JAMB UTME - Physics - 1999
Frage 1 Bericht
Antwortdetails
Frage 2 Bericht
Antwortdetails
Frage 3 Bericht
Antwortdetails
Frage 4 Bericht
In the J-tube above, Y and X are on the same horizontal level and 30cm3 of air is trapped above Y when the atmospheric pressure is 75cm Hg, calculate the volume of air trapped above Y when 15cm Hg is now poured into the limb above X
Antwortdetails
Frage 5 Bericht
Antwortdetails
(0.05 x 200) - (0.95 x 0) = (0.05 + 0.95) x V (since collision is inelastic).
Thus V = 10m/s.
K.E = 1/2 (0.05 + 0.95) x 102
K.E = 1/2 (1 x 100) = 50 J
Frage 6 Bericht
Antwortdetails
800(25−0)20×25 = 2.5 x 10 4 watts
Frage 7 Bericht
The diagram above shows a solid figure with base PQ and center of gravity G on a inclined plane. Which of the following statements is correct
Antwortdetails
Frage 8 Bericht
Antwortdetails
Frage 9 Bericht
In the circuit above, the ammeter reads a current of 5.0 A when R = 8? and reads 7.0A when R = 5?. The value of the unknown resistance X is
Antwortdetails
Frage 10 Bericht
The diagram above shows the velocity-time graph of a vehicle. Its acceleration and retardation respectively are
Antwortdetails
∴ acceleration and retardation = 4m/s2; 2m/s2
Frage 11 Bericht
In fleming's right-hand rule, the thumb, the forefinger and the middle finger if held mutually at right angles represent respectively, the
Antwortdetails
Frage 12 Bericht
Antwortdetails
Frage 13 Bericht
The equation of a wave travelling along the positive x-direction is given by;
Y = 0.25 x 10-3 sin (500t - 0.025x).
Determine the angular frequency of the wave motion.
Antwortdetails
Frage 14 Bericht
Antwortdetails
Frage 15 Bericht
Antwortdetails
Frage 17 Bericht
Antwortdetails
Frage 18 Bericht
In the diagram above, if the internal resistance of the cell is zero, the ration of the powers P1 and P2 dissipated by R1 and R2
Antwortdetails
Frage 19 Bericht
In the circuit above, The potential across each capacitor is 100V. The total energy stored in the two capacitors is
Antwortdetails
Frage 20 Bericht
Antwortdetails
R = igrg/(I - ig)
Where R = 0.05Ω
rg = 5Ω
I = 2M
∴ ig = IR/(rg + R)
= (2 x 0.05)/(5 + 0.05)
= 0.10/5.05
= 0.0198A
= 19.8mA
= 20mA
Frage 21 Bericht
Antwortdetails
Strain = e/l0. = (10.05 - 10.00)/10.00 = 0.005
Thus Y = 107/0.005 = 2 . 0 x 109Nm-2
Frage 22 Bericht
Antwortdetails
This energy is converted to heat energy - mcΔt
∴ From the principle of energy conversion,
mcΔt = mgh
m x 450 x Δt = m x 10 x 20
∴ Δt = m x 10 x 20/(m x 450)
= 200/450
= 4/9°C
Frage 23 Bericht
The diagram above shows a magnet X with its south pole moved along a soft - iron bar PQ in the direction shown. After some time, the poles at P and Q respectively are
Antwortdetails
Frage 24 Bericht
Antwortdetails
Frage 25 Bericht
Antwortdetails
Frage 26 Bericht
Antwortdetails
Frage 27 Bericht
The diagram above shows a lift pump with valves at P and Q. During a downward stroke of the piston
Antwortdetails
Frage 28 Bericht
Antwortdetails
Frage 29 Bericht
Antwortdetails
Let P1 = P0 and V1 = V0, then solve accordingly.
Frage 30 Bericht
Antwortdetails
Frage 31 Bericht
Antwortdetails
Frage 32 Bericht
Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss;
Specific heat capacity of copper = 400JKg-1K-1
Latent heat of fusion of ice = 3.3 x 105JKg-1
Antwortdetails
Frage 33 Bericht
Antwortdetails
Frage 34 Bericht
The figure above represents a frictionless pulley system in which a weight W is in equilibrium with a weight of 40N. Find the value of W.
Antwortdetails
Frage 35 Bericht
Antwortdetails
Frage 36 Bericht
Antwortdetails
Frage 37 Bericht
I. A liquid boils when its saturated vapour pressure is equal to the external pressure
II. Dissolved substances in pure water lead to increase in the boiling point.
III. When the external pressure is increased, the boiling point increases.
IV. Dissolved substances in pure water decrease the boiling point.Which combination of the above are peculiarities of the boiling point of a liquid?
Antwortdetails
Frage 38 Bericht
The diagram above represents a transverse electromagnetic wave travelling with speed 3.0 x 108ms-1. What is the frequency of the wave.
Antwortdetails
Where λ = wavelength
From the above, the distance OA = one wavelength; AB = one wave length and BC = one wavelength.
=> OC = 3 wavelength = 3λ
∴3λ = 0.3M
λ = 0.3/3
= 0.1m
∴ f = V/λ = (3.0 x 108) / 0.1
= 3.0 x 109Hz
Frage 39 Bericht
Antwortdetails
Frage 40 Bericht
In the series a.c circuit shown above, the p.d across the inductor is 8Vr.m.s and that across the resistor is 6Vr.m.s. The effective voltage is
Antwortdetails
Frage 41 Bericht
Antwortdetails
Frage 42 Bericht
Antwortdetails
However, the effective internal resistance adds as parallel arrangement given as
1/r = 1/r1 + 1/r2 + 1/r3 + 1/r4
= 1/4 + 1/4 + 1/4 + 1/4
= 1Ω
∴ r = 1Ω
Answer = 1.5V, 1Ω
Frage 43 Bericht
Antwortdetails
= 80−200.02
= 600.02
= 3000Km-1
= 3.0 x 103Km-1
Frage 44 Bericht
Antwortdetails
E = hf = hV/λ (since V = fxλ)
But in terms of mass M, E = ∆MV2
∴ ∆MV2 = hV/λ
∆MV = h/λ
∴ V = h/λ∆M
V = 6.63 x 10-34/(10-27 x 10-8)
V = 6.63 x 10-34/10-35
V = 6.63 x 10-34+35
V = 6.63 x 10
V = 66.3ms-1
Frage 45 Bericht
2311Na + Proton → pqX + alpha particle
What are the values of p and q respectively in the equation above?
Antwortdetails
Represent;
2311Na + 11P → pqX + 42He
Thus from the above equations, p = 20 and q = 10
Frage 46 Bericht
Antwortdetails
Energy before hitting ground is = P.E at the height of 15m.
P.E = mgh = 0.1 x 10 x 15 = 15 J
Frage 47 Bericht
A solid weigh 10 .00 N in air, 6 N when fully immersed in water and 7 . 0 N when fully immersed in a liquid X. Calculate the relative density of the liquid, X.
Antwortdetails
R.D = loss in weight in liquid X loss in weight in water.
R.D = (10 - 7)/(10 - 6) = 3/4
Frage 48 Bericht
Antwortdetails
Frage 49 Bericht
Antwortdetails
Frage 50 Bericht
A 3000W electric cooker is to be used on a 200V mains circuit. Which of the fuses below can be used safely with the cooker?
Antwortdetails
The maximum current drawn by the cooker is given by;
I = P/V
∴ I = 3000/200
I = 15A
Thus the most suitable fuse to be used is a 10A fuse
