC)

Probability

Antwort anzeigen

Frage 48 Bericht

A bricklayer measured the length of a wall and obtained 4.10m. If the actual length of the wall is 4.25m, find his percentage error.

3 9/17% Richtige Antwort

3 27/41%

15%

35 5/17%

36 24/41%

Antwortdetails

To find the percentage error, we need to find the absolute difference between the measured value and actual value, divide it by the actual value, and then multiply by 100 to get a percentage. Absolute difference = |actual value - measured value| = |4.25 - 4.10| = 0.15 Percentage error = (|actual value - measured value| / actual value) x 100% Percentage error = (0.15 / 4.25) x 100% = 3.529% (rounded to 3 decimal places) Therefore, the percentage error is approximately 3.529%, which corresponds to 3 9/17%.

Lies die Unterrichtsnotiz zu Percentages (WAEC)

Lies die Unterrichtsnotiz zu Fractions, Decimals, Approximations And Percentage (JAMB)

Percentages

Fractions, Decimals, Approximations And Percentage

Antwort anzeigen






Drücken und Halten zum Ziehen
Hier klicken, um zu schließen

WAEC SSCE - General Mathematics - 1992 (Objective)